Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

I thought you were soo smart, that you would know them by now. LOL jk jk.
Lol. I'm not a calculator. I can get stuck too! :P @OpenstudyUser
Try distributing.

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

\[ \Large 9^{2x} + 2(9^{x+1}) = 40 \] Correction^
Just tell me the next and step after that please.
write 9^(x+1) as 9^x.9 then put y=9^x. solve the quadratic
DANG!!! KILL ME!!!! My teacher told me that. -_- Thanks for recalling @hartnn
Just guessing, can't we do it like this? \[9^{2x} + 2(9^x \times 9) = 40\] Ans so on?
didn't i tell u to do just that?
Yes, but you said me to write 9^x = y Got that. But can't we solve it by another way? Something like: \[9^{2x} + 2(9^x)\times 18=40\]
nopes, i don't think so....no formula for log(a+b) or log (a-b)
I see. THanks man.
Did you missed a +sign in your first step? @micahwood50
@OpenstudyUser kept on distributing. :D
I atleast tried -_-
Just do what hartnn told you to do.
I want to learn your method too! @micahwood50
My "method" is incorrect. I just though lnab = ln (a + b), but it's actually lna + lnb so forgot it.
Oh. No problem. Thanks for trying though. :)
I solved it @hartnn . got: x = 0.315
what roots of quadratic did u get?
2, -20
yup. can't be -20 so 9^x=2 x=0.315 u are correct!
Yep. Thanks.

Not the answer you are looking for?

Search for more explanations.

Ask your own question