## Eyad 3 years ago Need Help In Continuity of a function .

1. bahrom7893

post the question

F(x)= x+2m ,x<-3 3m(x^2)+k ,-3≤x<1 2(x^3)-m ,x>1 ___________________________ (this is da multi-rule) ^^ Where F(x) is continuous at x=-3 ,at x=1 Find m,k

Can't u wait ?!

4. bahrom7893

NO! BAH DOES NOT WAIT!

5. bahrom7893

So basically plug in x=-3 into x+2m and into 3m(x^2)+k

6. bahrom7893

-3+2m 3m(9)+k

Alright BAH (i wish if i was a mod >.>) Do BAH KNOW THE ANSWER ?

8. bahrom7893

Now equate them because you want them to meet at the same point for the function to be continuous -3+2m=27m+k 2m-27m=k+3 -25m=k+3 k = -(25m+3)

i did that ,and ?

10. bahrom7893

Do the same thing for 3m(x^2)+k 2(x^3)-m, but at x=1

11. bahrom7893

3m+k=2-m

12. bahrom7893

Solve the two equations

13. bahrom7893

And everything will be revealed............................................

well that was my answer but i got a diff. value :/

15. bahrom7893

:\

ty Bahrom :D

17. bahrom7893

k = -(25m+3) 3m+k=2-m 3m-25m-3=2-m -22m+m=2+3 -21m=5 m=-5/21

18. bahrom7893

k = -(125/21 + 3) ... whatever that is