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if an aroma of vanillin fills a room, having the dimensions of 12ftx10.5ftx10.0ft. if the density is 2.4x10^11g/L how many kilograms of vanillin are in the room?
 one year ago
 one year ago
if an aroma of vanillin fills a room, having the dimensions of 12ftx10.5ftx10.0ft. if the density is 2.4x10^11g/L how many kilograms of vanillin are in the room?
 one year ago
 one year ago

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.Sam.Best ResponseYou've already chosen the best response.0
Density formula: \[\rho=\frac{m}{V}\] \[m=\rho V\]  Volume= 12x10.5x10.0=1260ft^3= 35679 liters \[m=\rho V\] \[m=( 2.4x10^{11}g/L )(35679L) \] \[m=8.56\times 10^{7}g=8.56 \times 10^{10}kg\]
 one year ago

dddanBest ResponseYou've already chosen the best response.0
hey thanks can you explain how you get from cubic feet to liters?
 one year ago

.Sam.Best ResponseYou've already chosen the best response.0
You either remembering it or from a table of conversions, 1 Cubic Feet = 28.32 Liters You can arrange it so that the cubic feet is at the bottom when you multiply, to cancel the cubic feet. You want liters here, so: \[1280~ ft^3 \times \frac{28.32~liters}{1~Cubic~feet}=35679~liters\]
 one year ago

dddanBest ResponseYou've already chosen the best response.0
got it. thank you so much!
 one year ago
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