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razor99

  • 3 years ago

Factorize

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  1. razor99
    • 3 years ago
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    81a^2-100

  2. swissgirl
    • 3 years ago
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    (9a+10)(9a-10) Its difference of squares

  3. razor99
    • 3 years ago
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    yep

  4. razor99
    • 3 years ago
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    swissgirl

  5. razor99
    • 3 years ago
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    @swissgirl

  6. swissgirl
    • 3 years ago
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    so you got it?

  7. razor99
    • 3 years ago
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    could u tell me the steps

  8. razor99
    • 3 years ago
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    i mean could u show it

  9. swissgirl
    • 3 years ago
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    I realized that we were missing the middle term Usually the equation is in the form \(ax^2+bx+c\) In this case the equation was in this form \(ax^2+c\) it was missing the bx So that means its difference of squares meaning that middle term canceled out

  10. razor99
    • 3 years ago
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    oh i get it thanx pippa u are a life saver

  11. swissgirl
    • 3 years ago
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    I am back should i finish off explaining or did u get it?

  12. razor99
    • 3 years ago
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    could u finish it

  13. swissgirl
    • 3 years ago
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    So anyways it is in the form \(a^2-b^2=(a-b)(a+b)\) \(81x^2-100=(9x-10)(9x+10)\) In this case our a=9x and b=10 So \(a^2=(9x)^2=81x^2 \text{ and } b^2=(10)^2=100\)

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