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aceace
 3 years ago
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aceace
 3 years ago
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aceace
 3 years ago
Best ResponseYou've already chosen the best response.0If \[ T_{n} = \frac{ n1 }{ n }\], prove \[T_{n+1}  T _{n1} = \frac{ 2 }{ n^2 1 }\]

Mikael
 3 years ago
Best ResponseYou've already chosen the best response.1This is nice exercise for the hands

Mikael
 3 years ago
Best ResponseYou've already chosen the best response.1\[ T_{n+1} = \frac{n}{n+1}\]

Mikael
 3 years ago
Best ResponseYou've already chosen the best response.1So \[ T_{n+1}  T_{n1} = \frac{ n }{ n+1 }  \frac{n1}{n} \]

Mikael
 3 years ago
Best ResponseYou've already chosen the best response.1Sorry \[ T_{n+1}  T_{n1} = \frac{ n }{ n+1 }  \frac{n2}{n1}\]

Mikael
 3 years ago
Best ResponseYou've already chosen the best response.1Just bring to the common denominator by multiplying the denominators and recall that \[ (n+1)(n1) = ...^2  1^2 \]

aceace
 3 years ago
Best ResponseYou've already chosen the best response.0it seems like i cant go any further
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