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bahrom7893
 3 years ago
Solution incoming..Need to figure out what I'm doing wrong.
bahrom7893
 3 years ago
Solution incoming..Need to figure out what I'm doing wrong.

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bahrom7893
 3 years ago
Best ResponseYou've already chosen the best response.0A driver needs to drive her car across a 180m long canyon. The side of the canyon opposite his starting point is 40m lower than the side that he's starting on. His initial speed is 50 m/s. At what smallest possible angle should a ramp be built so that he makes it across the canyon.

bahrom7893
 3 years ago
Best ResponseYou've already chosen the best response.0So this is what I did..

bahrom7893
 3 years ago
Best ResponseYou've already chosen the best response.0\[V_{iy}=V_{i}Sin\theta\] \[V_{ix}=V_{i}Cos\theta\] \[y=40m\] \[x=180m\] \[V_i=50(m/s)\] \[\theta?\]

bahrom7893
 3 years ago
Best ResponseYou've already chosen the best response.0\[y = V_{iy}t+(1/2)at^2=>40=V_{iy}t4.9t^2\]

bahrom7893
 3 years ago
Best ResponseYou've already chosen the best response.0\[V_{iy}=V_iSin\theta=50Sin\theta\] \[40=50(Sin\theta)t4.9t^2\] \[x=V_{ix}t+(1/2)at^2=V_{ix}t=>180=50(Cos\theta)t=> t=18/(5Cos\theta)\]

bahrom7893
 3 years ago
Best ResponseYou've already chosen the best response.0After I plug in the value of t into: \[40=50(Sin\theta)t4.9t^2\] differentiate and solve for t, i get a crazy answer. Does anyone know why?

bahrom7893
 3 years ago
Best ResponseYou've already chosen the best response.0@TuringTest @anemonix

bahrom7893
 3 years ago
Best ResponseYou've already chosen the best response.0@AccessDenied @satellite73 @amistre64

bahrom7893
 3 years ago
Best ResponseYou've already chosen the best response.0Gotta run to a store, will be back in about half an hour, would appreciate it if anyone could take a look at this and tell me what's wrong with my solution.

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.1give me a minute to finish breakfast plz

bahrom7893
 3 years ago
Best ResponseYou've already chosen the best response.0Ok lol.. i just started eating breakfast too actually hahah

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.1first thing I gonna do when my hands are more free is draw it... I always draw it

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0>.> i got 8.27 degrees actually.

bahrom7893
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1348331215780:dw

bahrom7893
 3 years ago
Best ResponseYou've already chosen the best response.0What was the equation that you differentiated? 40=180Tan(theta)  63.5(Sec(theta))^2 ?

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.1I don't think differentiation is required

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0just write sec^2(theta) as 1+tan^2(theta).

bahrom7893
 3 years ago
Best ResponseYou've already chosen the best response.0never am i going to trust wolf ever again..

bahrom7893
 3 years ago
Best ResponseYou've already chosen the best response.040 = 180Tan(theta) 63.5(Sec(theta))^2 and just solve for theta right?
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