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A machine gun is mounted on the top of tower 100m high.At what angle should the gun be inclined to cover a max range of firing the ground below?Muzzle speed=150m/s,take g=10m/s^2
 one year ago
 one year ago
A machine gun is mounted on the top of tower 100m high.At what angle should the gun be inclined to cover a max range of firing the ground below?Muzzle speed=150m/s,take g=10m/s^2
 one year ago
 one year ago

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siddhantsharanBest ResponseYou've already chosen the best response.2
Okay. This is going to take some time. First we find the time. dw:1347968161543:dw
 one year ago

siddhantsharanBest ResponseYou've already chosen the best response.2
Now, \[100 = (150\sin \theta)t  5t^2\] \[t^2  30\sin \theta t 20=0\] Solving for t, \[t = [30\sin \theta \pm \sqrt{(900\sin^2 \theta) + 80}]/2\]
 one year ago

siddhantsharanBest ResponseYou've already chosen the best response.2
Now , We need to find the expression for range. \[Range = (150\cos \theta)*t\]
 one year ago

siddhantsharanBest ResponseYou've already chosen the best response.2
Substituting t and maximizing your expression will give you the answer.
 one year ago

siddhantsharanBest ResponseYou've already chosen the best response.2
To maximize differenciate R with respect to theta.
 one year ago

siddhantsharanBest ResponseYou've already chosen the best response.2
@Yahoo! Calculation is there. But other than that, Do you get it?
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.0
Yup....i understood...ur method.....Does...This...need...Serious....Calculus...Since....i am ..not very much exp with it...
 one year ago

siddhantsharanBest ResponseYou've already chosen the best response.2
No. Not really. You know product rule, right?
 one year ago

siddhantsharanBest ResponseYou've already chosen the best response.2
You should get a value close to 45 degrees. Maybe something like 43 degrees or 44.
 one year ago
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