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henpen Group TitleBest ResponseYou've already chosen the best response.0
\[x=(tanA+cotA)^2 *(sinA\tan^2A)\]This?
 2 years ago

uzumakhi Group TitleBest ResponseYou've already chosen the best response.0
is @henpen right?
 2 years ago

henpen Group TitleBest ResponseYou've already chosen the best response.0
\[(tanA+cotA)=(\frac{sinA}{cosA}+\frac{cosA}{sinA})=(\frac{sinAsinA}{cosAsinA}+\frac{cosAcosA}{sinAcosA})=\frac{1}{cosAsinA}\]
 2 years ago

henpen Group TitleBest ResponseYou've already chosen the best response.0
\[\because \cos^2(x)+\sin^2(x)=1\]
 2 years ago

henpen Group TitleBest ResponseYou've already chosen the best response.0
\[sinA\tan^2A=\frac{sinAcos^2A}{\cos^2A}\frac{\sin^2A}{\cos^2A}=\frac{sinAcos^2A\sin^2A}{\cos^2A}\]
 2 years ago

eroshea Group TitleBest ResponseYou've already chosen the best response.0
give me a minute to analyze what you had illustrated
 2 years ago

henpen Group TitleBest ResponseYou've already chosen the best response.0
Multiplying,\[(\frac{1}{cosAsinA})^2*(\frac{sinAcos^2A\sin^2A}{\cos^2A})=\frac{sinAcos^2A\sin^2A}{\cos^4Asin^2A}\]
 2 years ago

henpen Group TitleBest ResponseYou've already chosen the best response.0
Which you can simplify if you want.
 2 years ago

Zekarias Group TitleBest ResponseYou've already chosen the best response.0
you must get this csc(x)sec^2(x)
 2 years ago

eroshea Group TitleBest ResponseYou've already chosen the best response.0
owh.. i'm sorry .. you should find the value of x? the possible answers are: a. 4 b.3 c.2 d.1
 2 years ago

henpen Group TitleBest ResponseYou've already chosen the best response.0
\[cscAsec^2A\sec^4A\]I must be mistaken.
 2 years ago

eroshea Group TitleBest ResponseYou've already chosen the best response.0
how will i arrive at the possible answers?
 2 years ago
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