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bahrom7893
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Solution incoming..Need to figure out what I'm doing wrong.
 one year ago
 one year ago
bahrom7893 Group Title
Solution incoming..Need to figure out what I'm doing wrong.
 one year ago
 one year ago

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bahrom7893 Group TitleBest ResponseYou've already chosen the best response.0
A driver needs to drive her car across a 180m long canyon. The side of the canyon opposite his starting point is 40m lower than the side that he's starting on. His initial speed is 50 m/s. At what smallest possible angle should a ramp be built so that he makes it across the canyon.
 one year ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.0
So this is what I did..
 one year ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.0
\[V_{iy}=V_{i}Sin\theta\] \[V_{ix}=V_{i}Cos\theta\] \[y=40m\] \[x=180m\] \[V_i=50(m/s)\] \[\theta?\]
 one year ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.0
\[y = V_{iy}t+(1/2)at^2=>40=V_{iy}t4.9t^2\]
 one year ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.0
\[V_{iy}=V_iSin\theta=50Sin\theta\] \[40=50(Sin\theta)t4.9t^2\] \[x=V_{ix}t+(1/2)at^2=V_{ix}t=>180=50(Cos\theta)t=> t=18/(5Cos\theta)\]
 one year ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.0
After I plug in the value of t into: \[40=50(Sin\theta)t4.9t^2\] differentiate and solve for t, i get a crazy answer. Does anyone know why?
 one year ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.0
@TuringTest @anemonix
 one year ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.0
@AccessDenied @satellite73 @amistre64
 one year ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.0
Gotta run to a store, will be back in about half an hour, would appreciate it if anyone could take a look at this and tell me what's wrong with my solution.
 one year ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.0
yay Turing's here
 one year ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
give me a minute to finish breakfast plz
 one year ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.0
Ok lol.. i just started eating breakfast too actually hahah
 one year ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
first thing I gonna do when my hands are more free is draw it... I always draw it
 one year ago

rajathsbhat Group TitleBest ResponseYou've already chosen the best response.3
>.> i got 8.27 degrees actually.
 one year ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.0
dw:1348331215780:dw
 one year ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.0
What was the equation that you differentiated? 40=180Tan(theta)  63.5(Sec(theta))^2 ?
 one year ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
I don't think differentiation is required
 one year ago

rajathsbhat Group TitleBest ResponseYou've already chosen the best response.3
just write sec^2(theta) as 1+tan^2(theta).
 one year ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.0
ohhhhhhh
 one year ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.0
never am i going to trust wolf ever again..
 one year ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
good choice :)
 one year ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.0
40 = 180Tan(theta) 63.5(Sec(theta))^2 and just solve for theta right?
 one year ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.0
thanks a lot guys
 one year ago
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