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anonymous
 4 years ago
x=(tanA+cotA)^2 sinAtan^2A
anonymous
 4 years ago
x=(tanA+cotA)^2 sinAtan^2A

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[x=(tanA+cotA)^2 *(sinA\tan^2A)\]This?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[(tanA+cotA)=(\frac{sinA}{cosA}+\frac{cosA}{sinA})=(\frac{sinAsinA}{cosAsinA}+\frac{cosAcosA}{sinAcosA})=\frac{1}{cosAsinA}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\because \cos^2(x)+\sin^2(x)=1\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[sinA\tan^2A=\frac{sinAcos^2A}{\cos^2A}\frac{\sin^2A}{\cos^2A}=\frac{sinAcos^2A\sin^2A}{\cos^2A}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0give me a minute to analyze what you had illustrated

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Multiplying,\[(\frac{1}{cosAsinA})^2*(\frac{sinAcos^2A\sin^2A}{\cos^2A})=\frac{sinAcos^2A\sin^2A}{\cos^4Asin^2A}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Which you can simplify if you want.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you must get this csc(x)sec^2(x)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0owh.. i'm sorry .. you should find the value of x? the possible answers are: a. 4 b.3 c.2 d.1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[cscAsec^2A\sec^4A\]I must be mistaken.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how will i arrive at the possible answers?
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