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mathslover
 4 years ago
The nearest star to our solar system is 4.29 light years away. How much is this distance in terms of parsecs? How much parallax would this star (named Alpha Centauri) show when viewed from two locations of the Earth six months apart in its orbit around the Sun?
mathslover
 4 years ago
The nearest star to our solar system is 4.29 light years away. How much is this distance in terms of parsecs? How much parallax would this star (named Alpha Centauri) show when viewed from two locations of the Earth six months apart in its orbit around the Sun?

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mathslover
 4 years ago
Best ResponseYou've already chosen the best response.1OK so I had done the first part but I am confused with the second one. 1.3333... pascal is the answer for 1st part. @hartnn @Algebraic! @sauravshakya

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.0nopes,seen such question for the first time.

mathslover
 4 years ago
Best ResponseYou've already chosen the best response.1well I can remind you that it is "parallax method"

vishweshshrimali5
 4 years ago
Best ResponseYou've already chosen the best response.0@mukushla may help you...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[4.26ly=(3*10^8)(365.25*24*60*60)m=9.467*10^{15}m\]\[1psc=3.09*10^{16}m\] \[4.26ly=\frac{9.467*10^{15}}{3.09*10^{16}}psc=0.306psc\]

mathslover
 4 years ago
Best ResponseYou've already chosen the best response.1\[\large{4.29 ly = 9.46*10^{15}m * 4.29 = 40.5834*10^{15} = 4 * 10^{16} m }\] \[\large{4.29 ly = \frac{4*10^{16}}{3*10^{16}}=\frac{4}{3}=1.3333...}\]

mathslover
 4 years ago
Best ResponseYou've already chosen the best response.1\(\large{1ly = 9.46*10^{15}m}\)

mathslover
 4 years ago
Best ResponseYou've already chosen the best response.1@henpen You have done a mistake there, you forgot to multiply 4.29 there and you by fault wrote 4.26 ly ..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh yes just multiply the end result by 4.26

mathslover
 4 years ago
Best ResponseYou've already chosen the best response.1so the answer is 1.33... ?

mathslover
 4 years ago
Best ResponseYou've already chosen the best response.1lol sorry forgot that but still m i correct with the solution given above?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes. As to the parallax, the earth sun distance *2 is 3*10^11 m, so just use trigonometry to work out the angle change

mathslover
 4 years ago
Best ResponseYou've already chosen the best response.1I tried that by applying the formula (parallax formula) : d = b / theta but I was unable to complete it... to the correct answer Can you show your work? or just answer you get so that I can check it with the correct answer... (I am not wanting a direct answer but here I want to check it so please provide your answer )

mathslover
 4 years ago
Best ResponseYou've already chosen the best response.1In short : what r u getting after doing that @henpen

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1348407871723:dw Multiply by 2 for the change

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Actually, don't multiply by 2dw:1348408141213:dw. Take the answer away from 90, and multiply THAT answer by 2.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.02*(90arctan(8*10^5 /3)) http://web2.0calc.com/

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0If parallax is measured in degrees, that is.

mathslover
 4 years ago
Best ResponseYou've already chosen the best response.1Yes that is absolutely *correct* @henpen good work
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