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Harkirat
 2 years ago
Best ResponseYou've already chosen the best response.1Which method do you have to use??? Factorisation??

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0Compare your quadratic equation with \(ax^2+bx+c=0\) find a,b,c then the two roots of x are: \(\huge{x=\frac{b \pm \sqrt{b^24ac}}{2a}}\)

Geometry_Hater
 2 years ago
Best ResponseYou've already chosen the best response.0ok it just says solve the equation graphically

Harkirat
 2 years ago
Best ResponseYou've already chosen the best response.1Put different values of x and get corresponding values of y, plot them and see where the graph intersects the xaxis....... the intersection points are the solutions....

robtobey
 2 years ago
Best ResponseYou've already chosen the best response.0Your plot is attached. Notice that the curve does not cross the x axis. There are no real roots.
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