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Mr.Math Group TitleBest ResponseYou've already chosen the best response.2
Write \[x^3 9x^2 +27x 27=(x^327)+(9x^2+27x)=(x^33^3)9x(x3)=\dots\] Does this help?
 one year ago

sabika13 Group TitleBest ResponseYou've already chosen the best response.0
let me try: (x^3  3^3)  9x (x3) 1^3 (x3) 9x (x3) (x3) (9x) lol am i right :S?
 one year ago

Mr.Math Group TitleBest ResponseYou've already chosen the best response.2
Not quite. You first need to know the formula for the difference of two cubes: \[(a^3b^3)=(ab)(a^2+ab+b^2).\] http://www.mathsisfun.com/algebra/polynomialsdifferencetwocubes.html
 one year ago

Mr.Math Group TitleBest ResponseYou've already chosen the best response.2
Now we will apply this to the problem in our hand. You wanna try?
 one year ago

sabika13 Group TitleBest ResponseYou've already chosen the best response.0
im so confused.. i havent learned this formula.. All i really needed from this equation was the zeros.. is there a easier way to find zeros than factoring?
 one year ago

Mr.Math Group TitleBest ResponseYou've already chosen the best response.2
Don't be. It's an easytolearn formula. You can find help in understanding it in the link I gave above. Now back to our problem (and by applying that formula), we can write: \[(x^3  3^3)  9x (x3)=(x3)(x^2+3x+9)9x(x3)\] \[=(x3)(x^2+3x+99x)=(x3)(x^26x+9)\] \[=(x3)(x3)^2=(x3)^3.\]
 one year ago

Mr.Math Group TitleBest ResponseYou've already chosen the best response.2
Makes sense?
 one year ago

sabika13 Group TitleBest ResponseYou've already chosen the best response.0
how did you get from: =(x−3)(x^2+3x+9−9x) to =(x−3)(x−3)^2
 one year ago

sabika13 Group TitleBest ResponseYou've already chosen the best response.0
oh no not that one sorry.
 one year ago

sabika13 Group TitleBest ResponseYou've already chosen the best response.0
(x^3−3^3)−9x(x−3) to (x3) (x^2+3x+99x)
 one year ago
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