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remnantBest ResponseYou've already chosen the best response.0
\[\Large y' + 2y = e ^{x}\]
 one year ago

remnantBest ResponseYou've already chosen the best response.0
but i can't get past this\[\Large \frac{ dy }{ dx } + 2y = e ^{x}\]
 one year ago

akash_809Best ResponseYou've already chosen the best response.1
for a lde\[dy/dx+p(x)y=q(x)\] solution is given as \[y=\int\limits_{?}^{?} q. e ^pxdx\]
 one year ago

akash_809Best ResponseYou've already chosen the best response.1
sorry its e^pdx got an extra x by mistake
 one year ago

bahrom7893Best ResponseYou've already chosen the best response.0
akash just wrote what you need to do: y = Integral(q*e^(p(x)dx) wait is it e^(px) ir e^(p(x))?
 one year ago

akash_809Best ResponseYou've already chosen the best response.1
it is e^p(x).... @remnant did u try using the formula
 one year ago

remnantBest ResponseYou've already chosen the best response.0
i didnt get the right answer from the formula
 one year ago
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