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Mr.Math Group TitleBest ResponseYou've already chosen the best response.2
Write \[x^3 9x^2 +27x 27=(x^327)+(9x^2+27x)=(x^33^3)9x(x3)=\dots\] Does this help?
 2 years ago

sabika13 Group TitleBest ResponseYou've already chosen the best response.0
let me try: (x^3  3^3)  9x (x3) 1^3 (x3) 9x (x3) (x3) (9x) lol am i right :S?
 2 years ago

Mr.Math Group TitleBest ResponseYou've already chosen the best response.2
Not quite. You first need to know the formula for the difference of two cubes: \[(a^3b^3)=(ab)(a^2+ab+b^2).\] http://www.mathsisfun.com/algebra/polynomialsdifferencetwocubes.html
 2 years ago

Mr.Math Group TitleBest ResponseYou've already chosen the best response.2
Now we will apply this to the problem in our hand. You wanna try?
 2 years ago

sabika13 Group TitleBest ResponseYou've already chosen the best response.0
im so confused.. i havent learned this formula.. All i really needed from this equation was the zeros.. is there a easier way to find zeros than factoring?
 2 years ago

Mr.Math Group TitleBest ResponseYou've already chosen the best response.2
Don't be. It's an easytolearn formula. You can find help in understanding it in the link I gave above. Now back to our problem (and by applying that formula), we can write: \[(x^3  3^3)  9x (x3)=(x3)(x^2+3x+9)9x(x3)\] \[=(x3)(x^2+3x+99x)=(x3)(x^26x+9)\] \[=(x3)(x3)^2=(x3)^3.\]
 2 years ago

Mr.Math Group TitleBest ResponseYou've already chosen the best response.2
Makes sense?
 2 years ago

sabika13 Group TitleBest ResponseYou've already chosen the best response.0
how did you get from: =(x−3)(x^2+3x+9−9x) to =(x−3)(x−3)^2
 2 years ago

sabika13 Group TitleBest ResponseYou've already chosen the best response.0
oh no not that one sorry.
 2 years ago

sabika13 Group TitleBest ResponseYou've already chosen the best response.0
(x^3−3^3)−9x(x−3) to (x3) (x^2+3x+99x)
 2 years ago
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