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bahrom7893

  • 3 years ago

Solution incoming..Need to figure out what I'm doing wrong.

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  1. bahrom7893
    • 3 years ago
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    A driver needs to drive her car across a 180m long canyon. The side of the canyon opposite his starting point is 40m lower than the side that he's starting on. His initial speed is 50 m/s. At what smallest possible angle should a ramp be built so that he makes it across the canyon.

  2. bahrom7893
    • 3 years ago
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    So this is what I did..

  3. bahrom7893
    • 3 years ago
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    \[V_{iy}=V_{i}Sin\theta\] \[V_{ix}=V_{i}Cos\theta\] \[y=-40m\] \[x=180m\] \[V_i=50(m/s)\] \[\theta-?\]

  4. bahrom7893
    • 3 years ago
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    \[y = V_{iy}t+(1/2)at^2=>-40=V_{iy}t-4.9t^2\]

  5. bahrom7893
    • 3 years ago
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    \[V_{iy}=V_iSin\theta=50Sin\theta\] \[-40=50(Sin\theta)t-4.9t^2\] \[x=V_{ix}t+(1/2)at^2=V_{ix}t=>180=50(Cos\theta)t=> t=18/(5Cos\theta)\]

  6. bahrom7893
    • 3 years ago
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    After I plug in the value of t into: \[-40=50(Sin\theta)t-4.9t^2\] differentiate and solve for t, i get a crazy answer. Does anyone know why?

  7. bahrom7893
    • 3 years ago
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    @TuringTest @anemonix

  8. bahrom7893
    • 3 years ago
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    @AccessDenied @satellite73 @amistre64

  9. bahrom7893
    • 3 years ago
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    Gotta run to a store, will be back in about half an hour, would appreciate it if anyone could take a look at this and tell me what's wrong with my solution.

  10. bahrom7893
    • 3 years ago
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    yay Turing's here

  11. TuringTest
    • 3 years ago
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    give me a minute to finish breakfast plz

  12. bahrom7893
    • 3 years ago
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    Ok lol.. i just started eating breakfast too actually hahah

  13. TuringTest
    • 3 years ago
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    first thing I gonna do when my hands are more free is draw it... I always draw it

  14. rajathsbhat
    • 3 years ago
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    >.> i got 8.27 degrees actually.

  15. bahrom7893
    • 3 years ago
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    |dw:1348331215780:dw|

  16. bahrom7893
    • 3 years ago
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    What was the equation that you differentiated? -40=180Tan(theta) - 63.5(Sec(theta))^2 ?

  17. TuringTest
    • 3 years ago
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    I don't think differentiation is required

  18. rajathsbhat
    • 3 years ago
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    just write sec^2(theta) as 1+tan^2(theta).

  19. bahrom7893
    • 3 years ago
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    ohhhhhhh

  20. bahrom7893
    • 3 years ago
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    never am i going to trust wolf ever again..

  21. TuringTest
    • 3 years ago
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    good choice :)

  22. bahrom7893
    • 3 years ago
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    -40 = 180Tan(theta) -63.5(Sec(theta))^2 and just solve for theta right?

  23. rajathsbhat
    • 3 years ago
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    yup.

  24. bahrom7893
    • 3 years ago
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    thanks a lot guys

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