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JakeV8 Group TitleBest ResponseYou've already chosen the best response.0
Try factoring the top first. Factor out all the numbers, u, and v terms you can. Then look for opportunities to cancel with the terms on the bottom.
 one year ago

dddan Group TitleBest ResponseYou've already chosen the best response.0
ok i factored out the top but i still dont know what to do next..
 one year ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.0
what did you get?
 one year ago

dddan Group TitleBest ResponseYou've already chosen the best response.0
3u^3v^3(6u^3v^2+8) / 42u^2v^5
 one year ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.0
ok, great Now you can cancel the 3 with the 42... 3 "goes into" 42 by 14
 one year ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.0
so 14 is left on bottom and you can cancel the u^2 on the bottom with the u^3 in the front on top, leaving just u out front and cancel the v^3 out in front on top with the v^5 on the bottom, leaving v^2 on the bottom
 one year ago

dddan Group TitleBest ResponseYou've already chosen the best response.0
alright so what to i do with (6u^3v^2+8)?
 one year ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.0
Hold on... Is (18u^6v^5+24u^3v^3)/42u^2v^5 written like: \[\frac{ 18u ^{6}6v ^{5}+24u ^{3}v ^{3} }{ 42u ^{2}v ^{5} }\]
 one year ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.0
You can simplify that part in your last post slightly by multiplying the 6 and 3 together to get (18u^3v^2 + 8) and you could then factor out another 2, to get 2(9u^3v^2 + 4), but you can't cancel that 2 with anything on the bottom because you only had 13 left on the bottom.
 one year ago

dddan Group TitleBest ResponseYou've already chosen the best response.0
you mean 14 on the bottom..
 one year ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.0
so like you had, 3u^3v^3(6u^3v^2+8) / 42u^2v^5 simplify parenthesis and factor out 2 to get: (3u^3v^3)(2)(9u^3v^2 + 4) / 42u^2v^5 and cancel whatever you can to get: 2u(9u^3v2 + 4) / 13v^3
 one year ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.0
yes, sorry, 14 on bottom
 one year ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.0
so you CAN cancel that extra 2 on top, leaving 7 on the bottom
 one year ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.0
good catch!
 one year ago

dddan Group TitleBest ResponseYou've already chosen the best response.0
alright so now we got rid of the 2 and then put the 7 on the bottom, i then factored the u(9u^3v^2+4) and simplified the v's and got (9u^3+4u)/7....
 one year ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.0
you lost me... but I also messed up... I multiplied the 6 and 3 inside the parenthesis to get 18, but then when I factored out the 2 (to leave 9), I left the original 3 in the term :( Sorry
 one year ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.0
wait, hold on, that 3 was the exponent on u. typing this stuff is killing me... sorry for the confusion.
 one year ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.0
Should be: 2u(9u^3v^2 + 4) / 14v^3 Then cancel the 2: u(9u^3v^2 + 4) / 7v^3 An you are done at that point... all simplified.
 one year ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.0
Ugly, yes, but simplified
 one year ago

dddan Group TitleBest ResponseYou've already chosen the best response.0
ya i tried to go a step further but i will leave at that this is complicated enough. thank u so much!
 one year ago
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