andriod09
Pythagoreum problem please help!
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andriod09
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ik what the answers are, i just need help finding how to get them
They are 5", 12", and 13"
cgreenwade2000
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The Theorem is a^2 + b^2 = c^2
Where a and b are sides of the right triangle and c is the hypotenuse of the right triangle.
andriod09
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ik the thirum, i just havn't done it in about 3 years.
cgreenwade2000
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Ok. Let a = x and b = x+7
therefore,
(x)^2 + (x+7)^2 = (8+x)^2
andriod09
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okay, then what?
andriod09
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@cgreenwade2000
andriod09
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@cshalvey @Callisto @Yahoo!
Yahoo!
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\[(x+8)^2 = x^2 + (x+7)^2\]
Yahoo!
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nw expand this.......
\[(a+b)^2 = a^2 + 2ab + b^2\]
andriod09
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please do not use the equation button i have a mathjax error and it annoys me. i see the slashes and brackets and braces.
erica.d
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(x+8)^2=x^2+(x+7)^2
Yahoo!
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lol.... ) (x)^2 + (x+7)^2 = (8+x)^2
andriod09
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okay?? then you do??????
Callisto
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Expand the terms for both sides of the question, then simplify it.
As Yahoo! mentioned, you can expand the term (a+b)^2 by using the identity (a+b)^2 = a^2 + 2ab + b^2.
If you don't know where this identity comes from, you can simply perform multiplication for the term, i.e. (a+b)^2 = (a+b)(a+b), now expand it.
What have you got for now?
andriod09
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andriod09
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@Callisto that made no sense to me. :c
Callisto
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May I know what made no sense to you?
andriod09
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"Expand the terms for both sides of the question, then simplify it.
As Yahoo! mentioned, you can expand the term (a+b)^2 by using the identity (a+b)^2 = a^2 + 2ab + b^2.
If you don't know where this identity comes from, you can simply perform multiplication for the term, i.e. (a+b)^2 = (a+b)(a+b), now expand it."
Callisto
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Which part you don't understand?
andriod09
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the expansion parts.
Callisto
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Do you know how to expand (a+b)^2?
andriod09
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no. im homeschooled, i havn't even done pythagereum theory much.
erica.d
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x^2+16x+64=x^2+x^2+14x+49
Callisto
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That is not Pyth. Thm. It's just simple multiplication of some factors.
For instance,
\[x^2 = x \times x\]\[x^3 = x \times x \times x\] Similarly, \[(a+b)^2 = (a+b) \times (a+b)\]It can be expanded in this way:
\[(a+b)^2 = (a+b) \times (a+b) = a(a+b) + b(a+b)\]Can you further expand and simplify it?
andriod09
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i can not see the equations from the eqtation button!!!!!!!!!!
Callisto
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equation button is for you to type latex...
Callisto
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*type in latex
andriod09
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yes, but i see:
\[\\]\[\\\]][\\]\[\\] thats what i see, i see evey single slash, all the brackets, the braces, everything
Callisto
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\sqrt{x} = \(\sqrt{x}\) and so on.. You can try these on the equation button. Though, back to your question, are you still having trouble with your question?
andriod09
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yes. and i see the \sqrt{x} = \(\sqrt{x}\) like i see all the braces, the terms for them, and everything like that. my mathjax thing isn't working atm
Callisto
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Can you see what I've typed in latex?
andriod09
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no. i see the equation as if you write it with out the button, like i don't see the (x)^2 i see the ()^{} and things like that. and yes, i still am having problems with my problem
Callisto
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andriod09
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yes.
Callisto
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Now, can you expand a(a+b) +b(a+b) ?
andriod09
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how?
Callisto
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Distributing a into a+b and b into a+b
andriod09
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then??
Callisto
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Expand it first.
andriod09
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how?
Callisto
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a(a+b) = a(a) + a(b) = a^2 + ab
Can you try b(a+b) now?
andriod09
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is it:
b(a+b)=b(a)+b(b)=b^2+ba?
Callisto
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Yes!
Now combine them
What is a(a+b) + b(a+b) ?
andriod09
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(a(a+b) = a(a) + a(b) = a^2 + ab)+(b(a+b)=b(a)+b(b)=b^2+ba)?
Callisto
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Nope not really.. can you try again?
andriod09
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what would it be then?
andriod09
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@ash2326
andriod09
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@ganeshie8
andriod09
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@Callisto
andriod09
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@ash2326
andriod09
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someone help me please!
andriod09
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