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remnant

truing to do this differential equation:

  • one year ago
  • one year ago

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  1. remnant
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    \[\Large y' + 2y = e ^{-x}\]

    • one year ago
  2. remnant
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    but i can't get past this\[\Large \frac{ dy }{ dx } + 2y = e ^{-x}\]

    • one year ago
  3. akash_809
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    for a lde\[dy/dx+p(x)y=q(x)\] solution is given as \[y=\int\limits_{?}^{?} q. e ^pxdx\]

    • one year ago
  4. akash_809
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    sorry its e^pdx got an extra x by mistake

    • one year ago
  5. bahrom7893
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    akash just wrote what you need to do: y = Integral(q*e^(p(x)dx) wait is it e^(px) ir e^(-p(x))?

    • one year ago
  6. akash_809
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    it is e^p(x).... @remnant did u try using the formula

    • one year ago
  7. remnant
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    i didnt get the right answer from the formula

    • one year ago
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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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