baldymcgee6
  • baldymcgee6
Find the value of this limit:
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
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anonymous
  • anonymous
tell me the question please
baldymcgee6
  • baldymcgee6
\[\lim_{x \rightarrow 8} \frac{ (x^\frac{ 2 }{ 3 } - 4) }{ (x^\frac{ 1 }{ 3 } - 2) }\]
anonymous
  • anonymous
can u attach it with clear pls

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More answers

baldymcgee6
  • baldymcgee6
attach it with what? @sudharsa
baldymcgee6
  • baldymcgee6
http://gyazo.com/9e646627ecf766a91ef117db60d3c64d
across
  • across
Hint: factor the numerator.
baldymcgee6
  • baldymcgee6
how do we factor it? what do we take out?
baldymcgee6
  • baldymcgee6
@across ?
across
  • across
The numerator has the form \(a^2-b^2=(a+b)(a-b)\).
anonymous
  • anonymous
dvide numerator and denominator by x^1/3 yeah
across
  • across
You don't have to divide, @sudharsa.
anonymous
  • anonymous
ok ur also goog idea that mke it simple
anonymous
  • anonymous
across is good then answer is simple yeah
baldymcgee6
  • baldymcgee6
but what is sqrt(x^2/3)
anonymous
  • anonymous
if x= 8 then cubic root of it will be 2 then proceed yeah
baldymcgee6
  • baldymcgee6
@across I don't understand how to factor the numberator..
across
  • across
If you let \(u=x^{1/3}\), then your numerator will become \(u^2-4\). Can you factor that?
baldymcgee6
  • baldymcgee6
its x^(2/3), but nonetheless, (u+2)(u-2)
across
  • across
You have to let \(u=x^{1/3}\) because then \(u^2=x^{2/3}\)... now re-substitute and solve your exercise.
baldymcgee6
  • baldymcgee6
okay thank you.

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