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Armstrong number is a number obtained summing the cubes of each number.....
consider the number to be abc
so took the eqn as
100a + 10b + c = a^3 + b^3 + c^3
how to solve this eqn???
 one year ago
 one year ago
Armstrong number is a number obtained summing the cubes of each number..... consider the number to be abc so took the eqn as 100a + 10b + c = a^3 + b^3 + c^3 how to solve this eqn???
 one year ago
 one year ago

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Jemurray3Best ResponseYou've already chosen the best response.1
There are an infinite number of possible solutions to that equation, but I suspect that's not quite what you're looking for...
 one year ago

chandhuruBest ResponseYou've already chosen the best response.0
I want to find the solution... in what way can i approach it ??
 one year ago

Jemurray3Best ResponseYou've already chosen the best response.1
Having googled "Armstrong Number", a better way to phrase that question is "An Armstrong number is a 3digit number such that the sum of the cubes of each of its constituent digits is equal to the number itself. How can I find an armstrong number?"
 one year ago

Jemurray3Best ResponseYou've already chosen the best response.1
Are you trying to find a general expression for all Armstrong numbers, or are you trying to simply find one Armstrong number?
 one year ago

chandhuruBest ResponseYou've already chosen the best response.0
yaa i know it is a 3 digit number.... i am trying to find the general expression and i want to find the total number of armstrong numbers present.
 one year ago

Jemurray3Best ResponseYou've already chosen the best response.1
I realize that you know the definition. My point was that I did not, so what I said would have been a better way to ask the question in the first place. Incidentally, you are restricting your attention to 3 digit numbers, then? Because the general concept of an Armstrong number can be applied to a number with any number of digits. If you are restricting yourself to 3 digit numbers, I don't think you can express a general relationship between the digits but it would be straightforward to systematically solve for them. There are only a handful.
 one year ago

chandhuruBest ResponseYou've already chosen the best response.0
if i can find the solution for this eqn ... then same procedure can be used to find it 4 or 5 or 6 digit number...
 one year ago

chandhuruBest ResponseYou've already chosen the best response.0
@hartn can u help me ???
 one year ago

Jemurray3Best ResponseYou've already chosen the best response.1
You're asking for THE solution to an equation with MANY solutions. That is the primary problem here.
 one year ago

Jemurray3Best ResponseYou've already chosen the best response.1
or at least SEVERAL.
 one year ago

chandhuruBest ResponseYou've already chosen the best response.0
@Jemurray3 cant we find that several numbers???
 one year ago

Jemurray3Best ResponseYou've already chosen the best response.1
Yes, but I'm saying that you'd probably have to do it algorithmically rather than try to find a general expression for the digits. For instance, rearranging the equation, \[100aa^3 + 10bb^3 + cc^3 = 0\] if a = 1 and b = 1, \[99 + 9 = c^2 c \] which doesn't yield an integer c... but going through this process, you might find that 153 works out just fine.
 one year ago

chandhuruBest ResponseYou've already chosen the best response.0
yaa i found that one... i solve it like dw:1348380805812:dw i dont no to proceed further.. if i go by ur method it will be trial and error method.. so i am trying for some different approach.
 one year ago

Jemurray3Best ResponseYou've already chosen the best response.1
If you code a program you could do it in about ten seconds...
 one year ago

Jemurray3Best ResponseYou've already chosen the best response.1
def Armstrong(): for i in range(1,9): for j in range(0,9): for k in range(0,9): if i*i*i + j*j*j + k*k*k == 100*i + 10*j + k: print(100*i+10*j+k)
 one year ago

Jemurray3Best ResponseYou've already chosen the best response.1
I'm serious. This is a perfect example of when a computer program would be wonderful. The above code took a little over 10 seconds to write and produced the four 3digit Armstrong numbers.
 one year ago
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