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Calcmathlete Group Title

Why is the range of \(y = \sin^{-1}\theta\) in Quadrants I and IV? I thought that the principal values were in Quadrants I and III?

  • one year ago
  • one year ago

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  1. lgbasallote Group Title
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    but the positive and negative reference angles are in Quadrant I and IV yes?

    • one year ago
  2. Calcmathlete Group Title
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    Yes? Not entirely sure if I understand the concept of this.

    • one year ago
  3. lgbasallote Group Title
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    what don't you understand?

    • one year ago
  4. Calcmathlete Group Title
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    Well, I don't quite understand what the range comes from? I understand that the principal values are the values that make \(y = \sin^{-1}\theta\) a function, but I don't quite understand what the change of domain and range is? Since I don't seem to understand the refernece angles you mentioned above for this, could you explain that?

    • one year ago
  5. lgbasallote Group Title
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    now....im not entirely sure what you're asking

    • one year ago
  6. Calcmathlete Group Title
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    Well, going back to the original question, I was confused on why the range would be in Quadrants I and IV. Would I be getting the range of which quadrants it's in based on the principal values? For instance, the principal values are \(-\frac π2 ≤ \theta ≤ - \frac π2\) Would it mean that the range is in quadrants I and IV because if \(\theta\) is within that range, it would lie in Quadrants I and IV?

    • one year ago
  7. Calcmathlete Group Title
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    I mean \(-\frac π2 ≤ \theta ≤ \frac π2\)

    • one year ago
  8. Calcmathlete Group Title
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    |dw:1348274826087:dw|

    • one year ago
  9. Calcmathlete Group Title
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    NEver mind. I have to go. Thanks.

    • one year ago
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