anonymous
  • anonymous
5(2x-3)=15
Mathematics
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
3
anonymous
  • anonymous
thanks..........
anonymous
  • anonymous
divide by 5, add 3, then divide by 2

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

karatechopper
  • karatechopper
@sam314 Welcome to OpenStudy and @halokitty Same to you:) I would like to address one thing, because you both are new to the site, When answering a question, Always explain. And i see you just did that:) But thanks!
karatechopper
  • karatechopper
If you have any questions on the site, just message me!
anonymous
  • anonymous
how dod you work it out?
anonymous
  • anonymous
did
karatechopper
  • karatechopper
How did I? or how did sam314?
anonymous
  • anonymous
both
karatechopper
  • karatechopper
Well i used Distributive Property. I distributed The 5 to the parenthesis. 5(2x-3)=15 10x-15=15 10x=30 x=3
anonymous
  • anonymous
i got 1.8
anonymous
  • anonymous
its 3

Looking for something else?

Not the answer you are looking for? Search for more explanations.