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dddan Group Title

how do you simplify (18u^6v^5+24u^3v^3)/42u^2v^5

  • one year ago
  • one year ago

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  1. JakeV8 Group Title
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    Try factoring the top first. Factor out all the numbers, u, and v terms you can. Then look for opportunities to cancel with the terms on the bottom.

    • one year ago
  2. dddan Group Title
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    ok i factored out the top but i still dont know what to do next..

    • one year ago
  3. JakeV8 Group Title
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    what did you get?

    • one year ago
  4. dddan Group Title
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    3u^3v^3(6u^3v^2+8) / 42u^2v^5

    • one year ago
  5. JakeV8 Group Title
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    ok, great Now you can cancel the 3 with the 42... 3 "goes into" 42 by 14

    • one year ago
  6. JakeV8 Group Title
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    so 14 is left on bottom and you can cancel the u^2 on the bottom with the u^3 in the front on top, leaving just u out front and cancel the v^3 out in front on top with the v^5 on the bottom, leaving v^2 on the bottom

    • one year ago
  7. dddan Group Title
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    alright so what to i do with (6u^3v^2+8)?

    • one year ago
  8. JakeV8 Group Title
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    Hold on... Is (18u^6v^5+24u^3v^3)/42u^2v^5 written like: \[\frac{ 18u ^{6}6v ^{5}+24u ^{3}v ^{3} }{ 42u ^{2}v ^{5} }\]

    • one year ago
  9. dddan Group Title
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    yup

    • one year ago
  10. JakeV8 Group Title
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    You can simplify that part in your last post slightly by multiplying the 6 and 3 together to get (18u^3v^2 + 8) and you could then factor out another 2, to get 2(9u^3v^2 + 4), but you can't cancel that 2 with anything on the bottom because you only had 13 left on the bottom.

    • one year ago
  11. dddan Group Title
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    you mean 14 on the bottom..

    • one year ago
  12. JakeV8 Group Title
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    so like you had, 3u^3v^3(6u^3v^2+8) / 42u^2v^5 simplify parenthesis and factor out 2 to get: (3u^3v^3)(2)(9u^3v^2 + 4) / 42u^2v^5 and cancel whatever you can to get: 2u(9u^3v2 + 4) / 13v^3

    • one year ago
  13. JakeV8 Group Title
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    yes, sorry, 14 on bottom

    • one year ago
  14. JakeV8 Group Title
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    so you CAN cancel that extra 2 on top, leaving 7 on the bottom

    • one year ago
  15. JakeV8 Group Title
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    good catch!

    • one year ago
  16. dddan Group Title
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    alright so now we got rid of the 2 and then put the 7 on the bottom, i then factored the u(9u^3v^2+4) and simplified the v's and got (9u^3+4u)/7....

    • one year ago
  17. JakeV8 Group Title
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    you lost me... but I also messed up... I multiplied the 6 and 3 inside the parenthesis to get 18, but then when I factored out the 2 (to leave 9), I left the original 3 in the term :( Sorry

    • one year ago
  18. JakeV8 Group Title
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    wait, hold on, that 3 was the exponent on u. typing this stuff is killing me... sorry for the confusion.

    • one year ago
  19. JakeV8 Group Title
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    Should be: 2u(9u^3v^2 + 4) / 14v^3 Then cancel the 2: u(9u^3v^2 + 4) / 7v^3 An you are done at that point... all simplified.

    • one year ago
  20. JakeV8 Group Title
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    Ugly, yes, but simplified

    • one year ago
  21. dddan Group Title
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    ya i tried to go a step further but i will leave at that this is complicated enough. thank u so much!

    • one year ago
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