## dddan Group Title if an aroma of vanillin fills a room, having the dimensions of 12ftx10.5ftx10.0ft. if the density is 2.4x10^-11g/L how many kilograms of vanillin are in the room? 2 years ago 2 years ago

1. .Sam.

Density formula: $\rho=\frac{m}{V}$ $m=\rho V$ ------------------------------------------------------- Volume= 12x10.5x10.0=1260ft^3= 35679 liters $m=\rho V$ $m=( 2.4x10^{-11}g/L )(35679L)$ $m=8.56\times 10^{-7}g=8.56 \times 10^{-10}kg$

2. dddan

hey thanks- can you explain how you get from cubic feet to liters?

3. .Sam.

You either remembering it or from a table of conversions, 1 Cubic Feet = 28.32 Liters You can arrange it so that the cubic feet is at the bottom when you multiply, to cancel the cubic feet. You want liters here, so: $1280~ ft^3 \times \frac{28.32~liters}{1~Cubic~feet}=35679~liters$

4. dddan

got it. thank you so much!