Dallasb22
A bicycle wheel with radius 26" rotates through an arc that measures 80°. What is the length of the arc of the tire that touched the ground?



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Freyes
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Find the circumference

Dallasb22
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is this the same ?

Freyes
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then multiply it by 80/360

Freyes
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I told you how to do it now you should be able to do it

Dallasb22
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104/9?

Dallasb22
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or 11.5

Freyes
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circumference is : \[\Pi2r = \Pi d\]

Freyes
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\[52 \Pi\]

Dallasb22
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Yes, i got that

Freyes
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yeah but you forgot the pi

Dallasb22
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And i did, 52pi*80/360

Dallasb22
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Oh

Freyes
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\[52 \Pi \times \frac{ 80 }{ 360 }\]

Freyes
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see you know how to do it, just put the pi back in

Freyes
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104/9 * pi

Freyes
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that's it

Dallasb22
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\[104\pi/9\]

Dallasb22
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The pi times the whole set?

Freyes
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thats the answer ^^

Freyes
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the 104 pi / 9

Dallasb22
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Okay, thank you AGAIN.