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baldymcgee6Best ResponseYou've already chosen the best response.0
or if anyones used something called "smart math", i'm very new to both.
 one year ago

helder_edwinBest ResponseYou've already chosen the best response.2
like this? \[ \large f(x)=\begin{cases} x^2+1&\quad\hbox{if ...}\\ 1/x&\quad\hbox{if ......} \end{cases} \]
 one year ago

helder_edwinBest ResponseYou've already chosen the best response.2
is this what u call picewise function?
 one year ago

helder_edwinBest ResponseYou've already chosen the best response.2
\begin{cases} x^2+1&\quad\hbox{if ...}\\ 1/x&\quad\hbox{if...} \end{cases}
 one year ago

helder_edwinBest ResponseYou've already chosen the best response.2
can u copy the code. i don't know how to make the code appear
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.0
I can't copy the code I don't think. Thanks guys.
 one year ago

KingGeorgeBest ResponseYou've already chosen the best response.0
To copy the code, right click the math, move to "Show Math As" and then click on "TeX Commands" Then copy paste the text that appears in the new window.
 one year ago

helder_edwinBest ResponseYou've already chosen the best response.2
can u download that?
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.0
@helder_edwin yes, got the code from the attachment
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.0
thanks for the tip @KingGeorge, works great!
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.0
@helder_edwin how do you do less than or equal to?
 one year ago

helder_edwinBest ResponseYou've already chosen the best response.2
"\leq" gives you \(\leq\) "\geq" gives you \(\geq\)
 one year ago

helder_edwinBest ResponseYou've already chosen the best response.2
this might be of help
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.0
\large f(x)=\begin{cases} 2x &\quad\hbox{if x < 1}\\ x^3 + x^2 +3 &\quad\hbox{if x \leq 0 }\\x/(x^2+1) &\quad\hbox{if x > 0 } \end{cases}
 one year ago

helder_edwinBest ResponseYou've already chosen the best response.2
u have to write "\hbox{if $x\leq0$}" or \[\verb"\hbox{if \(x\leq0\)}"\]
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.0
thanks so much, worked great
 one year ago
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