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henpen Group TitleBest ResponseYou've already chosen the best response.0
\[x=(tanA+cotA)^2 *(sinA\tan^2A)\]This?
 one year ago

uzumakhi Group TitleBest ResponseYou've already chosen the best response.0
is @henpen right?
 one year ago

henpen Group TitleBest ResponseYou've already chosen the best response.0
\[(tanA+cotA)=(\frac{sinA}{cosA}+\frac{cosA}{sinA})=(\frac{sinAsinA}{cosAsinA}+\frac{cosAcosA}{sinAcosA})=\frac{1}{cosAsinA}\]
 one year ago

henpen Group TitleBest ResponseYou've already chosen the best response.0
\[\because \cos^2(x)+\sin^2(x)=1\]
 one year ago

henpen Group TitleBest ResponseYou've already chosen the best response.0
\[sinA\tan^2A=\frac{sinAcos^2A}{\cos^2A}\frac{\sin^2A}{\cos^2A}=\frac{sinAcos^2A\sin^2A}{\cos^2A}\]
 one year ago

eroshea Group TitleBest ResponseYou've already chosen the best response.0
give me a minute to analyze what you had illustrated
 one year ago

henpen Group TitleBest ResponseYou've already chosen the best response.0
Multiplying,\[(\frac{1}{cosAsinA})^2*(\frac{sinAcos^2A\sin^2A}{\cos^2A})=\frac{sinAcos^2A\sin^2A}{\cos^4Asin^2A}\]
 one year ago

henpen Group TitleBest ResponseYou've already chosen the best response.0
Which you can simplify if you want.
 one year ago

Zekarias Group TitleBest ResponseYou've already chosen the best response.0
you must get this csc(x)sec^2(x)
 one year ago

eroshea Group TitleBest ResponseYou've already chosen the best response.0
owh.. i'm sorry .. you should find the value of x? the possible answers are: a. 4 b.3 c.2 d.1
 one year ago

henpen Group TitleBest ResponseYou've already chosen the best response.0
\[cscAsec^2A\sec^4A\]I must be mistaken.
 one year ago

eroshea Group TitleBest ResponseYou've already chosen the best response.0
how will i arrive at the possible answers?
 one year ago
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