## KatherinePierce1864 3 years ago 6. If ACB is a right angle, m<1 = 4y, and m<2 = 2y + 18, find m<2. (1 point) 12º 48º 36º 42º

1. KatherinePierce1864

2. lgbasallote

here's a hint.. \[\angle ACB = m\angle 1 + m\angle 2 = 90\] does that help? or do you need more help?

3. KatherinePierce1864

More please, if you don't mind.

4. lgbasallote

what is the value of m<1 according to the problem?

5. KatherinePierce1864

4y?

6. lgbasallote

right. and m<2 is?

7. KatherinePierce1864

2y+18

8. lgbasallote

right. and i said m<1 + m<2 = 90 so 4y + 2y + 18 = 90 solve for y and tell me what you get

9. KatherinePierce1864

y=12?

10. KatherinePierce1864

11. lgbasallote

nope. that's just y

12. lgbasallote

m<2 = 2y + 18 so to solve m<2 you have to substitute y into 2y + 18 make sense?

13. KatherinePierce1864

Okay so it would be 4(12) +2(12)+18...?

14. lgbasallote

no...substitute y into 2y + 18 only

15. KatherinePierce1864

so 2(12)+18

16. lgbasallote

right

17. KatherinePierce1864

which equals 42?

18. lgbasallote

right

19. KatherinePierce1864

20. lgbasallote

yes

21. KatherinePierce1864

Thank you!! :)

22. lgbasallote

welcome

23. KatherinePierce1864

Oh I have one more question, that goes to the same photo above. 4. What is another name for <1? C DCA ACB CDA I choose CDA as my answer but I'm not sure if that's right.

24. KatherinePierce1864

or it might be DCA, I'm not sure.

25. lgbasallote

|dw:1348283028935:dw| that's how m<1 looks right?

26. KatherinePierce1864

Yes

27. lgbasallote

can you identify the letter of the middle of that angle?

28. KatherinePierce1864

C?

29. lgbasallote

right. C is the middle. and what are the endpoints?

30. KatherinePierce1864

A and D

31. KatherinePierce1864

So C would be inthe middle, right? so it would be DCA?

32. lgbasallote

right

33. KatherinePierce1864

Thanks!