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mathslover

  • 2 years ago

What is the ratio of potential energy to total energy o electron?

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  1. mathslover
    • 2 years ago
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    @hartnn

  2. mathslover
    • 2 years ago
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    @akash123 @ganeshie8 @UnkleRhaukus @lgbasallote

  3. UnkleRhaukus
    • 2 years ago
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    total energy as in ; mass energy?

  4. mathslover
    • 2 years ago
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    a) -2 b) 2 c) 1 d) -1 @UnkleRhaukus can't say exactly

  5. UnkleRhaukus
    • 2 years ago
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    well i dont think negative energy makes much sense in this question

  6. mathslover
    • 2 years ago
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    Yes, since total energy and potential energy both are \(-ve\) and their ratio will be positive... (for electron)

  7. UnkleRhaukus
    • 2 years ago
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    how is either negative/?

  8. mathslover
    • 2 years ago
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    well since : 2 potential energy = total energy

  9. mathslover
    • 2 years ago
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    should the answer be 2 : 1 ? Well @UnkleRhaukus In the case of electron, both are negative

  10. UnkleRhaukus
    • 2 years ago
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    really?

  11. mathslover
    • 2 years ago
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    yes...

  12. UnkleRhaukus
    • 2 years ago
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    i dont know what you mean

  13. mathslover
    • 2 years ago
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    total energy = -ve potential energy = - ve and hence : their ratio will be +ve

  14. mathslover
    • 2 years ago
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    @hartnn and @lgbasallote any suggestions/ideas ?

  15. Jemurray3
    • 2 years ago
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    I assume you're basing this on an electron orbiting a nucleus (which you need to say, otherwise this doesn't make any sense), in which case the virial theorem states that on the average, \[2T = -U \] where T is the kinetic energy and U is the potential energy. The total energy is thus \[ E = T + U = -\frac{1}{2}U + U = \frac{1}{2}U \]

  16. mathslover
    • 2 years ago
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    OK very right .. so the answer is 2 ?

  17. Jemurray3
    • 2 years ago
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    The ratio of total energy to potential energy is 1/2, but the ration of potential energy to total energy is 2.

  18. Jemurray3
    • 2 years ago
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    ratio*

  19. mathslover
    • 2 years ago
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    lol I changed the question wrong

  20. mathslover
    • 2 years ago
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    thanks @Jemurray3

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