## Miyuru 3 years ago Forces at equilibrium

1. bahrom7893

|dw:1348489516558:dw|

2. bahrom7893

|dw:1348489858765:dw|

3. Miyuru

|dw:1348489726714:dw|

4. bahrom7893

I'm not following the drawing..

5. bahrom7893

@amistre64 do you?

6. amistre64

it looks familiar, you are prolly trying to find the Rs to put the system in equilibrium.

7. amistre64

think of a complicated seesaw

8. Miyuru

Yeah i trying to make it equilibrium

9. Miyuru

I need to find the r value

10. amistre64

|dw:1348490479611:dw|

11. amistre64

if i were to take a guess; r1 = -20 r2/.8 = 16(1) -20(.8) r2 = 16(.8) -20(.64) = 0 .... been too long

12. amistre64

theres is some interplay between distance and force ....

13. Miyuru

For this we should find that the upward forces are equal to downward forces

14. Miyuru

This question is about moment M = Fd

15. amistre64

http://demonstrations.wolfram.com/EquilibriumOfASuspendedMobile/ this looks pretty cool

16. amistre64

yeah, its just to early for me to focus thru this :/ ill think on it and come backl later to see if theres any progress on it

17. Miyuru

Ahh ok Thnx for ypur help this too complicated for me too I'll be looking for an answer from u

18. Miyuru

This question is about rotation the clockwise and anti clockwise but bcauz of these forces it won't rotate and I have to find the R1 and R2 value

19. Algebraic!

@Miyuru you'll have better luck getting help if you actually ask a question (don't forget to state it fully and clearly)

20. pitankar

the net torque or couple on the system is zero.

21. pkjha3105

equilibrium means the condition of balancd state or rest condition.in this case net force and torque on the system is zero.

22. amistre64

|dw:1348513729666:dw|an idea i have, right or wrong, as to take an arbitrary fulcrum. And the left should equate to the right

23. amistre64

-16(.9) + R1(.7) = -16(.1) + R2(.9) -14.4 + R1(.7) = -1.6 + R2(.9) R1(.7) = 12.8 + R2(.9) R1 = (12.8 + R2(.9)).7