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dddan
 2 years ago
if an aroma of vanillin fills a room, having the dimensions of 12ftx10.5ftx10.0ft. if the density is 2.4x10^11g/L how many kilograms of vanillin are in the room?
dddan
 2 years ago
if an aroma of vanillin fills a room, having the dimensions of 12ftx10.5ftx10.0ft. if the density is 2.4x10^11g/L how many kilograms of vanillin are in the room?

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.Sam.
 2 years ago
Best ResponseYou've already chosen the best response.0Density formula: \[\rho=\frac{m}{V}\] \[m=\rho V\]  Volume= 12x10.5x10.0=1260ft^3= 35679 liters \[m=\rho V\] \[m=( 2.4x10^{11}g/L )(35679L) \] \[m=8.56\times 10^{7}g=8.56 \times 10^{10}kg\]

dddan
 2 years ago
Best ResponseYou've already chosen the best response.0hey thanks can you explain how you get from cubic feet to liters?

.Sam.
 2 years ago
Best ResponseYou've already chosen the best response.0You either remembering it or from a table of conversions, 1 Cubic Feet = 28.32 Liters You can arrange it so that the cubic feet is at the bottom when you multiply, to cancel the cubic feet. You want liters here, so: \[1280~ ft^3 \times \frac{28.32~liters}{1~Cubic~feet}=35679~liters\]

dddan
 2 years ago
Best ResponseYou've already chosen the best response.0got it. thank you so much!
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