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HarkiratBest ResponseYou've already chosen the best response.1
Which method do you have to use??? Factorisation??
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
Compare your quadratic equation with \(ax^2+bx+c=0\) find a,b,c then the two roots of x are: \(\huge{x=\frac{b \pm \sqrt{b^24ac}}{2a}}\)
 one year ago

Geometry_HaterBest ResponseYou've already chosen the best response.0
ok it just says solve the equation graphically
 one year ago

HarkiratBest ResponseYou've already chosen the best response.1
Put different values of x and get corresponding values of y, plot them and see where the graph intersects the xaxis....... the intersection points are the solutions....
 one year ago

HarkiratBest ResponseYou've already chosen the best response.1
dw:1348520452396:dw
 one year ago

robtobeyBest ResponseYou've already chosen the best response.0
Your plot is attached. Notice that the curve does not cross the x axis. There are no real roots.
 one year ago
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