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chicagochica5 Group Title

Solve the equation using square roots.

  • one year ago
  • one year ago

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  1. chicagochica5 Group Title
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    • one year ago
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  2. hartnn Group Title
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    Add 9 to both sides. what u get ?

    • one year ago
  3. chicagochica5 Group Title
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    My choices: A. –3, 3 B. –9, 9 \[-\sqrt{3}, \sqrt{3}\] D. no real number solutions

    • one year ago
  4. hartnn Group Title
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    Add 9 to both sides. what u get ?

    • one year ago
  5. chicagochica5 Group Title
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    C?

    • one year ago
  6. hartnn Group Title
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    Add 9 in both sides of x^2-9 =0 what u get? u don't get direct answers here, sorry.

    • one year ago
  7. chicagochica5 Group Title
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    @hartnn, I dont know how to... I get 81 - 9 = 0 which im pretty sure is wrong

    • one year ago
  8. hal_stirrup Group Title
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    there after the answer ONLY!!

    • one year ago
  9. hartnn Group Title
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    how did u get 81 ?

    • one year ago
  10. chicagochica5 Group Title
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    \[9^{2}\]

    • one year ago
  11. hartnn Group Title
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    why did u put x=9 ?

    • one year ago
  12. chicagochica5 Group Title
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    what?

    • one year ago
  13. hartnn Group Title
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    u got 81 by 9^2 but why 9^2 ? keep it as x^2 u have x^2-9=0 Adding 9 to both sides, x^2-9+9=0+9 x^2+0=9 x^2=9 can u solve this ?

    • one year ago
  14. Lovie03 Group Title
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    @hartnn help me for this problem Write an equation with the variable on each both side of the equal sign, at least one fractional cofficient, and a solution of-6. Thank you

    • one year ago
  15. hartnn Group Title
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    @Lovie03 i answered that, check it.

    • one year ago
  16. Lovie03 Group Title
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    how you get that

    • one year ago
  17. hartnn Group Title
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    @chicagochica5 x^2=9 can u solve this ?

    • one year ago
  18. hartnn Group Title
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    taking square root on both sides, x= +3 or x=-3

    • one year ago
  19. chicagochica5 Group Title
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    @hartnn, im sorry I do not understand what to do or how to solve

    • one year ago
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