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Coolsector
 2 years ago
Best ResponseYou've already chosen the best response.0f(u,v) = u/v f' = (u'vv'u)/(v^2) does this help ?

haterofmath
 2 years ago
Best ResponseYou've already chosen the best response.0no not really....i understand what you put up, but there's like two part to the numerator

Coolsector
 2 years ago
Best ResponseYou've already chosen the best response.0so you can either use the product rule or just simplify the numerator then differentiate

KKJ
 2 years ago
Best ResponseYou've already chosen the best response.0Differentiation using the quotient rule

KKJ
 2 years ago
Best ResponseYou've already chosen the best response.0\[y = \frac{ u }{ v } \rightarrow \frac{ dy }{ dx } = \frac{ v \frac{ du }{ dx }u \frac{ dv }{dx } }{ v^2 }\]
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