A community for students.
Here's the question you clicked on:
 0 viewing
experimentX
 3 years ago
You have 25 liters of water in bucket A and 25 in bucket B. The difference in temperature difference is 40K between them. Now if you take one liter from A to B and then from B to A (after mixing properly). What would be the temperature difference between A and B.
If you do this activity 5 times what would be the final temperature difference. What would be temperature difference in 10 th time?
experimentX
 3 years ago
You have 25 liters of water in bucket A and 25 in bucket B. The difference in temperature difference is 40K between them. Now if you take one liter from A to B and then from B to A (after mixing properly). What would be the temperature difference between A and B. If you do this activity 5 times what would be the final temperature difference. What would be temperature difference in 10 th time?

This Question is Closed

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.3AFTER FIRST TIME THE DIFFERENCE WILL BE 36.92307692 K

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.3ACTUALLY I THINK I FOUND THE SERIES: t_0=40 t_1=40*(24/26)=40*(12/13) t_2=t_1*(12/13)=40*(12/13)^2 . . . t_n=40*(12/13)^n

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.3So, after five times, t_5=26.807 K AND AFTER 10 times, t_10=17.965 K

Mikael
 3 years ago
Best ResponseYou've already chosen the best response.0I think both @demitris and @sauravshakya are almost excatly there. However neither of you guys has clearly A) stated B) Reasoned in explaining you respective \[ \Large\color{Magenta}{\text{Recursion Equation }} \\ \\ \\ Concentration(n+1) = \\\ =\Large{F}{(Concnetrat._{\,\,hotb}(n)\,\, , Concentrat. _{\,\,coldb}(n) )} \] Of course we mean concentration of heat. now \[ Heat.Concentrat. \,\,\sim\, Temperature \]

Mikael
 3 years ago
Best ResponseYou've already chosen the best response.0We all understand that this is a kind of geometric decrease , yet you have endeavored to SOLVE it exactly.... Did you not ?

Mikael
 3 years ago
Best ResponseYou've already chosen the best response.0@demitris and @sauravshakya

Mikael
 3 years ago
Best ResponseYou've already chosen the best response.0The night was silent in fron of him ... \[ \Huge\color{green} {\underbrace{\ddot{}}} \]

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.3WASNT THE ANSWER GIVEN BY ME CORRECT

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.0not sure if that was correct ... I didn't have answer and don't remember my answer either. I had got the recursion relation. pretty close \[ t_n = {25 \over 26}t_{n1}\]

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.0while demetris had got \[ t_n = {24 \over 25}t_{n1}\] which is pretty close. probably weather you take from hot cold or cold to hot might make difference. Not sure though. If you are interested you can check.

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.3I solved it assuming the water is transferred from cold to hot and back from hot to cold.

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.0try assuming water is transferred from cold to hot and from hot to cold. also use 1 liter.

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.3U MEAN HOT TO COLD NOW?

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.0yep ... if results are symmetric then you must be correct.

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.3YEP GOT THE SAME SERIES.

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.3OK HERE IS MY METHOD. LET THE DIFFERENCE IN TEMPERATURE OF 25 liters of water in bucket A and 25 in bucket B be x KELVIN (ALSO LET A IS HOTTER THAN B).......ALSO LET TEMPERATURE OF BUCKET B BE y KELVIN THEN the temperature of bucket A is (y+x) kelvin NOW, FROM B TO A: WHEN 1 liter of water is transferred from B to A then, THE temperature of bucket B does not change but the temperature of bucket A changes. The temperature of bucket A will be (1*y+25*(y+x))/26 = y+25/26 x Now again 1 litre of water is transferred from bucket B to A.... THIS TIME the temperature of bucket A will remain constant but the temperature of bucket B will change: TEMPERATURE OF BUCKET B = {1*(y+25/26 x) + 24*y}/25 =y+(1/26)x NOW, DIFFERENCE IN TEMPERATURE=y+25/26 x y1/26x = 12/13 x

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.3WHICH CLEARLY SHOWS THAT temperature difference is in geometric series with common ratio 12/13

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.3GOT SAME RESULT WHEN ASSUMED WATER IS TRANSFERRED FROM A to B.

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.0worked out again and ... looks like both of you are right!! Help each other with medals.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.