sarihmanlapaz
If ysinx=a and ycosx=b find y in terms of a and b. :)



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akash_809
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\[y^2\sin^2x+y^2\cos^2x=a^2+b^2\]>\[y=\sqrt{a^2+b^2}\]

akash_809
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since \[\sin^2x+\cos^2x=1\]

akash_809
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do u get it

akash_809
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@sarihmanlapaz do u need any further explanation...or u understand this

sarihmanlapaz
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yes i get it! thanks for the help :)