A community for students.
Here's the question you clicked on:
 0 viewing
dddan
 3 years ago
a 1.40 g sample of gold having a density of 19.32 g/cm^3 is hammered into a very thin sheet. if the area of the sheet is 35.0ft^2, what is the average thickness of the sheet expressed in centimeters?
dddan
 3 years ago
a 1.40 g sample of gold having a density of 19.32 g/cm^3 is hammered into a very thin sheet. if the area of the sheet is 35.0ft^2, what is the average thickness of the sheet expressed in centimeters?

This Question is Closed

.Sam.
 3 years ago
Best ResponseYou've already chosen the best response.1Using back the formula, \[\rho= \frac{m}{V}\] \[V= \frac{m}{\rho}\] \[V= \frac{1.40 g }{19.32 g/cm^3}\] \[V= 0.072cm^3\]  Changing 35.0ft^2, \[35.0ft^2=\frac{929cm^2}{1ft^2}=32515cm^2\]  We assume that the metal sheet is either cubed or cuboid, \[V=Length \times Base \times Height\] \[V=Aree \times Height\] \[Height=\frac{Volume}{Area}\] \[Height=\frac{0.072cm^3}{32515cm^2}\] \[Height=2.21 \times 10^{6}cm\]

dddan
 3 years ago
Best ResponseYou've already chosen the best response.0thanks can you explain how you get from v=basexhightxlength to v=areaxheight?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.