6 and a half days!
1) that's not correct 2) this doesn't have an "LGBARIDDLE" heading so im asking for solution
i think that's right, but let me double check
all possible ways to choose 2 team out of 13
how are you all getting those?
12 days. <-' I guess
no. it's supposed to be 13 gamedays with 6 games each. but i don't know how
wait, so all the teams play 6 games each?
i have no idea. i suppose it means each day has 6 games
13C2 divided by 6
since 6 games per day
but how do you know 6 games per day?
it wasn't given
pay attention: What is the minimum number of days can they all play without any team playing more than one game a day?
6 teams can play 1 game everyday
that's the maximum possible games
it's looking for minimum though
no, its 13 days, with 6 games per day
because a maximum of 6 games can be played per day
12 teams can play 6 games on day 1 repeat for day 2 etc.
i still don't get the logic why that's the solution
maximum games per day=6
im getting 12 days : first team finishes all its games(12) first day, second team finishes all its remaining games(11) second day, ... 12+11+10+9+8+7+6+5+4+3+2+1
minimum days=total games/max games per day
if you divide total by max..won't that make the final answer max?
oops ! bad logic disregard that
no cuz the minimum would be 1 game per day
you are trying to minmize the number of days, by fitting the most games in one day
I don't think you're reading the whole question and given correctly.
is there a different solution?
13C1 gives the same result though...
13 teams..one game per day...so 13C1 would make sense right?
no, there must be a total of 78 games
13 teams must play all the other teams
isn't that what 13C1 means?
with 13 teams, only 12 teams can play in one day
no 13 C 1 means the number of ways you can select 1 team from 13 teams
the question is, what is the minimum day that they can ALL play without any team playing more than 1 team a day
so what are you implying?
12 team playing on 1 day=6 games in total for the day
this was a question in a board exam back in '94 so it's meant to be tricky
in the first day, you are left with one team unable to play
so you need to move on to the second day to give that specific team who didn't play to play.
i really think 13C1 makes sense
in the case of (13C2)/6...why divide by 6? of all the numbers?
6 is the number of games played in 1 day by 12 teams
but what about for the case of 13 teams?
only 12 teams can play per day because they have to be grouped in teams of 2
i don't think that means the other team should be disregarded
its a 1v1 match, 2 teams per game
okay, on the first day team 1 vs 2 3 vs 4 5 vs 6 7 vs 8 9 vs 10 11 vs 12 the 13th team can't play because all the other teams have already played a game
yes i get that. but im asking for the case of 13 teams. is that logic applicable in that case?
you used 13C2 and then divided by 6 (which is for 12 teams)
13C2 represents the total games because you are select teams of 2 out of 13 teams if you organize all the games, 6 games per day, it would take 13 days in total
*groups of two teams out of 13 teams
so what is the answer with the formula being suggested?
ganesh is close
(13C2)/6 I really need to work on explaining things, hopefully openstudy will help me with that
don't worry bro, you got it from the first time. Illustration makes a better explanation sometimes.
@pizzapi Is right. Because there has to be a total of 78 games played for each team to play each other team. It asks for the minimum number of days for these 78 games to be played in (at least that's the interpretation of the question). So to find that you divide 78 by the maximum number of games that can be played on a single day, which is 6. Therefore, 78/6=13. It takes 13 days for all teams to play each other.