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eroshea
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\[\frac{ 4-4\sqrt{3}i }{ -2\sqrt{3}+2i }\]
hartnn
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multiply and divide by -2root3-2i
hartnn
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or take -2i common from numerator.
u get -2i(2i-2root 3) in numerator.
so what gets cancelled?
eroshea
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wait.. i'll try
eroshea
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is there something that can be cancelled?
hartnn
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see the factor in numerator and denominator!!
eroshea
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owh.. -2i will remain??and the factor will cancel out the denominator?
hartnn
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yup,-2i,got it ?
eroshea
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but i think its wrong? i thnk this should be what in the numerator is , -2i(2i+2root3),, am i right??
hartnn
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O.o
hartnn
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options?
hartnn
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and yes, u are right....
eroshea
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i dont know what to do next
hartnn
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multiply and divide by -2root3-2i
eroshea
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i hate it when that "i" is in my solution .. :D i'll try solving it
eroshea
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the denominator will be 8? but i have a difficulty in solving the numerator :((
hartnn
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8 ?? or -16 ?
eroshea
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my bad.. i believe the numerator should be 18?? 12-4i^2 = 12-4(-1) = 12+4= 16?
eroshea
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i mean the DENOMINATOR
hartnn
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*minus*
eroshea
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y negative?
eroshea
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\[(-2\sqrt{3}+2i)(-2\sqrt{3}-2i) = (-2\sqrt{3})^{2}-4i ^{2}=12-4(-1)=16\]
hartnn
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my bad, sorry,i took - common from that....ok,so 16
numerator = ?
hartnn
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and what are your options ?
eroshea
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my final answer is -root3 - i
eroshea
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if i simplified my numerator, -16root3 - 16i
and divide that by 16
-root3 -i
is my answer correct?
hartnn
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hmm....its my silly mistake's day or i m getting i-root3
eroshea
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owh @_@
eroshea
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i'll try solving it again
eroshea
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owh you're right!! hahaha... i had a mistake with my subtraction, 24i-8i should be 16i and not -16i.. thanks ! :))
hartnn
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finally!
welcome :)
eroshea
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it's not your silly mistake day :))
hartnn
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glad to know :)
eroshea
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how long have you've been in this site?
hartnn
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48 days around.....
eroshea
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owh.. i just made my account yesterday :3
brb.. i'll just go out and eat first and then back in reviewing :))
i have my finals tomorrow for algebra and trigonometry
hartnn
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best of luck.