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andriod09

  • 2 years ago

Pythagoreum problem please help! Triangle is in comments

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  1. andriod09
    • 2 years ago
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    |dw:1348498599367:dw| ik what the answers are, i just need help finding how to get them They are 5", 12", and 13"

  2. cgreenwade2000
    • 2 years ago
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    The Theorem is a^2 + b^2 = c^2 Where a and b are sides of the right triangle and c is the hypotenuse of the right triangle.

  3. andriod09
    • 2 years ago
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    ik the thirum, i just havn't done it in about 3 years.

  4. cgreenwade2000
    • 2 years ago
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    Ok. Let a = x and b = x+7 therefore, (x)^2 + (x+7)^2 = (8+x)^2

  5. andriod09
    • 2 years ago
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    okay, then what?

  6. andriod09
    • 2 years ago
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    @cgreenwade2000

  7. andriod09
    • 2 years ago
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    @cshalvey @Callisto @Yahoo!

  8. Yahoo!
    • 2 years ago
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    \[(x+8)^2 = x^2 + (x+7)^2\]

  9. Yahoo!
    • 2 years ago
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    nw expand this....... \[(a+b)^2 = a^2 + 2ab + b^2\]

  10. andriod09
    • 2 years ago
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    please do not use the equation button i have a mathjax error and it annoys me. i see the slashes and brackets and braces.

  11. erica.d
    • 2 years ago
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    (x+8)^2=x^2+(x+7)^2

  12. Yahoo!
    • 2 years ago
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    lol.... ) (x)^2 + (x+7)^2 = (8+x)^2

  13. andriod09
    • 2 years ago
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    okay?? then you do??????

  14. Callisto
    • 2 years ago
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    Expand the terms for both sides of the question, then simplify it. As Yahoo! mentioned, you can expand the term (a+b)^2 by using the identity (a+b)^2 = a^2 + 2ab + b^2. If you don't know where this identity comes from, you can simply perform multiplication for the term, i.e. (a+b)^2 = (a+b)(a+b), now expand it. What have you got for now?

  15. andriod09
    • 2 years ago
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    |dw:1348501546848:dw|

  16. andriod09
    • 2 years ago
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    @Callisto that made no sense to me. :c

  17. Callisto
    • 2 years ago
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    May I know what made no sense to you?

  18. andriod09
    • 2 years ago
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    "Expand the terms for both sides of the question, then simplify it. As Yahoo! mentioned, you can expand the term (a+b)^2 by using the identity (a+b)^2 = a^2 + 2ab + b^2. If you don't know where this identity comes from, you can simply perform multiplication for the term, i.e. (a+b)^2 = (a+b)(a+b), now expand it."

  19. Callisto
    • 2 years ago
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    Which part you don't understand?

  20. andriod09
    • 2 years ago
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    the expansion parts.

  21. Callisto
    • 2 years ago
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    Do you know how to expand (a+b)^2?

  22. andriod09
    • 2 years ago
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    no. im homeschooled, i havn't even done pythagereum theory much.

  23. erica.d
    • 2 years ago
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    x^2+16x+64=x^2+x^2+14x+49

  24. Callisto
    • 2 years ago
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    That is not Pyth. Thm. It's just simple multiplication of some factors. For instance, \[x^2 = x \times x\]\[x^3 = x \times x \times x\] Similarly, \[(a+b)^2 = (a+b) \times (a+b)\]It can be expanded in this way: \[(a+b)^2 = (a+b) \times (a+b) = a(a+b) + b(a+b)\]Can you further expand and simplify it?

  25. andriod09
    • 2 years ago
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    i can not see the equations from the eqtation button!!!!!!!!!!

  26. Callisto
    • 2 years ago
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    equation button is for you to type latex...

  27. Callisto
    • 2 years ago
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    *type in latex

  28. andriod09
    • 2 years ago
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    yes, but i see: \[\\]\[\\\]][\\]\[\\] thats what i see, i see evey single slash, all the brackets, the braces, everything

  29. Callisto
    • 2 years ago
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    \sqrt{x} = \(\sqrt{x}\) and so on.. You can try these on the equation button. Though, back to your question, are you still having trouble with your question?

  30. andriod09
    • 2 years ago
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    yes. and i see the \sqrt{x} = \(\sqrt{x}\) like i see all the braces, the terms for them, and everything like that. my mathjax thing isn't working atm

  31. Callisto
    • 2 years ago
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    Can you see what I've typed in latex?

  32. andriod09
    • 2 years ago
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    no. i see the equation as if you write it with out the button, like i don't see the (x)^2 i see the ()^{} and things like that. and yes, i still am having problems with my problem

  33. Callisto
    • 2 years ago
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    |dw:1348503516047:dw|

  34. andriod09
    • 2 years ago
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    yes.

  35. Callisto
    • 2 years ago
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    Now, can you expand a(a+b) +b(a+b) ?

  36. andriod09
    • 2 years ago
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    how?

  37. Callisto
    • 2 years ago
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    Distributing a into a+b and b into a+b

  38. andriod09
    • 2 years ago
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    then??

  39. Callisto
    • 2 years ago
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    Expand it first.

  40. andriod09
    • 2 years ago
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    how?

  41. Callisto
    • 2 years ago
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    a(a+b) = a(a) + a(b) = a^2 + ab Can you try b(a+b) now?

  42. andriod09
    • 2 years ago
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    is it: b(a+b)=b(a)+b(b)=b^2+ba?

  43. Callisto
    • 2 years ago
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    Yes! Now combine them What is a(a+b) + b(a+b) ?

  44. andriod09
    • 2 years ago
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    (a(a+b) = a(a) + a(b) = a^2 + ab)+(b(a+b)=b(a)+b(b)=b^2+ba)?

  45. Callisto
    • 2 years ago
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    Nope not really.. can you try again?

  46. andriod09
    • 2 years ago
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    what would it be then?

  47. andriod09
    • 2 years ago
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    @ash2326

  48. andriod09
    • 2 years ago
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    @ganeshie8

  49. andriod09
    • 2 years ago
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    @Callisto

  50. andriod09
    • 2 years ago
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    @ash2326

  51. andriod09
    • 2 years ago
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    someone help me please!

  52. andriod09
    • 2 years ago
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    |dw:1348510329568:dw|

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