Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

if an aroma of vanillin fills a room, having the dimensions of 12ftx10.5ftx10.0ft. if the density is 2.4x10^-11g/L how many kilograms of vanillin are in the room?

Chemistry
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SIGN UP FOR FREE
Density formula: \[\rho=\frac{m}{V}\] \[m=\rho V\] ------------------------------------------------------- Volume= 12x10.5x10.0=1260ft^3= 35679 liters \[m=\rho V\] \[m=( 2.4x10^{-11}g/L )(35679L) \] \[m=8.56\times 10^{-7}g=8.56 \times 10^{-10}kg\]
hey thanks- can you explain how you get from cubic feet to liters?
You either remembering it or from a table of conversions, 1 Cubic Feet = 28.32 Liters You can arrange it so that the cubic feet is at the bottom when you multiply, to cancel the cubic feet. You want liters here, so: \[1280~ ft^3 \times \frac{28.32~liters}{1~Cubic~feet}=35679~liters\]

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

got it. thank you so much!

Not the answer you are looking for?

Search for more explanations.

Ask your own question