experimentX
  • experimentX
You have 25 liters of water in bucket A and 25 in bucket B. The difference in temperature difference is 40K between them. Now if you take one liter from A to B and then from B to A (after mixing properly). What would be the temperature difference between A and B. If you do this activity 5 times what would be the final temperature difference. What would be temperature difference in 10 th time?
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
AFTER FIRST TIME THE DIFFERENCE WILL BE 36.92307692 K
anonymous
  • anonymous
ACTUALLY I THINK I FOUND THE SERIES: t_0=40 t_1=40*(24/26)=40*(12/13) t_2=t_1*(12/13)=40*(12/13)^2 . . . t_n=40*(12/13)^n
anonymous
  • anonymous
So, after five times, t_5=26.807 K AND AFTER 10 times, t_10=17.965 K

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
I think both @demitris and @sauravshakya are almost excatly there. However neither of you guys has clearly A) stated B) Reasoned in explaining you respective \[ \Large\color{Magenta}{\text{Recursion Equation }} \\ \\ \\ Concentration(n+1) = \\\ =\Large{F}{(Concnetrat._{\,\,hotb}(n)\,\, , Concentrat. _{\,\,coldb}(n) )} \] Of course we mean concentration of heat. now \[ Heat.Concentrat. \,\,\sim\, Temperature \]
anonymous
  • anonymous
We all understand that this is a kind of geometric decrease , yet you have endeavored to SOLVE it exactly.... Did you not ?
anonymous
  • anonymous
@demitris and @sauravshakya
anonymous
  • anonymous
The night was silent in fron of him ... \[ \Huge\color{green} {\underbrace{\ddot{}}} \]
anonymous
  • anonymous
WASNT THE ANSWER GIVEN BY ME CORRECT
anonymous
  • anonymous
@mikael
experimentX
  • experimentX
not sure if that was correct ... I didn't have answer and don't remember my answer either. I had got the recursion relation. pretty close \[ t_n = {25 \over 26}t_{n-1}\]
experimentX
  • experimentX
while demetris had got \[ t_n = {24 \over 25}t_{n-1}\] which is pretty close. probably weather you take from hot cold or cold to hot might make difference. Not sure though. If you are interested you can check.
anonymous
  • anonymous
I solved it assuming the water is transferred from cold to hot and back from hot to cold.
experimentX
  • experimentX
try assuming water is transferred from cold to hot and from hot to cold. also use 1 liter.
anonymous
  • anonymous
U MEAN HOT TO COLD NOW?
experimentX
  • experimentX
yep ... if results are symmetric then you must be correct.
anonymous
  • anonymous
YEP GOT THE SAME SERIES.
anonymous
  • anonymous
OK HERE IS MY METHOD. LET THE DIFFERENCE IN TEMPERATURE OF 25 liters of water in bucket A and 25 in bucket B be x KELVIN (ALSO LET A IS HOTTER THAN B).......ALSO LET TEMPERATURE OF BUCKET B BE y KELVIN THEN the temperature of bucket A is (y+x) kelvin NOW, FROM B TO A: WHEN 1 liter of water is transferred from B to A then, THE temperature of bucket B does not change but the temperature of bucket A changes. The temperature of bucket A will be (1*y+25*(y+x))/26 = y+25/26 x Now again 1 litre of water is transferred from bucket B to A.... THIS TIME the temperature of bucket A will remain constant but the temperature of bucket B will change: TEMPERATURE OF BUCKET B = {1*(y+25/26 x) + 24*y}/25 =y+(1/26)x NOW, DIFFERENCE IN TEMPERATURE=y+25/26 x -y-1/26x = 12/13 x
anonymous
  • anonymous
WHICH CLEARLY SHOWS THAT temperature difference is in geometric series with common ratio 12/13
anonymous
  • anonymous
GOT SAME RESULT WHEN ASSUMED WATER IS TRANSFERRED FROM A to B.
experimentX
  • experimentX
worked out again and ... looks like both of you are right!! Help each other with medals.

Looking for something else?

Not the answer you are looking for? Search for more explanations.