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anonymous
 4 years ago
Oh I think I get the idea of stripping out a term now.
Simply by taking out an \[a_1\] changes where the sum starts? Yes?
\[\sum_{n=1}^\infty a_n=a_1+\sum_{n=2}^{\infty} a_n\]
anonymous
 4 years ago
Oh I think I get the idea of stripping out a term now. Simply by taking out an \[a_1\] changes where the sum starts? Yes? \[\sum_{n=1}^\infty a_n=a_1+\sum_{n=2}^{\infty} a_n\]

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so when I have \[\sum_{n=1}^{\infty}a_nnx^n=a_1+\sum_{n=2}^{\infty}a_nnx^n\] but it's not n=0? Why?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'm trying to start at n=0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\sum_{n=1}^{\infty}a_nnx^n \rightarrow \sum_{n=0}^{\infty}a_nnx^n\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I looked at example 1 a. http://tutorial.math.lamar.edu/Classes/CalcII/Series_Basics.aspx but I'm not trying to do an index shift :C

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Well do you need to start at 0? because if you want n = 0 you can just make it at the bottom n = 0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0why is that all I need to do?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\sum_{n =0}^{\infty}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0because in your equation it would work for not getting an answer anyway

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0because multiplying by 0 just leaves the term out basically, so you can have it as n=0 but you won't get an actual term out.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if you are trying to get a term out there have to be different conditions met in your equation otherwise it won't work that way. But it looks fine for getting a term out if it's not n = 0.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0by that do you mean that \[\sum_{n=1}^{\infty}a_nnx^n=a_1+\sum_{n=0}^{\infty}a_nnx^n\] It leaves the \[a_1\]out?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it's right the left part

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but if you made that n = 0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0on the left and n= 1 on the right

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it would be \[\alpha _{0}*0*x^0\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0OMG! I think something just clicked!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yeah, you see where im going with it

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no wait, just a second

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You can have it start at 0.. but it doesnt change anything if you start at 1 in this case

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\sum_{n=0}^{\infty}a_nnx^n=0\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it's like putting 0 + \[\sum_{n=1}^{\infty} (insert rest here)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I guess if you want to start at 0, it has to be fixed at 0 and you can't change that value for it so it's usually left out of summations and n starts at 1. There are situations where you can have n start at 0 but in you equation those conditions for having a different term at n = 0 is not met.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'm a very visual learner. Where you said: "on the left and n= 1 on the right" \[\sum_{n=1}^{\infty}a_nnx^n=a_1+\sum_{n=0}^{\infty}a_nnx^n\] ^^^Is wrong I know, but would you mind writing what you mean?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'm honestly trying hard to get this...I think we're almost there...sorry =/

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\sum_{n=0}^{\infty}a _{n}nx ^{n} = 0 + \sum_{n=1}^{\infty}a _{n}nx ^{n}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0using the rule that 0 multiplied by anything is 0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Lol it's ok, glad i could help
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