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iluvvyyhu

Can someone help me with this question? (One sec I have to draw the triangle) Find cos θ.

  • one year ago
  • one year ago

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  1. iluvvyyhu
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    |dw:1348426873500:dw| sorry i drew the numbers before i realized i could type them lol

    • one year ago
  2. klimenkov
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    What is \(\theta\)?

    • one year ago
  3. klimenkov
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    \(\angle BAC\) ?

    • one year ago
  4. kingforever
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    its ...........thought u was gettin the answerHaHaHa!!!!!

    • one year ago
  5. iluvvyyhu
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    o-o what im sorry im lost

    • one year ago
  6. iluvvyyhu
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    oh wait

    • one year ago
  7. klimenkov
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    |dw:1348427264524:dw|

    • one year ago
  8. iluvvyyhu
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    |dw:1348427257607:dw| does that help a little o-o

    • one year ago
  9. klimenkov
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    Yes, \(\cos\theta=\frac9{\sqrt{5^2+9^2}}\).

    • one year ago
  10. iluvvyyhu
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    :( im still confused

    • one year ago
  11. klimenkov
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    Can't you calculate \(\sqrt{5^2+9^2}\) ?

    • one year ago
  12. iluvvyyhu
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    oh im sorry i couldnt see it, i got sqrt106?

    • one year ago
  13. nphuongsun93
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    why not use SOHCAHTOA |dw:1348427620061:dw|

    • one year ago
  14. nphuongsun93
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    \[\tan \theta = \frac{5}9\]

    • one year ago
  15. iluvvyyhu
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    Ohh okay thankyou this is co much easier(:

    • one year ago
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