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Oh I think I get the idea of stripping out a term now.
Simply by taking out an \[a_1\] changes where the sum starts? Yes?
\[\sum_{n=1}^\infty a_n=a_1+\sum_{n=2}^{\infty} a_n\]
 one year ago
 one year ago
Oh I think I get the idea of stripping out a term now. Simply by taking out an \[a_1\] changes where the sum starts? Yes? \[\sum_{n=1}^\infty a_n=a_1+\sum_{n=2}^{\infty} a_n\]
 one year ago
 one year ago

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MathSofiyaBest ResponseYou've already chosen the best response.0
so when I have \[\sum_{n=1}^{\infty}a_nnx^n=a_1+\sum_{n=2}^{\infty}a_nnx^n\] but it's not n=0? Why?
 one year ago

MathSofiyaBest ResponseYou've already chosen the best response.0
I'm trying to start at n=0
 one year ago

MathSofiyaBest ResponseYou've already chosen the best response.0
\[\sum_{n=1}^{\infty}a_nnx^n \rightarrow \sum_{n=0}^{\infty}a_nnx^n\]
 one year ago

MathSofiyaBest ResponseYou've already chosen the best response.0
I looked at example 1 a. http://tutorial.math.lamar.edu/Classes/CalcII/Series_Basics.aspx but I'm not trying to do an index shift :C
 one year ago

FreyesBest ResponseYou've already chosen the best response.1
Well do you need to start at 0? because if you want n = 0 you can just make it at the bottom n = 0
 one year ago

MathSofiyaBest ResponseYou've already chosen the best response.0
why is that all I need to do?
 one year ago

FreyesBest ResponseYou've already chosen the best response.1
\[\sum_{n =0}^{\infty}\]
 one year ago

FreyesBest ResponseYou've already chosen the best response.1
because in your equation it would work for not getting an answer anyway
 one year ago

FreyesBest ResponseYou've already chosen the best response.1
because multiplying by 0 just leaves the term out basically, so you can have it as n=0 but you won't get an actual term out.
 one year ago

FreyesBest ResponseYou've already chosen the best response.1
if you are trying to get a term out there have to be different conditions met in your equation otherwise it won't work that way. But it looks fine for getting a term out if it's not n = 0.
 one year ago

MathSofiyaBest ResponseYou've already chosen the best response.0
by that do you mean that \[\sum_{n=1}^{\infty}a_nnx^n=a_1+\sum_{n=0}^{\infty}a_nnx^n\] It leaves the \[a_1\]out?
 one year ago

FreyesBest ResponseYou've already chosen the best response.1
it's right the left part
 one year ago

FreyesBest ResponseYou've already chosen the best response.1
but if you made that n = 0
 one year ago

FreyesBest ResponseYou've already chosen the best response.1
on the left and n= 1 on the right
 one year ago

FreyesBest ResponseYou've already chosen the best response.1
it would be \[\alpha _{0}*0*x^0\]
 one year ago

MathSofiyaBest ResponseYou've already chosen the best response.0
OMG! I think something just clicked!
 one year ago

FreyesBest ResponseYou've already chosen the best response.1
Yeah, you see where im going with it
 one year ago

MathSofiyaBest ResponseYou've already chosen the best response.0
no wait, just a second
 one year ago

FreyesBest ResponseYou've already chosen the best response.1
You can have it start at 0.. but it doesnt change anything if you start at 1 in this case
 one year ago

MathSofiyaBest ResponseYou've already chosen the best response.0
\[\sum_{n=0}^{\infty}a_nnx^n=0\]
 one year ago

FreyesBest ResponseYou've already chosen the best response.1
it's like putting 0 + \[\sum_{n=1}^{\infty} (insert rest here)\]
 one year ago

FreyesBest ResponseYou've already chosen the best response.1
I guess if you want to start at 0, it has to be fixed at 0 and you can't change that value for it so it's usually left out of summations and n starts at 1. There are situations where you can have n start at 0 but in you equation those conditions for having a different term at n = 0 is not met.
 one year ago

MathSofiyaBest ResponseYou've already chosen the best response.0
I'm a very visual learner. Where you said: "on the left and n= 1 on the right" \[\sum_{n=1}^{\infty}a_nnx^n=a_1+\sum_{n=0}^{\infty}a_nnx^n\] ^^^Is wrong I know, but would you mind writing what you mean?
 one year ago

MathSofiyaBest ResponseYou've already chosen the best response.0
I'm honestly trying hard to get this...I think we're almost there...sorry =/
 one year ago

FreyesBest ResponseYou've already chosen the best response.1
\[\sum_{n=0}^{\infty}a _{n}nx ^{n} = 0 + \sum_{n=1}^{\infty}a _{n}nx ^{n}\]
 one year ago

FreyesBest ResponseYou've already chosen the best response.1
using the rule that 0 multiplied by anything is 0
 one year ago

MathSofiyaBest ResponseYou've already chosen the best response.0
Thank you, finally!
 one year ago

FreyesBest ResponseYou've already chosen the best response.1
Lol it's ok, glad i could help
 one year ago
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