UnkleRhaukus
  • UnkleRhaukus
Negation
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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UnkleRhaukus
  • UnkleRhaukus
(a) \[\neg(\pi>3.2)\quad\longrightarrow\quad\pi\leq 3.2\](b) \[\neg (x < 0)\quad\longrightarrow\quad x\geq 0\](c) \[\neg(x^2 > 0)\quad\longrightarrow\quad x=0\] (d) \[\neg(x = 1)\quad\longrightarrow\quad x\neq 1\](e) \[\neg\neg \psi\quad\longrightarrow\quad \psi\]
UnkleRhaukus
  • UnkleRhaukus
any mistakes?
hartnn
  • hartnn
(c) ?

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UnkleRhaukus
  • UnkleRhaukus
sure?
hartnn
  • hartnn
its correct. except for imaginary x
UnkleRhaukus
  • UnkleRhaukus
so this is a more gerneral answer to c)\[\neg(x^2 > 0)\quad\longrightarrow\quad x\in\Im\]?
hartnn
  • hartnn
yup. but if it is mentioned that x is real, then x=0. else x belongs to imaginary.
hartnn
  • hartnn
sorry, x belongs to imaginary or x=0
UnkleRhaukus
  • UnkleRhaukus
\[\longrightarrow \Re(x)=0\]
UnkleRhaukus
  • UnkleRhaukus
im a bit confused, what if x is complex
hartnn
  • hartnn
but, if x is complex then u x^2 can be positive. yes,even i was thinking that. better assume x as real then x=0
UnkleRhaukus
  • UnkleRhaukus
im not sure
UnkleRhaukus
  • UnkleRhaukus
maybe all i can do is this \[\neg(x^2 > 0)\quad\longrightarrow\quad x^2\leq0\]
UnkleRhaukus
  • UnkleRhaukus
@AccessDenied
UnkleRhaukus
  • UnkleRhaukus
what is the best answer for part (c)
anonymous
  • anonymous
Typically when you're talking about statements of logic you work in real numbers for simplicity just to get the ideas of negation and implication and all that stuff down. I would mark (c) as correct. Furthermore, since complex numbers are not ordered, the symbols don't make sense for complex numbers, lending credence to the assumption that the quantities in question are real.
UnkleRhaukus
  • UnkleRhaukus
so i should leave it as i had it at the top of the page then ,
anonymous
  • anonymous
I would say yes.
UnkleRhaukus
  • UnkleRhaukus
thanks

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