Dallasb22
Find the ratio of the area of triangle XBY to the area of triangle ABC for the given measurements, if LINE XY is PARALLEL TO LINE AC



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Dallasb22
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BY = 3, YC = 2

Dallasb22
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@tcarroll010 Some help please?

Freyes
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thats a ratio of 3:5?

Dallasb22
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Lol, is it?

Freyes
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dw:1348331164200:dw

Dallasb22
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Isn't that 5:2?

Freyes
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then the area of the top one is 9 and the bigger triangle is 25

Freyes
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\[\frac{ 3^{2} }{ 5^{2}}\]

Freyes
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9/25

Freyes
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dw:1348331474528:dw

Dallasb22
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I'm sorry i don't understand how you are getting this
Mind running me through the first steps?

Freyes
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dw:1348331540707:dw

Freyes
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dw:1348331623710:dw

Freyes
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then the pictures above show them on top of each other

Dallasb22
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How did you get 10?

Freyes
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The ratio of the sides is equal if there are parallel lines

Freyes
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because they are similar

Freyes
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because you are just extending the sides of the smaller one yes?

Dallasb22
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Oh yes

Freyes
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So the scale used to increase the smaller one is 3:5

Freyes
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so i made one of the sides = 6 and that is an easy ratio to do

Freyes
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i just multipled the ratio by 2

Freyes
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so 6:10

Dallasb22
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Ohhhh. Okay

Freyes
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and since area is basically multiplying the ratio of the sides

Freyes
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3/5 * 3/5

Freyes
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\[\frac{ 3^2 }{ 5^2 }\]

Freyes
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9/25 is the answer

Dallasb22
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9/25?
not 9:25?

Freyes
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same thing

Dallasb22
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Ok cool

Dallasb22
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What if BY = 2, BC = 4?