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andriod09

Pythagoreum problem please help! Triangle is in comments

  • one year ago
  • one year ago

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  1. andriod09
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    |dw:1348498599367:dw| ik what the answers are, i just need help finding how to get them They are 5", 12", and 13"

    • one year ago
  2. cgreenwade2000
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    The Theorem is a^2 + b^2 = c^2 Where a and b are sides of the right triangle and c is the hypotenuse of the right triangle.

    • one year ago
  3. andriod09
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    ik the thirum, i just havn't done it in about 3 years.

    • one year ago
  4. cgreenwade2000
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    Ok. Let a = x and b = x+7 therefore, (x)^2 + (x+7)^2 = (8+x)^2

    • one year ago
  5. andriod09
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    okay, then what?

    • one year ago
  6. andriod09
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    @cgreenwade2000

    • one year ago
  7. andriod09
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    @cshalvey @Callisto @Yahoo!

    • one year ago
  8. Yahoo!
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    \[(x+8)^2 = x^2 + (x+7)^2\]

    • one year ago
  9. Yahoo!
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    nw expand this....... \[(a+b)^2 = a^2 + 2ab + b^2\]

    • one year ago
  10. andriod09
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    please do not use the equation button i have a mathjax error and it annoys me. i see the slashes and brackets and braces.

    • one year ago
  11. erica.d
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    (x+8)^2=x^2+(x+7)^2

    • one year ago
  12. Yahoo!
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    lol.... ) (x)^2 + (x+7)^2 = (8+x)^2

    • one year ago
  13. andriod09
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    okay?? then you do??????

    • one year ago
  14. Callisto
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    Expand the terms for both sides of the question, then simplify it. As Yahoo! mentioned, you can expand the term (a+b)^2 by using the identity (a+b)^2 = a^2 + 2ab + b^2. If you don't know where this identity comes from, you can simply perform multiplication for the term, i.e. (a+b)^2 = (a+b)(a+b), now expand it. What have you got for now?

    • one year ago
  15. andriod09
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    |dw:1348501546848:dw|

    • one year ago
  16. andriod09
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    @Callisto that made no sense to me. :c

    • one year ago
  17. Callisto
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    May I know what made no sense to you?

    • one year ago
  18. andriod09
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    "Expand the terms for both sides of the question, then simplify it. As Yahoo! mentioned, you can expand the term (a+b)^2 by using the identity (a+b)^2 = a^2 + 2ab + b^2. If you don't know where this identity comes from, you can simply perform multiplication for the term, i.e. (a+b)^2 = (a+b)(a+b), now expand it."

    • one year ago
  19. Callisto
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    Which part you don't understand?

    • one year ago
  20. andriod09
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    the expansion parts.

    • one year ago
  21. Callisto
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    Do you know how to expand (a+b)^2?

    • one year ago
  22. andriod09
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    no. im homeschooled, i havn't even done pythagereum theory much.

    • one year ago
  23. erica.d
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    x^2+16x+64=x^2+x^2+14x+49

    • one year ago
  24. Callisto
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    That is not Pyth. Thm. It's just simple multiplication of some factors. For instance, \[x^2 = x \times x\]\[x^3 = x \times x \times x\] Similarly, \[(a+b)^2 = (a+b) \times (a+b)\]It can be expanded in this way: \[(a+b)^2 = (a+b) \times (a+b) = a(a+b) + b(a+b)\]Can you further expand and simplify it?

    • one year ago
  25. andriod09
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    i can not see the equations from the eqtation button!!!!!!!!!!

    • one year ago
  26. Callisto
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    equation button is for you to type latex...

    • one year ago
  27. Callisto
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    *type in latex

    • one year ago
  28. andriod09
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    yes, but i see: \[\\]\[\\\]][\\]\[\\] thats what i see, i see evey single slash, all the brackets, the braces, everything

    • one year ago
  29. Callisto
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    \sqrt{x} = \(\sqrt{x}\) and so on.. You can try these on the equation button. Though, back to your question, are you still having trouble with your question?

    • one year ago
  30. andriod09
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    yes. and i see the \sqrt{x} = \(\sqrt{x}\) like i see all the braces, the terms for them, and everything like that. my mathjax thing isn't working atm

    • one year ago
  31. Callisto
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    Can you see what I've typed in latex?

    • one year ago
  32. andriod09
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    no. i see the equation as if you write it with out the button, like i don't see the (x)^2 i see the ()^{} and things like that. and yes, i still am having problems with my problem

    • one year ago
  33. Callisto
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    |dw:1348503516047:dw|

    • one year ago
  34. andriod09
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    yes.

    • one year ago
  35. Callisto
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    Now, can you expand a(a+b) +b(a+b) ?

    • one year ago
  36. andriod09
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    how?

    • one year ago
  37. Callisto
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    Distributing a into a+b and b into a+b

    • one year ago
  38. andriod09
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    then??

    • one year ago
  39. Callisto
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    Expand it first.

    • one year ago
  40. andriod09
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    how?

    • one year ago
  41. Callisto
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    a(a+b) = a(a) + a(b) = a^2 + ab Can you try b(a+b) now?

    • one year ago
  42. andriod09
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    is it: b(a+b)=b(a)+b(b)=b^2+ba?

    • one year ago
  43. Callisto
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    Yes! Now combine them What is a(a+b) + b(a+b) ?

    • one year ago
  44. andriod09
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    (a(a+b) = a(a) + a(b) = a^2 + ab)+(b(a+b)=b(a)+b(b)=b^2+ba)?

    • one year ago
  45. Callisto
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    Nope not really.. can you try again?

    • one year ago
  46. andriod09
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    what would it be then?

    • one year ago
  47. andriod09
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    @ash2326

    • one year ago
  48. andriod09
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    @ganeshie8

    • one year ago
  49. andriod09
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    @Callisto

    • one year ago
  50. andriod09
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    @ash2326

    • one year ago
  51. andriod09
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    someone help me please!

    • one year ago
  52. andriod09
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    |dw:1348510329568:dw|

    • one year ago
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