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eroshea

  • 3 years ago

please answer :)

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  1. eroshea
    • 3 years ago
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    \[if x+y=90, then \frac{ sinx tany }{ siny tanx } is equal \to?\]

  2. hartnn
    • 3 years ago
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    u want answer in terms of x or y ?

  3. eroshea
    • 3 years ago
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    the possible answers are a. tanx b.1/tanx c.-tanx d. -1/tanx

  4. ash2326
    • 3 years ago
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    given \[x+y=90\] \[\frac{\sin x \tan y}{\sin y \tan x}\ \ \ \ \ \ \ =\] write all in terms of y=90-x @eroshea what's sin (90-x)??

  5. eroshea
    • 3 years ago
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    cos x?

  6. ash2326
    • 3 years ago
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    good, so sin y=sin (90-x)=cos x similarly change tan y in terms of x

  7. eroshea
    • 3 years ago
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    i'm confused @.@

  8. ash2326
    • 3 years ago
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    tan y=tan (90-x)=??

  9. eroshea
    • 3 years ago
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    that's cot y = (tan 90-x)

  10. ash2326
    • 3 years ago
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    good so \[\frac{\sin x \tan y}{\sin y \tan x}\ \ \ \ \ \ \ =\frac{\sin x \cot x}{\cos x \tan x}\ \ \ \ \ \ \ = ?\] Can you simplify this now?

  11. eroshea
    • 3 years ago
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    tanx?

  12. eroshea
    • 3 years ago
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    owh.. 1/tanx maybe?

  13. ash2326
    • 3 years ago
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    check again, are you sure?

  14. eroshea
    • 3 years ago
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    what i got was cosx/sinx =cotx or 1/tanx

  15. ash2326
    • 3 years ago
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    you're correct :)

  16. eroshea
    • 3 years ago
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    thanks! :))

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