A community for students.
Here's the question you clicked on:
 0 viewing
UnkleRhaukus
 3 years ago
Negation
UnkleRhaukus
 3 years ago
Negation

This Question is Closed

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.0(a) \[\neg(\pi>3.2)\quad\longrightarrow\quad\pi\leq 3.2\](b) \[\neg (x < 0)\quad\longrightarrow\quad x\geq 0\](c) \[\neg(x^2 > 0)\quad\longrightarrow\quad x=0\] (d) \[\neg(x = 1)\quad\longrightarrow\quad x\neq 1\](e) \[\neg\neg \psi\quad\longrightarrow\quad \psi\]

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1its correct. except for imaginary x

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.0so this is a more gerneral answer to c)\[\neg(x^2 > 0)\quad\longrightarrow\quad x\in\Im\]?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1yup. but if it is mentioned that x is real, then x=0. else x belongs to imaginary.

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1sorry, x belongs to imaginary or x=0

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.0\[\longrightarrow \Re(x)=0\]

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.0im a bit confused, what if x is complex

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1but, if x is complex then u x^2 can be positive. yes,even i was thinking that. better assume x as real then x=0

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.0maybe all i can do is this \[\neg(x^2 > 0)\quad\longrightarrow\quad x^2\leq0\]

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.0what is the best answer for part (c)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Typically when you're talking about statements of logic you work in real numbers for simplicity just to get the ideas of negation and implication and all that stuff down. I would mark (c) as correct. Furthermore, since complex numbers are not ordered, the symbols don't make sense for complex numbers, lending credence to the assumption that the quantities in question are real.

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.0so i should leave it as i had it at the top of the page then ,
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.