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KatherinePierce1864 Group Title

6. If ACB is a right angle, m<1 = 4y, and m<2 = 2y + 18, find m<2. (1 point) 12º 48º 36º 42º

  • 2 years ago
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  1. KatherinePierce1864 Group Title
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    • 2 years ago
  2. lgbasallote Group Title
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    here's a hint.. \[\angle ACB = m\angle 1 + m\angle 2 = 90\] does that help? or do you need more help?

    • 2 years ago
  3. KatherinePierce1864 Group Title
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    More please, if you don't mind.

    • 2 years ago
  4. lgbasallote Group Title
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    what is the value of m<1 according to the problem?

    • 2 years ago
  5. KatherinePierce1864 Group Title
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    4y?

    • 2 years ago
  6. lgbasallote Group Title
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    right. and m<2 is?

    • 2 years ago
  7. KatherinePierce1864 Group Title
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    2y+18

    • 2 years ago
  8. lgbasallote Group Title
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    right. and i said m<1 + m<2 = 90 so 4y + 2y + 18 = 90 solve for y and tell me what you get

    • 2 years ago
  9. KatherinePierce1864 Group Title
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    y=12?

    • 2 years ago
  10. KatherinePierce1864 Group Title
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    So 12 is the answer?

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  11. lgbasallote Group Title
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    nope. that's just y

    • 2 years ago
  12. lgbasallote Group Title
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    m<2 = 2y + 18 so to solve m<2 you have to substitute y into 2y + 18 make sense?

    • 2 years ago
  13. KatherinePierce1864 Group Title
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    Okay so it would be 4(12) +2(12)+18...?

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  14. lgbasallote Group Title
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    no...substitute y into 2y + 18 only

    • 2 years ago
  15. KatherinePierce1864 Group Title
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    so 2(12)+18

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  16. lgbasallote Group Title
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    right

    • 2 years ago
  17. KatherinePierce1864 Group Title
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    which equals 42?

    • 2 years ago
  18. lgbasallote Group Title
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    right

    • 2 years ago
  19. KatherinePierce1864 Group Title
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    so 42 is my answer?

    • 2 years ago
  20. lgbasallote Group Title
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    yes

    • 2 years ago
  21. KatherinePierce1864 Group Title
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    Thank you!! :)

    • 2 years ago
  22. lgbasallote Group Title
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    welcome

    • 2 years ago
  23. KatherinePierce1864 Group Title
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    Oh I have one more question, that goes to the same photo above. 4. What is another name for <1? C DCA ACB CDA I choose CDA as my answer but I'm not sure if that's right.

    • 2 years ago
  24. KatherinePierce1864 Group Title
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    or it might be DCA, I'm not sure.

    • 2 years ago
  25. lgbasallote Group Title
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    |dw:1348283028935:dw| that's how m<1 looks right?

    • 2 years ago
  26. KatherinePierce1864 Group Title
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    Yes

    • 2 years ago
  27. lgbasallote Group Title
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    can you identify the letter of the middle of that angle?

    • 2 years ago
  28. KatherinePierce1864 Group Title
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    C?

    • 2 years ago
  29. lgbasallote Group Title
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    right. C is the middle. and what are the endpoints?

    • 2 years ago
  30. KatherinePierce1864 Group Title
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    A and D

    • 2 years ago
  31. KatherinePierce1864 Group Title
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    So C would be inthe middle, right? so it would be DCA?

    • 2 years ago
  32. lgbasallote Group Title
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    right

    • 2 years ago
  33. KatherinePierce1864 Group Title
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    Thanks!

    • 2 years ago
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