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anonymous
 3 years ago
6. If ACB is a right angle, m<1 = 4y, and m<2 = 2y + 18, find m<2. (1 point)
12º
48º
36º
42º
anonymous
 3 years ago
6. If ACB is a right angle, m<1 = 4y, and m<2 = 2y + 18, find m<2. (1 point) 12º 48º 36º 42º

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0here's a hint.. \[\angle ACB = m\angle 1 + m\angle 2 = 90\] does that help? or do you need more help?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0More please, if you don't mind.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what is the value of m<1 according to the problem?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0right. and i said m<1 + m<2 = 90 so 4y + 2y + 18 = 90 solve for y and tell me what you get

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0m<2 = 2y + 18 so to solve m<2 you have to substitute y into 2y + 18 make sense?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Okay so it would be 4(12) +2(12)+18...?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no...substitute y into 2y + 18 only

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Oh I have one more question, that goes to the same photo above. 4. What is another name for <1? C DCA ACB CDA I choose CDA as my answer but I'm not sure if that's right.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0or it might be DCA, I'm not sure.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1348283028935:dw that's how m<1 looks right?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0can you identify the letter of the middle of that angle?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0right. C is the middle. and what are the endpoints?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So C would be inthe middle, right? so it would be DCA?
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