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\[x^4>x^2\]

\(x^2(x^2-1)>0\) divide it by \(x^2\):
\((x-1)(x+1)>0\)
\(x\in(-\infty;-1)\bigcup(1;\infty)\)

why is it greater than 0

oh subtract the x^2?

yep//....

almost, what about after x^2(x^2-1) is greater than 0

\(x^2\) is always bigger than 0. It equals 0 when \(x=0\). But it doesn't satisfy the inequality.

took x^2 common in both the terms....

yep got that

nops.. while splitting the inequality x has to be >0

will you break it down after the x^2(x^2-1) is greater than 0

yep.... both the split terms are compared to the inequalities...

I understand how it works so I need to find all the solutions for x that satisfy the inequality

thanks now I'll try some on my own. Will you recommend a problem that has the same properties?

thanks

is either 0 or non-zero **

solution is \[x <0, x <1] so (negative infinity, to 0 not including zero)?

for x^3-x^2 is less than 0