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Just a sec.
supplementary angles add upto 180*.
So, for the first one it's angle 4.
For question 2, it's asking for complimentary angle of angle 3. Complimentary agnles add upto 90* So, it's angle 2.
For question 3. Vertically opposite angles are equal of each other|dw:1348279518333:dw|
Therefore, 2 and 5 are v.o.a.
Rest all are easy too!
solve for x right
what did you get? I want to check if i got it right
What do you get?
so its 30 degrees right
yes were always done thanks for the help your a good teacher
Thank you! :)
So i have to do all of them? lol. How about you give them a try and i check your answers?
how about 1 more 1 last one can you do number 9
Break the problem into parts..
i want a 100percent on this assignment it will bring me to a B
They all are easy, you'll get it.
Suppose the angle be x. And since it's a supp. angle, hence (180 -x) And since it's 3 times of that, 3(180-x) And as it's 20 less out of it.. so: x=3(180-x) - 20 x=540-3x-20 4x=520 x=130*
is this 9
Now let's check: If x is 130, then the supp angle of x is 180-130 = 50. Three times the supplement of x is 3*50 = 150. And 20 less than that is 150-20 = 130.
And yes, it's 9.
thank you i really appreacitae it
is number 5 30 degrees ?
The answer is not given. It's 120*.
is number 6 B
6 is b
and number seven i gotten 6x - 40 = 3x + 5 6x - 3x = 5 + 40 3x = 45 x = 15 deg
number 8 y + 3x = 180 3x = 75 y + 75 = 180 y = 105 deg
3x = 75 x = 75/3 x = 25
can u check my work if i copy the docment