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anonymous
 3 years ago
Remainder(14! divided by 17) ??
anonymous
 3 years ago
Remainder(14! divided by 17) ??

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.014! = 14*13*12*11*10*9*8*7*6*5*4*3*2*1

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.3maybe wilson theorem might help, check that out.

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1\[\large{\frac{14*13*12*11*10*9*8*7*6*5*4*3*2*1}{17}}\] Remainder theorem will not work here... at least

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0wilson theorem shud solve dis..plz elaborate

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.3(n1)!+1 = 0 mod n (171)!+1 = 0 mod 17 (16)!+1 = 0mod 17 now i m stuck.

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1well my answer is "very very very long"

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1and hopefully wrong .. :P

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0please post it!!! any help wud be appreciated

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1Remainder can not be > or equal to 17 and hence my answer is wrong @jaguarhunter007 sorry... :(

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1http://www.wolframalpha.com/input/?i=Remainder+when+14%21+%2F+17+

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1Wolfram says that as *8* ..

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1I think hartnn has a method but thats' too complicated for me now..

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.3similar problem here: http://math.stackexchange.com/questions/23809/whatistheremainderof16isdividedby19

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Just reduce the expression.\[ 16!=16\mod17\\ 240\times14!\mod17=16\mod17\\ 14!=\frac{16}2\mod17\\ \ \ \ \ =8\mod17 \]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oldrin where did the 2 come from?? fine till step 2..where did 240 disappear??

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[240=2+238=2+17\times14\\240\mod17=2\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@hartnn was on the right track... \[ 16!+1=0\mod17\\ 16!=(1)\mod17\\ \ \ \ \ \cong16\mod17 \]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@oldrin can u give link to properties of mod...how can we move 1 to the left of equation like dat?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0http://www.math.rutgers.edu/~erowland/modulararithmetic.html

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oldrin u are the best!
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