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luisz

  • 3 years ago

If the area of a circle whose diameter is pi, is written as a times pi to the b power, what is the value of ab?

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  1. luisz
    • 3 years ago
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    no more drawings this time

  2. luisz
    • 3 years ago
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    I got pi cubed/4

  3. Algebraic!
    • 3 years ago
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    yep

  4. luisz
    • 3 years ago
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    so how could I rewrite this?

  5. Algebraic!
    • 3 years ago
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    rewrite what?

  6. luisz
    • 3 years ago
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    pi cubed/4

  7. luisz
    • 3 years ago
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    I need to rewrite as a times pi to the b power

  8. micahwood50
    • 3 years ago
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    So, the area is π³/4. Rewrite it as π³/4 = aπ^b. Find the a and b.

  9. Mr.Math
    • 3 years ago
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    You know the area of a circle is \(\pi r^2\), where \(r\) is the radius of the circle. In this case we have \(r=\frac{\pi}{2}\). Thus the area, call it \(A\), is \(A=\pi(\frac{\pi}{2})^2=\frac{1}{4}\pi^3.\) Now if we set this \(A=a\pi^b=\frac{1}{4}\pi^3.\) Then we have \(a=\frac{1}{4}\) and \(b=3\). So \(ab=\frac{3}{4}\).

  10. luisz
    • 3 years ago
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    ok

  11. micahwood50
    • 3 years ago
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    You asked me why a should be 1/4, not 4. It's because 4 is in denominator, so it is 1/4. π³/4 = (1/4)π³

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