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aceace Group TitleBest ResponseYou've already chosen the best response.0
If \[ T_{n} = \frac{ n1 }{ n }\], prove \[T_{n+1}  T _{n1} = \frac{ 2 }{ n^2 1 }\]
 2 years ago

Mikael Group TitleBest ResponseYou've already chosen the best response.1
This is nice exercise for the hands
 2 years ago

Mikael Group TitleBest ResponseYou've already chosen the best response.1
\[ T_{n+1} = \frac{n}{n+1}\]
 2 years ago

Mikael Group TitleBest ResponseYou've already chosen the best response.1
So \[ T_{n+1}  T_{n1} = \frac{ n }{ n+1 }  \frac{n1}{n} \]
 2 years ago

Mikael Group TitleBest ResponseYou've already chosen the best response.1
Sorry \[ T_{n+1}  T_{n1} = \frac{ n }{ n+1 }  \frac{n2}{n1}\]
 2 years ago

Mikael Group TitleBest ResponseYou've already chosen the best response.1
Just bring to the common denominator by multiplying the denominators and recall that \[ (n+1)(n1) = ...^2  1^2 \]
 2 years ago

aceace Group TitleBest ResponseYou've already chosen the best response.0
it seems like i cant go any further
 2 years ago
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