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chicagochica5

  • 3 years ago

Solve the equation using square roots.

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  1. chicagochica5
    • 3 years ago
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  2. hartnn
    • 3 years ago
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    Add 9 to both sides. what u get ?

  3. chicagochica5
    • 3 years ago
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    My choices: A. –3, 3 B. –9, 9 \[-\sqrt{3}, \sqrt{3}\] D. no real number solutions

  4. hartnn
    • 3 years ago
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    Add 9 to both sides. what u get ?

  5. chicagochica5
    • 3 years ago
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    C?

  6. hartnn
    • 3 years ago
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    Add 9 in both sides of x^2-9 =0 what u get? u don't get direct answers here, sorry.

  7. chicagochica5
    • 3 years ago
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    @hartnn, I dont know how to... I get 81 - 9 = 0 which im pretty sure is wrong

  8. hal_stirrup
    • 3 years ago
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    there after the answer ONLY!!

  9. hartnn
    • 3 years ago
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    how did u get 81 ?

  10. chicagochica5
    • 3 years ago
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    \[9^{2}\]

  11. hartnn
    • 3 years ago
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    why did u put x=9 ?

  12. chicagochica5
    • 3 years ago
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    what?

  13. hartnn
    • 3 years ago
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    u got 81 by 9^2 but why 9^2 ? keep it as x^2 u have x^2-9=0 Adding 9 to both sides, x^2-9+9=0+9 x^2+0=9 x^2=9 can u solve this ?

  14. Lovie03
    • 3 years ago
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    @hartnn help me for this problem Write an equation with the variable on each both side of the equal sign, at least one fractional cofficient, and a solution of-6. Thank you

  15. hartnn
    • 3 years ago
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    @Lovie03 i answered that, check it.

  16. Lovie03
    • 3 years ago
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    how you get that

  17. hartnn
    • 3 years ago
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    @chicagochica5 x^2=9 can u solve this ?

  18. hartnn
    • 3 years ago
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    taking square root on both sides, x= +3 or x=-3

  19. chicagochica5
    • 3 years ago
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    @hartnn, im sorry I do not understand what to do or how to solve

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