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Dallasb22
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A bicycle wheel with radius 26" rotates through an arc that measures 80°. What is the length of the arc of the tire that touched the ground?
 2 years ago
 2 years ago
Dallasb22 Group Title
A bicycle wheel with radius 26" rotates through an arc that measures 80°. What is the length of the arc of the tire that touched the ground?
 2 years ago
 2 years ago

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Freyes Group TitleBest ResponseYou've already chosen the best response.1
Find the circumference
 2 years ago

Dallasb22 Group TitleBest ResponseYou've already chosen the best response.1
is this the same ?
 2 years ago

Freyes Group TitleBest ResponseYou've already chosen the best response.1
then multiply it by 80/360
 2 years ago

Freyes Group TitleBest ResponseYou've already chosen the best response.1
I told you how to do it now you should be able to do it
 2 years ago

Freyes Group TitleBest ResponseYou've already chosen the best response.1
circumference is : \[\Pi2r = \Pi d\]
 2 years ago

Dallasb22 Group TitleBest ResponseYou've already chosen the best response.1
Yes, i got that
 2 years ago

Freyes Group TitleBest ResponseYou've already chosen the best response.1
yeah but you forgot the pi
 2 years ago

Dallasb22 Group TitleBest ResponseYou've already chosen the best response.1
And i did, 52pi*80/360
 2 years ago

Freyes Group TitleBest ResponseYou've already chosen the best response.1
\[52 \Pi \times \frac{ 80 }{ 360 }\]
 2 years ago

Freyes Group TitleBest ResponseYou've already chosen the best response.1
see you know how to do it, just put the pi back in
 2 years ago

Dallasb22 Group TitleBest ResponseYou've already chosen the best response.1
\[104\pi/9\]
 2 years ago

Dallasb22 Group TitleBest ResponseYou've already chosen the best response.1
The pi times the whole set?
 2 years ago

Freyes Group TitleBest ResponseYou've already chosen the best response.1
thats the answer ^^
 2 years ago

Freyes Group TitleBest ResponseYou've already chosen the best response.1
the 104 pi / 9
 2 years ago

Dallasb22 Group TitleBest ResponseYou've already chosen the best response.1
Okay, thank you AGAIN.
 2 years ago
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