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math_proof

what is the negation" all cabbages are green

  • one year ago
  • one year ago

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  1. nickhouraney
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    be more specific

    • one year ago
  2. math_proof
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    suppose that "if z is a w-group then z is solvable" is a true statement, you also know that the "z is solvable" is true. can you deduce that "z is a w-group" is true?

    • one year ago
  3. omgitsjc
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    i wish i was good a math

    • one year ago
  4. ChmE
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    no because for the statement to be true z is a w-group could be true or false

    • one year ago
  5. lgbasallote
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    unless there's more to that question...don't you just put a "not" before the adjective?

    • one year ago
  6. math_proof
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    igbasallote what are you talking about?

    • one year ago
  7. ChmE
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    in a "if p then q" statement. if "if p" is false the whole statement is true regardless of then p. If they are both true then it is also true. It can only be false if "if p" is true and "then q" is flase.

    • one year ago
  8. ChmE
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    I can give you an example to clarify if you want

    • one year ago
  9. ChmE
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    I was answering ur second question by the way

    • one year ago
  10. ChmE
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    @lgbasollote was answering your first.

    • one year ago
  11. ChmE
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    and @lgbasallote you were correct

    • one year ago
  12. math_proof
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    I don't get what lgbasallote was saying

    • one year ago
  13. ChmE
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    actually let me look at me logic notes to make sure.

    • one year ago
  14. ChmE
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    The correct answer to your first question is All cabages are not green

    • one year ago
  15. ChmE
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    Like the car is red. The negation is the car is not red

    • one year ago
  16. math_proof
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    why isn't it not all cabbages are green

    • one year ago
  17. ChmE
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    because that implies that some are green

    • one year ago
  18. ChmE
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    we want to to do a complete opposite

    • one year ago
  19. ChmE
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    its confusing I know

    • one year ago
  20. math_proof
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    so u wan't to tell that none of them are green right?

    • one year ago
  21. ChmE
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    correct

    • one year ago
  22. ChmE
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    Did you understand what I was saying to your second question

    • one year ago
  23. math_proof
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    im trying to figure it out now

    • one year ago
  24. ChmE
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    What class is this? just curious

    • one year ago
  25. math_proof
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    advanced mathematics

    • one year ago
  26. math_proof
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    whole class based on proofs basically

    • one year ago
  27. math_proof
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    induction proofing, contradictions, and now we are at sets theories

    • one year ago
  28. ChmE
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    I took a class called mathematical logic which involved a bunch of this stuff. Kinda interesting kinda hell

    • one year ago
  29. ChmE
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    I hate sets

    • one year ago
  30. ChmE
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    Only class I have ever had to drop cuz i was failing. Sets, relations, and functions.

    • one year ago
  31. ChmE
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    Let me know if you don't understand my explanation about your second question I can provide an example that would make it clearer. I'm going to move on to other questions

    • one year ago
  32. math_proof
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    thats pretty much what i am in now, and let me tell you that I have no idea how im going to pass that class

    • one year ago
  33. ChmE
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    Logic was kinda fun. Sets is hell. I would master definitions. completely understand what a subset is and what real numbers and complex numbers. just master definitions because you can use those in ur proofs. I wish I had done that.

    • one year ago
  34. math_proof
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    im trying to figure out that example and don't completely get it So P=>Q so if z is a w-group then z is solvable IS TRUE, then "Z is solvable is also true" why s s "Z is a w-group false?

    • one year ago
  35. DanielxAK
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    The negation of "all cabbages are green" is "there exists a cabbage which is not green". All is a quantifier.

    • one year ago
  36. math_proof
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    isn't the negation "all cabbages are not green?"

    • one year ago
  37. ChmE
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    So @DanielxAK we just had to show that for all to be false one is true?

    • one year ago
  38. ChmE
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    lets use p and q for your question all the words are confusing me lol. So the question is essentially... If, if p then q is true, then q is true" So its a nested statement?

    • one year ago
  39. ChmE
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    P-->Q T Premise Q T Prove

    • one year ago
  40. DanielxAK
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    I'm not sure I understand what you mean by that. If it was phrased, cabbage is green. Then, the negation would be cabbage is not green. But, you have "all cabbages are green". So, the negation would be "there exists a cabbage which isn't green". The negation of all is one. This might be able to explain it better than I can: http://www.math.cornell.edu/~hubbard/negation.pdf

    • one year ago
  41. ChmE
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    Good catch Daniels

    • one year ago
  42. ChmE
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    Your second question @math_proof, I think it is a correct statement. Because "if p" is true, for the statement to be true (which it is by a premise) "then q" must be true. and "if p" is false. Then "then q" is assumed true because it can't be proven otherwise.

    • one year ago
  43. ChmE
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    You got me inerested now. I dug out my logic notes. Law of Equivalence for Implication and Disjunction (LEID) states IF p-->q is true, THEN not p or q is true

    • one year ago
  44. math_proof
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    still confused omg

    • one year ago
  45. ChmE
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    So we are Given that P --> Q is true correct? and we have to prove that Q is true? am I understanding right?

    • one year ago
  46. math_proof
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    we know that Q is true

    • one year ago
  47. math_proof
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    so P can be either true of false

    • one year ago
  48. math_proof
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    so P=>Q, z is a w-group then z is solvable" is a true statement, so P->Q is true and we know Q is true because "Z is solvable" so P can be either True of False? thats what i'm thinking

    • one year ago
  49. ChmE
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    P->Q T Premise Q T Premise P T Prove Ok I'm on the right page

    • one year ago
  50. ChmE
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    So I would say the answer is ~P V P

    • one year ago
  51. math_proof
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    thats based on truth table on logical implication

    • one year ago
  52. ChmE
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    I agree

    • one year ago
  53. math_proof
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    so we can't deduce if P is true

    • one year ago
  54. ChmE
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    I have this cheat sheet that my teacher made us with all the laws of logic that can be used in a proof. If you'd like it i'll email it to you. Just private message me your email. If you are not comfortable with that I guess I could post it on this thread, but I've got warned for stuff like that

    • one year ago
  55. ChmE
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    I guess we can't for certain

    • one year ago
  56. math_proof
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    omg thanks so much for that, I actually get it now

    • one year ago
  57. ChmE
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    No problem. When you jump into sets I will be no help. Like I said earlier for sets proofs I would master definitions because my teacher used a lot of "By def'n..." in her proofs

    • one year ago
  58. math_proof
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    i never heard of this website, but now that i discovered it is so useful and helpful and for free

    • one year ago
  59. math_proof
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    how do you give a medal?

    • one year ago
  60. math_proof
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    oo oki got it

    • one year ago
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