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Yahoo!Best ResponseYou've already chosen the best response.0
14! = 14*13*12*11*10*9*8*7*6*5*4*3*2*1
 one year ago

jaguarhunter007Best ResponseYou've already chosen the best response.0
help needed folks!!
 one year ago

hartnnBest ResponseYou've already chosen the best response.3
maybe wilson theorem might help, check that out.
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
\[\large{\frac{14*13*12*11*10*9*8*7*6*5*4*3*2*1}{17}}\] Remainder theorem will not work here... at least
 one year ago

jaguarhunter007Best ResponseYou've already chosen the best response.0
wilson theorem shud solve dis..plz elaborate
 one year ago

hartnnBest ResponseYou've already chosen the best response.3
(n1)!+1 = 0 mod n (171)!+1 = 0 mod 17 (16)!+1 = 0mod 17 now i m stuck.
 one year ago

jaguarhunter007Best ResponseYou've already chosen the best response.0
wot's mod n =??
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
well my answer is "very very very long"
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
and hopefully wrong .. :P
 one year ago

jaguarhunter007Best ResponseYou've already chosen the best response.0
please post it!!! any help wud be appreciated
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
Remainder can not be > or equal to 17 and hence my answer is wrong @jaguarhunter007 sorry... :(
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
http://www.wolframalpha.com/input/?i=Remainder+when+14%21+%2F+17+
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
Wolfram says that as *8* ..
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
I think hartnn has a method but thats' too complicated for me now..
 one year ago

hartnnBest ResponseYou've already chosen the best response.3
similar problem here: http://math.stackexchange.com/questions/23809/whatistheremainderof16isdividedby19
 one year ago

oldrin.batakuBest ResponseYou've already chosen the best response.2
Just reduce the expression.\[ 16!=16\mod17\\ 240\times14!\mod17=16\mod17\\ 14!=\frac{16}2\mod17\\ \ \ \ \ =8\mod17 \]
 one year ago

jaguarhunter007Best ResponseYou've already chosen the best response.0
oldrin where did the 2 come from?? fine till step 2..where did 240 disappear??
 one year ago

oldrin.batakuBest ResponseYou've already chosen the best response.2
\[240=2+238=2+17\times14\\240\mod17=2\]
 one year ago

jaguarhunter007Best ResponseYou've already chosen the best response.0
wow oldrin thanks!!!
 one year ago

oldrin.batakuBest ResponseYou've already chosen the best response.2
@hartnn was on the right track... \[ 16!+1=0\mod17\\ 16!=(1)\mod17\\ \ \ \ \ \cong16\mod17 \]
 one year ago

jaguarhunter007Best ResponseYou've already chosen the best response.0
@oldrin can u give link to properties of mod...how can we move 1 to the left of equation like dat?
 one year ago

oldrin.batakuBest ResponseYou've already chosen the best response.2
http://www.math.rutgers.edu/~erowland/modulararithmetic.html
 one year ago

jaguarhunter007Best ResponseYou've already chosen the best response.0
oldrin u are the best!
 one year ago
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