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bahrom7893Best ResponseYou've already chosen the best response.0
A driver needs to drive her car across a 180m long canyon. The side of the canyon opposite his starting point is 40m lower than the side that he's starting on. His initial speed is 50 m/s. At what smallest possible angle should a ramp be built so that he makes it across the canyon.
 one year ago

bahrom7893Best ResponseYou've already chosen the best response.0
So this is what I did..
 one year ago

bahrom7893Best ResponseYou've already chosen the best response.0
\[V_{iy}=V_{i}Sin\theta\] \[V_{ix}=V_{i}Cos\theta\] \[y=40m\] \[x=180m\] \[V_i=50(m/s)\] \[\theta?\]
 one year ago

bahrom7893Best ResponseYou've already chosen the best response.0
\[y = V_{iy}t+(1/2)at^2=>40=V_{iy}t4.9t^2\]
 one year ago

bahrom7893Best ResponseYou've already chosen the best response.0
\[V_{iy}=V_iSin\theta=50Sin\theta\] \[40=50(Sin\theta)t4.9t^2\] \[x=V_{ix}t+(1/2)at^2=V_{ix}t=>180=50(Cos\theta)t=> t=18/(5Cos\theta)\]
 one year ago

bahrom7893Best ResponseYou've already chosen the best response.0
After I plug in the value of t into: \[40=50(Sin\theta)t4.9t^2\] differentiate and solve for t, i get a crazy answer. Does anyone know why?
 one year ago

bahrom7893Best ResponseYou've already chosen the best response.0
@TuringTest @anemonix
 one year ago

bahrom7893Best ResponseYou've already chosen the best response.0
@AccessDenied @satellite73 @amistre64
 one year ago

bahrom7893Best ResponseYou've already chosen the best response.0
Gotta run to a store, will be back in about half an hour, would appreciate it if anyone could take a look at this and tell me what's wrong with my solution.
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
give me a minute to finish breakfast plz
 one year ago

bahrom7893Best ResponseYou've already chosen the best response.0
Ok lol.. i just started eating breakfast too actually hahah
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
first thing I gonna do when my hands are more free is draw it... I always draw it
 one year ago

rajathsbhatBest ResponseYou've already chosen the best response.3
>.> i got 8.27 degrees actually.
 one year ago

bahrom7893Best ResponseYou've already chosen the best response.0
dw:1348331215780:dw
 one year ago

bahrom7893Best ResponseYou've already chosen the best response.0
What was the equation that you differentiated? 40=180Tan(theta)  63.5(Sec(theta))^2 ?
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
I don't think differentiation is required
 one year ago

rajathsbhatBest ResponseYou've already chosen the best response.3
just write sec^2(theta) as 1+tan^2(theta).
 one year ago

bahrom7893Best ResponseYou've already chosen the best response.0
never am i going to trust wolf ever again..
 one year ago

bahrom7893Best ResponseYou've already chosen the best response.0
40 = 180Tan(theta) 63.5(Sec(theta))^2 and just solve for theta right?
 one year ago
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