saifoo.khan
  • saifoo.khan
Logarithms
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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OpenstudyUser
  • OpenstudyUser
I thought you were soo smart, that you would know them by now. LOL jk jk.
saifoo.khan
  • saifoo.khan
Lol. I'm not a calculator. I can get stuck too! :P @OpenstudyUser
OpenstudyUser
  • OpenstudyUser
Try distributing.

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More answers

saifoo.khan
  • saifoo.khan
\[ \Large 9^{2x} + 2(9^{x+1}) = 40 \] Correction^
saifoo.khan
  • saifoo.khan
Just tell me the next and step after that please.
hartnn
  • hartnn
write 9^(x+1) as 9^x.9 then put y=9^x. solve the quadratic
saifoo.khan
  • saifoo.khan
DANG!!! KILL ME!!!! My teacher told me that. -_- Thanks for recalling @hartnn
saifoo.khan
  • saifoo.khan
Just guessing, can't we do it like this? \[9^{2x} + 2(9^x \times 9) = 40\] Ans so on?
saifoo.khan
  • saifoo.khan
Next? @micahwood50
hartnn
  • hartnn
didn't i tell u to do just that?
saifoo.khan
  • saifoo.khan
Yes, but you said me to write 9^x = y Got that. But can't we solve it by another way? Something like: \[9^{2x} + 2(9^x)\times 18=40\]
hartnn
  • hartnn
nopes, i don't think so....no formula for log(a+b) or log (a-b)
saifoo.khan
  • saifoo.khan
I see. THanks man.
saifoo.khan
  • saifoo.khan
Did you missed a +sign in your first step? @micahwood50
saifoo.khan
  • saifoo.khan
@OpenstudyUser kept on distributing. :D
OpenstudyUser
  • OpenstudyUser
I atleast tried -_-
anonymous
  • anonymous
Just do what hartnn told you to do.
saifoo.khan
  • saifoo.khan
I want to learn your method too! @micahwood50
anonymous
  • anonymous
My "method" is incorrect. I just though lnab = ln (a + b), but it's actually lna + lnb so forgot it.
saifoo.khan
  • saifoo.khan
Oh. No problem. Thanks for trying though. :)
saifoo.khan
  • saifoo.khan
I solved it @hartnn . got: x = 0.315
hartnn
  • hartnn
what roots of quadratic did u get?
saifoo.khan
  • saifoo.khan
2, -20
hartnn
  • hartnn
yup. can't be -20 so 9^x=2 x=0.315 u are correct!
saifoo.khan
  • saifoo.khan
Yep. Thanks.

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