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\[\frac{ 4-4\sqrt{3}i }{ -2\sqrt{3}+2i }\]
multiply and divide by -2root3-2i
or take -2i common from numerator. u get -2i(2i-2root 3) in numerator. so what gets cancelled?

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Other answers:

wait.. i'll try
is there something that can be cancelled?
see the factor in numerator and denominator!!
owh.. -2i will remain??and the factor will cancel out the denominator?
yup,-2i,got it ?
but i think its wrong? i thnk this should be what in the numerator is , -2i(2i+2root3),, am i right??
O.o
options?
and yes, u are right....
i dont know what to do next
multiply and divide by -2root3-2i
i hate it when that "i" is in my solution .. :D i'll try solving it
the denominator will be 8? but i have a difficulty in solving the numerator :((
8 ?? or -16 ?
my bad.. i believe the numerator should be 18?? 12-4i^2 = 12-4(-1) = 12+4= 16?
i mean the DENOMINATOR
*minus*
y negative?
\[(-2\sqrt{3}+2i)(-2\sqrt{3}-2i) = (-2\sqrt{3})^{2}-4i ^{2}=12-4(-1)=16\]
my bad, sorry,i took - common from that....ok,so 16 numerator = ?
and what are your options ?
my final answer is -root3 - i
if i simplified my numerator, -16root3 - 16i and divide that by 16 -root3 -i is my answer correct?
hmm....its my silly mistake's day or i m getting i-root3
owh @_@
i'll try solving it again
owh you're right!! hahaha... i had a mistake with my subtraction, 24i-8i should be 16i and not -16i.. thanks ! :))
finally! welcome :)
it's not your silly mistake day :))
glad to know :)
how long have you've been in this site?
48 days around.....
owh.. i just made my account yesterday :3 brb.. i'll just go out and eat first and then back in reviewing :)) i have my finals tomorrow for algebra and trigonometry
best of luck.

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