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math_proof Group Title

what is the negation" all cabbages are green

  • 2 years ago
  • 2 years ago

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  1. nickhouraney Group Title
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    be more specific

    • 2 years ago
  2. math_proof Group Title
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    suppose that "if z is a w-group then z is solvable" is a true statement, you also know that the "z is solvable" is true. can you deduce that "z is a w-group" is true?

    • 2 years ago
  3. omgitsjc Group Title
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    i wish i was good a math

    • 2 years ago
  4. ChmE Group Title
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    no because for the statement to be true z is a w-group could be true or false

    • 2 years ago
  5. lgbasallote Group Title
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    unless there's more to that question...don't you just put a "not" before the adjective?

    • 2 years ago
  6. math_proof Group Title
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    igbasallote what are you talking about?

    • 2 years ago
  7. ChmE Group Title
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    in a "if p then q" statement. if "if p" is false the whole statement is true regardless of then p. If they are both true then it is also true. It can only be false if "if p" is true and "then q" is flase.

    • 2 years ago
  8. ChmE Group Title
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    I can give you an example to clarify if you want

    • 2 years ago
  9. ChmE Group Title
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    I was answering ur second question by the way

    • 2 years ago
  10. ChmE Group Title
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    @lgbasollote was answering your first.

    • 2 years ago
  11. ChmE Group Title
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    and @lgbasallote you were correct

    • 2 years ago
  12. math_proof Group Title
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    I don't get what lgbasallote was saying

    • 2 years ago
  13. ChmE Group Title
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    actually let me look at me logic notes to make sure.

    • 2 years ago
  14. ChmE Group Title
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    The correct answer to your first question is All cabages are not green

    • 2 years ago
  15. ChmE Group Title
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    Like the car is red. The negation is the car is not red

    • 2 years ago
  16. math_proof Group Title
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    why isn't it not all cabbages are green

    • 2 years ago
  17. ChmE Group Title
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    because that implies that some are green

    • 2 years ago
  18. ChmE Group Title
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    we want to to do a complete opposite

    • 2 years ago
  19. ChmE Group Title
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    its confusing I know

    • 2 years ago
  20. math_proof Group Title
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    so u wan't to tell that none of them are green right?

    • 2 years ago
  21. ChmE Group Title
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    correct

    • 2 years ago
  22. ChmE Group Title
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    Did you understand what I was saying to your second question

    • 2 years ago
  23. math_proof Group Title
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    im trying to figure it out now

    • 2 years ago
  24. ChmE Group Title
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    What class is this? just curious

    • 2 years ago
  25. math_proof Group Title
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    advanced mathematics

    • 2 years ago
  26. math_proof Group Title
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    whole class based on proofs basically

    • 2 years ago
  27. math_proof Group Title
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    induction proofing, contradictions, and now we are at sets theories

    • 2 years ago
  28. ChmE Group Title
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    I took a class called mathematical logic which involved a bunch of this stuff. Kinda interesting kinda hell

    • 2 years ago
  29. ChmE Group Title
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    I hate sets

    • 2 years ago
  30. ChmE Group Title
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    Only class I have ever had to drop cuz i was failing. Sets, relations, and functions.

    • 2 years ago
  31. ChmE Group Title
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    Let me know if you don't understand my explanation about your second question I can provide an example that would make it clearer. I'm going to move on to other questions

    • 2 years ago
  32. math_proof Group Title
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    thats pretty much what i am in now, and let me tell you that I have no idea how im going to pass that class

    • 2 years ago
  33. ChmE Group Title
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    Logic was kinda fun. Sets is hell. I would master definitions. completely understand what a subset is and what real numbers and complex numbers. just master definitions because you can use those in ur proofs. I wish I had done that.

    • 2 years ago
  34. math_proof Group Title
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    im trying to figure out that example and don't completely get it So P=>Q so if z is a w-group then z is solvable IS TRUE, then "Z is solvable is also true" why s s "Z is a w-group false?

    • 2 years ago
  35. DanielxAK Group Title
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    The negation of "all cabbages are green" is "there exists a cabbage which is not green". All is a quantifier.

    • 2 years ago
  36. math_proof Group Title
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    isn't the negation "all cabbages are not green?"

    • 2 years ago
  37. ChmE Group Title
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    So @DanielxAK we just had to show that for all to be false one is true?

    • 2 years ago
  38. ChmE Group Title
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    lets use p and q for your question all the words are confusing me lol. So the question is essentially... If, if p then q is true, then q is true" So its a nested statement?

    • 2 years ago
  39. ChmE Group Title
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    P-->Q T Premise Q T Prove

    • 2 years ago
  40. DanielxAK Group Title
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    I'm not sure I understand what you mean by that. If it was phrased, cabbage is green. Then, the negation would be cabbage is not green. But, you have "all cabbages are green". So, the negation would be "there exists a cabbage which isn't green". The negation of all is one. This might be able to explain it better than I can: http://www.math.cornell.edu/~hubbard/negation.pdf

    • 2 years ago
  41. ChmE Group Title
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    Good catch Daniels

    • 2 years ago
  42. ChmE Group Title
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    Your second question @math_proof, I think it is a correct statement. Because "if p" is true, for the statement to be true (which it is by a premise) "then q" must be true. and "if p" is false. Then "then q" is assumed true because it can't be proven otherwise.

    • 2 years ago
  43. ChmE Group Title
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    You got me inerested now. I dug out my logic notes. Law of Equivalence for Implication and Disjunction (LEID) states IF p-->q is true, THEN not p or q is true

    • 2 years ago
  44. math_proof Group Title
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    still confused omg

    • 2 years ago
  45. ChmE Group Title
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    So we are Given that P --> Q is true correct? and we have to prove that Q is true? am I understanding right?

    • 2 years ago
  46. math_proof Group Title
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    we know that Q is true

    • 2 years ago
  47. math_proof Group Title
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    so P can be either true of false

    • 2 years ago
  48. math_proof Group Title
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    so P=>Q, z is a w-group then z is solvable" is a true statement, so P->Q is true and we know Q is true because "Z is solvable" so P can be either True of False? thats what i'm thinking

    • 2 years ago
  49. ChmE Group Title
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    P->Q T Premise Q T Premise P T Prove Ok I'm on the right page

    • 2 years ago
  50. ChmE Group Title
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    So I would say the answer is ~P V P

    • 2 years ago
  51. math_proof Group Title
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    thats based on truth table on logical implication

    • 2 years ago
  52. ChmE Group Title
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    I agree

    • 2 years ago
  53. math_proof Group Title
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    so we can't deduce if P is true

    • 2 years ago
  54. ChmE Group Title
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    I have this cheat sheet that my teacher made us with all the laws of logic that can be used in a proof. If you'd like it i'll email it to you. Just private message me your email. If you are not comfortable with that I guess I could post it on this thread, but I've got warned for stuff like that

    • 2 years ago
  55. ChmE Group Title
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    I guess we can't for certain

    • 2 years ago
  56. math_proof Group Title
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    omg thanks so much for that, I actually get it now

    • 2 years ago
  57. ChmE Group Title
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    No problem. When you jump into sets I will be no help. Like I said earlier for sets proofs I would master definitions because my teacher used a lot of "By def'n..." in her proofs

    • 2 years ago
  58. math_proof Group Title
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    i never heard of this website, but now that i discovered it is so useful and helpful and for free

    • 2 years ago
  59. math_proof Group Title
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    how do you give a medal?

    • 2 years ago
  60. math_proof Group Title
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    oo oki got it

    • 2 years ago
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