## anonymous 4 years ago truing to do this differential equation:

1. anonymous

$\Large y' + 2y = e ^{-x}$

2. anonymous

but i can't get past this$\Large \frac{ dy }{ dx } + 2y = e ^{-x}$

3. anonymous

for a lde$dy/dx+p(x)y=q(x)$ solution is given as $y=\int\limits_{?}^{?} q. e ^pxdx$

4. anonymous

sorry its e^pdx got an extra x by mistake

5. bahrom7893

akash just wrote what you need to do: y = Integral(q*e^(p(x)dx) wait is it e^(px) ir e^(-p(x))?

6. anonymous

it is e^p(x).... @remnant did u try using the formula

7. anonymous

i didnt get the right answer from the formula