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The nearest star to our solar system is 4.29 light years away. How much is this distance in terms of parsecs? How much parallax would this star (named Alpha Centauri) show when viewed from two locations of the Earth six months apart in its orbit around the Sun?
 one year ago
 one year ago
The nearest star to our solar system is 4.29 light years away. How much is this distance in terms of parsecs? How much parallax would this star (named Alpha Centauri) show when viewed from two locations of the Earth six months apart in its orbit around the Sun?
 one year ago
 one year ago

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mathsloverBest ResponseYou've already chosen the best response.1
OK so I had done the first part but I am confused with the second one. 1.3333... pascal is the answer for 1st part. @hartnn @Algebraic! @sauravshakya
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
nopes,seen such question for the first time.
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
well I can remind you that it is "parallax method"
 one year ago

vishweshshrimali5Best ResponseYou've already chosen the best response.0
@mukushla may help you...
 one year ago

henpenBest ResponseYou've already chosen the best response.1
\[4.26ly=(3*10^8)(365.25*24*60*60)m=9.467*10^{15}m\]\[1psc=3.09*10^{16}m\] \[4.26ly=\frac{9.467*10^{15}}{3.09*10^{16}}psc=0.306psc\]
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
\[\large{4.29 ly = 9.46*10^{15}m * 4.29 = 40.5834*10^{15} = 4 * 10^{16} m }\] \[\large{4.29 ly = \frac{4*10^{16}}{3*10^{16}}=\frac{4}{3}=1.3333...}\]
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
\(\large{1ly = 9.46*10^{15}m}\)
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
@henpen You have done a mistake there, you forgot to multiply 4.29 there and you by fault wrote 4.26 ly ..
 one year ago

henpenBest ResponseYou've already chosen the best response.1
Oh yes just multiply the end result by 4.26
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
so the answer is 1.33... ?
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
lol sorry forgot that but still m i correct with the solution given above?
 one year ago

henpenBest ResponseYou've already chosen the best response.1
Yes. As to the parallax, the earth sun distance *2 is 3*10^11 m, so just use trigonometry to work out the angle change
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
I tried that by applying the formula (parallax formula) : d = b / theta but I was unable to complete it... to the correct answer Can you show your work? or just answer you get so that I can check it with the correct answer... (I am not wanting a direct answer but here I want to check it so please provide your answer )
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
In short : what r u getting after doing that @henpen
 one year ago

henpenBest ResponseYou've already chosen the best response.1
dw:1348407871723:dw Multiply by 2 for the change
 one year ago

henpenBest ResponseYou've already chosen the best response.1
Actually, don't multiply by 2dw:1348408141213:dw. Take the answer away from 90, and multiply THAT answer by 2.
 one year ago

henpenBest ResponseYou've already chosen the best response.1
2*(90arctan(8*10^5 /3)) http://web2.0calc.com/
 one year ago

henpenBest ResponseYou've already chosen the best response.1
If parallax is measured in degrees, that is.
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
Yes that is absolutely *correct* @henpen good work
 one year ago
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