bahrom7893
  • bahrom7893
Solution incoming..Need to figure out what I'm doing wrong.
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
bahrom7893
  • bahrom7893
A driver needs to drive her car across a 180m long canyon. The side of the canyon opposite his starting point is 40m lower than the side that he's starting on. His initial speed is 50 m/s. At what smallest possible angle should a ramp be built so that he makes it across the canyon.
bahrom7893
  • bahrom7893
So this is what I did..
bahrom7893
  • bahrom7893
\[V_{iy}=V_{i}Sin\theta\] \[V_{ix}=V_{i}Cos\theta\] \[y=-40m\] \[x=180m\] \[V_i=50(m/s)\] \[\theta-?\]

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More answers

bahrom7893
  • bahrom7893
\[y = V_{iy}t+(1/2)at^2=>-40=V_{iy}t-4.9t^2\]
bahrom7893
  • bahrom7893
\[V_{iy}=V_iSin\theta=50Sin\theta\] \[-40=50(Sin\theta)t-4.9t^2\] \[x=V_{ix}t+(1/2)at^2=V_{ix}t=>180=50(Cos\theta)t=> t=18/(5Cos\theta)\]
bahrom7893
  • bahrom7893
After I plug in the value of t into: \[-40=50(Sin\theta)t-4.9t^2\] differentiate and solve for t, i get a crazy answer. Does anyone know why?
bahrom7893
  • bahrom7893
@TuringTest @anemonix
bahrom7893
  • bahrom7893
@AccessDenied @satellite73 @amistre64
bahrom7893
  • bahrom7893
Gotta run to a store, will be back in about half an hour, would appreciate it if anyone could take a look at this and tell me what's wrong with my solution.
bahrom7893
  • bahrom7893
yay Turing's here
TuringTest
  • TuringTest
give me a minute to finish breakfast plz
bahrom7893
  • bahrom7893
Ok lol.. i just started eating breakfast too actually hahah
TuringTest
  • TuringTest
first thing I gonna do when my hands are more free is draw it... I always draw it
anonymous
  • anonymous
>.> i got 8.27 degrees actually.
bahrom7893
  • bahrom7893
|dw:1348331215780:dw|
bahrom7893
  • bahrom7893
What was the equation that you differentiated? -40=180Tan(theta) - 63.5(Sec(theta))^2 ?
TuringTest
  • TuringTest
I don't think differentiation is required
anonymous
  • anonymous
just write sec^2(theta) as 1+tan^2(theta).
bahrom7893
  • bahrom7893
ohhhhhhh
bahrom7893
  • bahrom7893
never am i going to trust wolf ever again..
TuringTest
  • TuringTest
good choice :)
bahrom7893
  • bahrom7893
-40 = 180Tan(theta) -63.5(Sec(theta))^2 and just solve for theta right?
anonymous
  • anonymous
yup.
bahrom7893
  • bahrom7893
thanks a lot guys

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