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razor99 Group Title

Factorize

  • 2 years ago
  • 2 years ago

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  1. razor99 Group Title
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    81a^2-100

    • 2 years ago
  2. swissgirl Group Title
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    (9a+10)(9a-10) Its difference of squares

    • 2 years ago
  3. razor99 Group Title
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    yep

    • 2 years ago
  4. razor99 Group Title
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    swissgirl

    • 2 years ago
  5. razor99 Group Title
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    @swissgirl

    • 2 years ago
  6. swissgirl Group Title
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    so you got it?

    • 2 years ago
  7. razor99 Group Title
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    could u tell me the steps

    • 2 years ago
  8. razor99 Group Title
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    i mean could u show it

    • 2 years ago
  9. swissgirl Group Title
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    I realized that we were missing the middle term Usually the equation is in the form \(ax^2+bx+c\) In this case the equation was in this form \(ax^2+c\) it was missing the bx So that means its difference of squares meaning that middle term canceled out

    • 2 years ago
  10. razor99 Group Title
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    oh i get it thanx pippa u are a life saver

    • 2 years ago
  11. swissgirl Group Title
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    I am back should i finish off explaining or did u get it?

    • 2 years ago
  12. razor99 Group Title
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    could u finish it

    • 2 years ago
  13. swissgirl Group Title
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    So anyways it is in the form \(a^2-b^2=(a-b)(a+b)\) \(81x^2-100=(9x-10)(9x+10)\) In this case our a=9x and b=10 So \(a^2=(9x)^2=81x^2 \text{ and } b^2=(10)^2=100\)

    • 2 years ago
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