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sudharsa
 2 years ago
Best ResponseYou've already chosen the best response.0tell me the question please

baldymcgee6
 2 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow 8} \frac{ (x^\frac{ 2 }{ 3 }  4) }{ (x^\frac{ 1 }{ 3 }  2) }\]

sudharsa
 2 years ago
Best ResponseYou've already chosen the best response.0can u attach it with clear pls

baldymcgee6
 2 years ago
Best ResponseYou've already chosen the best response.0attach it with what? @sudharsa

across
 2 years ago
Best ResponseYou've already chosen the best response.1Hint: factor the numerator.

baldymcgee6
 2 years ago
Best ResponseYou've already chosen the best response.0how do we factor it? what do we take out?

across
 2 years ago
Best ResponseYou've already chosen the best response.1The numerator has the form \(a^2b^2=(a+b)(ab)\).

sudharsa
 2 years ago
Best ResponseYou've already chosen the best response.0dvide numerator and denominator by x^1/3 yeah

across
 2 years ago
Best ResponseYou've already chosen the best response.1You don't have to divide, @sudharsa.

sudharsa
 2 years ago
Best ResponseYou've already chosen the best response.0ok ur also goog idea that mke it simple

sudharsa
 2 years ago
Best ResponseYou've already chosen the best response.0across is good then answer is simple yeah

baldymcgee6
 2 years ago
Best ResponseYou've already chosen the best response.0but what is sqrt(x^2/3)

sudharsa
 2 years ago
Best ResponseYou've already chosen the best response.0if x= 8 then cubic root of it will be 2 then proceed yeah

baldymcgee6
 2 years ago
Best ResponseYou've already chosen the best response.0@across I don't understand how to factor the numberator..

across
 2 years ago
Best ResponseYou've already chosen the best response.1If you let \(u=x^{1/3}\), then your numerator will become \(u^24\). Can you factor that?

baldymcgee6
 2 years ago
Best ResponseYou've already chosen the best response.0its x^(2/3), but nonetheless, (u+2)(u2)

across
 2 years ago
Best ResponseYou've already chosen the best response.1You have to let \(u=x^{1/3}\) because then \(u^2=x^{2/3}\)... now resubstitute and solve your exercise.
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