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baldymcgee6

  • 2 years ago

Find the value of this limit:

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  1. sudharsa
    • 2 years ago
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    tell me the question please

  2. baldymcgee6
    • 2 years ago
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    \[\lim_{x \rightarrow 8} \frac{ (x^\frac{ 2 }{ 3 } - 4) }{ (x^\frac{ 1 }{ 3 } - 2) }\]

  3. sudharsa
    • 2 years ago
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    can u attach it with clear pls

  4. baldymcgee6
    • 2 years ago
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    attach it with what? @sudharsa

  5. baldymcgee6
    • 2 years ago
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    http://gyazo.com/9e646627ecf766a91ef117db60d3c64d

  6. across
    • 2 years ago
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    Hint: factor the numerator.

  7. baldymcgee6
    • 2 years ago
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    how do we factor it? what do we take out?

  8. baldymcgee6
    • 2 years ago
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    @across ?

  9. across
    • 2 years ago
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    The numerator has the form \(a^2-b^2=(a+b)(a-b)\).

  10. sudharsa
    • 2 years ago
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    dvide numerator and denominator by x^1/3 yeah

  11. across
    • 2 years ago
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    You don't have to divide, @sudharsa.

  12. sudharsa
    • 2 years ago
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    ok ur also goog idea that mke it simple

  13. sudharsa
    • 2 years ago
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    across is good then answer is simple yeah

  14. baldymcgee6
    • 2 years ago
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    but what is sqrt(x^2/3)

  15. sudharsa
    • 2 years ago
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    if x= 8 then cubic root of it will be 2 then proceed yeah

  16. baldymcgee6
    • 2 years ago
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    @across I don't understand how to factor the numberator..

  17. across
    • 2 years ago
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    If you let \(u=x^{1/3}\), then your numerator will become \(u^2-4\). Can you factor that?

  18. baldymcgee6
    • 2 years ago
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    its x^(2/3), but nonetheless, (u+2)(u-2)

  19. across
    • 2 years ago
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    You have to let \(u=x^{1/3}\) because then \(u^2=x^{2/3}\)... now re-substitute and solve your exercise.

  20. baldymcgee6
    • 2 years ago
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    okay thank you.

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