Can someone check my work?

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Can someone check my work?

Physics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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@rajathsbhat I got a diff answer.. here
I'd appreciate it if someone went over this. This is the original question (I'm solving for part b)
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@anemonix if nobody finds a mistake, you're good to go.
And I'll be back later everyone.
well, in my work, i approximated g to 10m/s^2. So, 7.8 degrees is right, i think.
ohh ok I see.
So we did end up using 18/5cos(theta) for t. Thank you so much for your time bahrom! (And thank you rajathsbhat, too, for checking work =)

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