Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

remnant

  • 3 years ago

truing to do this differential equation:

  • This Question is Closed
  1. remnant
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\Large y' + 2y = e ^{-x}\]

  2. remnant
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    but i can't get past this\[\Large \frac{ dy }{ dx } + 2y = e ^{-x}\]

  3. akash_809
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    for a lde\[dy/dx+p(x)y=q(x)\] solution is given as \[y=\int\limits_{?}^{?} q. e ^pxdx\]

  4. akash_809
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    sorry its e^pdx got an extra x by mistake

  5. bahrom7893
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    akash just wrote what you need to do: y = Integral(q*e^(p(x)dx) wait is it e^(px) ir e^(-p(x))?

  6. akash_809
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    it is e^p(x).... @remnant did u try using the formula

  7. remnant
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i didnt get the right answer from the formula

  8. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy