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eroshea

  • 3 years ago

rationalize

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  1. eroshea
    • 3 years ago
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    \[\frac{ 4-4\sqrt{3}i }{ -2\sqrt{3}+2i }\]

  2. hartnn
    • 3 years ago
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    multiply and divide by -2root3-2i

  3. hartnn
    • 3 years ago
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    or take -2i common from numerator. u get -2i(2i-2root 3) in numerator. so what gets cancelled?

  4. eroshea
    • 3 years ago
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    wait.. i'll try

  5. eroshea
    • 3 years ago
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    is there something that can be cancelled?

  6. hartnn
    • 3 years ago
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    see the factor in numerator and denominator!!

  7. eroshea
    • 3 years ago
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    owh.. -2i will remain??and the factor will cancel out the denominator?

  8. hartnn
    • 3 years ago
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    yup,-2i,got it ?

  9. eroshea
    • 3 years ago
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    but i think its wrong? i thnk this should be what in the numerator is , -2i(2i+2root3),, am i right??

  10. hartnn
    • 3 years ago
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    O.o

  11. hartnn
    • 3 years ago
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    options?

  12. hartnn
    • 3 years ago
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    and yes, u are right....

  13. eroshea
    • 3 years ago
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    i dont know what to do next

  14. hartnn
    • 3 years ago
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    multiply and divide by -2root3-2i

  15. eroshea
    • 3 years ago
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    i hate it when that "i" is in my solution .. :D i'll try solving it

  16. eroshea
    • 3 years ago
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    the denominator will be 8? but i have a difficulty in solving the numerator :((

  17. hartnn
    • 3 years ago
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    8 ?? or -16 ?

  18. eroshea
    • 3 years ago
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    my bad.. i believe the numerator should be 18?? 12-4i^2 = 12-4(-1) = 12+4= 16?

  19. eroshea
    • 3 years ago
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    i mean the DENOMINATOR

  20. hartnn
    • 3 years ago
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    *minus*

  21. eroshea
    • 3 years ago
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    y negative?

  22. eroshea
    • 3 years ago
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    \[(-2\sqrt{3}+2i)(-2\sqrt{3}-2i) = (-2\sqrt{3})^{2}-4i ^{2}=12-4(-1)=16\]

  23. hartnn
    • 3 years ago
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    my bad, sorry,i took - common from that....ok,so 16 numerator = ?

  24. hartnn
    • 3 years ago
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    and what are your options ?

  25. eroshea
    • 3 years ago
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    my final answer is -root3 - i

  26. eroshea
    • 3 years ago
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    if i simplified my numerator, -16root3 - 16i and divide that by 16 -root3 -i is my answer correct?

  27. hartnn
    • 3 years ago
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    hmm....its my silly mistake's day or i m getting i-root3

  28. eroshea
    • 3 years ago
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    owh @_@

  29. eroshea
    • 3 years ago
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    i'll try solving it again

  30. eroshea
    • 3 years ago
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    owh you're right!! hahaha... i had a mistake with my subtraction, 24i-8i should be 16i and not -16i.. thanks ! :))

  31. hartnn
    • 3 years ago
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    finally! welcome :)

  32. eroshea
    • 3 years ago
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    it's not your silly mistake day :))

  33. hartnn
    • 3 years ago
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    glad to know :)

  34. eroshea
    • 3 years ago
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    how long have you've been in this site?

  35. hartnn
    • 3 years ago
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    48 days around.....

  36. eroshea
    • 3 years ago
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    owh.. i just made my account yesterday :3 brb.. i'll just go out and eat first and then back in reviewing :)) i have my finals tomorrow for algebra and trigonometry

  37. hartnn
    • 3 years ago
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    best of luck.

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