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anonymous
 4 years ago
How do I make a piecewise funtion using latex?
anonymous
 4 years ago
How do I make a piecewise funtion using latex?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0or if anyones used something called "smart math", i'm very new to both.

helder_edwin
 4 years ago
Best ResponseYou've already chosen the best response.2like this? \[ \large f(x)=\begin{cases} x^2+1&\quad\hbox{if ...}\\ 1/x&\quad\hbox{if ......} \end{cases} \]

helder_edwin
 4 years ago
Best ResponseYou've already chosen the best response.2is this what u call picewise function?

helder_edwin
 4 years ago
Best ResponseYou've already chosen the best response.2\begin{cases} x^2+1&\quad\hbox{if ...}\\ 1/x&\quad\hbox{if...} \end{cases}

helder_edwin
 4 years ago
Best ResponseYou've already chosen the best response.2can u copy the code. i don't know how to make the code appear

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I can't copy the code I don't think. Thanks guys.

KingGeorge
 4 years ago
Best ResponseYou've already chosen the best response.0To copy the code, right click the math, move to "Show Math As" and then click on "TeX Commands" Then copy paste the text that appears in the new window.

helder_edwin
 4 years ago
Best ResponseYou've already chosen the best response.2can u download that?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@helder_edwin yes, got the code from the attachment

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thanks for the tip @KingGeorge, works great!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@helder_edwin how do you do less than or equal to?

helder_edwin
 4 years ago
Best ResponseYou've already chosen the best response.2"\leq" gives you \(\leq\) "\geq" gives you \(\geq\)

helder_edwin
 4 years ago
Best ResponseYou've already chosen the best response.2this might be of help

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\large f(x)=\begin{cases} 2x &\quad\hbox{if x < 1}\\ x^3 + x^2 +3 &\quad\hbox{if x \leq 0 }\\x/(x^2+1) &\quad\hbox{if x > 0 } \end{cases}

helder_edwin
 4 years ago
Best ResponseYou've already chosen the best response.2u have to write "\hbox{if $x\leq0$}" or \[\verb"\hbox{if \(x\leq0\)}"\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thanks so much, worked great
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