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Need Help In Continuity of a function .

Mathematics
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F(x)= x+2m ,x<-3 3m(x^2)+k ,-3≤x<1 2(x^3)-m ,x>1 ___________________________ (this is da multi-rule) ^^ Where F(x) is continuous at x=-3 ,at x=1 Find m,k
Can't u wait ?!

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Other answers:

NO! BAH DOES NOT WAIT!
So basically plug in x=-3 into x+2m and into 3m(x^2)+k
-3+2m 3m(9)+k
Alright BAH (i wish if i was a mod >.>) Do BAH KNOW THE ANSWER ?
Now equate them because you want them to meet at the same point for the function to be continuous -3+2m=27m+k 2m-27m=k+3 -25m=k+3 k = -(25m+3)
i did that ,and ?
Do the same thing for 3m(x^2)+k 2(x^3)-m, but at x=1
3m+k=2-m
Solve the two equations
And everything will be revealed............................................
well that was my answer but i got a diff. value :/
:\
ty Bahrom :D
k = -(25m+3) 3m+k=2-m 3m-25m-3=2-m -22m+m=2+3 -21m=5 m=-5/21
k = -(125/21 + 3) ... whatever that is

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