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iluvvyyhu

  • 3 years ago

Can someone help me with this question? (One sec I have to draw the triangle) Find cos θ.

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  1. iluvvyyhu
    • 3 years ago
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    |dw:1348426873500:dw| sorry i drew the numbers before i realized i could type them lol

  2. klimenkov
    • 3 years ago
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    What is \(\theta\)?

  3. klimenkov
    • 3 years ago
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    \(\angle BAC\) ?

  4. kingforever
    • 3 years ago
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    its ...........thought u was gettin the answerHaHaHa!!!!!

  5. iluvvyyhu
    • 3 years ago
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    o-o what im sorry im lost

  6. iluvvyyhu
    • 3 years ago
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    oh wait

  7. klimenkov
    • 3 years ago
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    |dw:1348427264524:dw|

  8. iluvvyyhu
    • 3 years ago
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    |dw:1348427257607:dw| does that help a little o-o

  9. klimenkov
    • 3 years ago
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    Yes, \(\cos\theta=\frac9{\sqrt{5^2+9^2}}\).

  10. iluvvyyhu
    • 3 years ago
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    :( im still confused

  11. klimenkov
    • 3 years ago
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    Can't you calculate \(\sqrt{5^2+9^2}\) ?

  12. iluvvyyhu
    • 3 years ago
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    oh im sorry i couldnt see it, i got sqrt106?

  13. nphuongsun93
    • 3 years ago
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    why not use SOHCAHTOA |dw:1348427620061:dw|

  14. nphuongsun93
    • 3 years ago
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    \[\tan \theta = \frac{5}9\]

  15. iluvvyyhu
    • 3 years ago
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    Ohh okay thankyou this is co much easier(:

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