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Harkirat Group TitleBest ResponseYou've already chosen the best response.1
Which method do you have to use??? Factorisation??
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
Compare your quadratic equation with \(ax^2+bx+c=0\) find a,b,c then the two roots of x are: \(\huge{x=\frac{b \pm \sqrt{b^24ac}}{2a}}\)
 2 years ago

Geometry_Hater Group TitleBest ResponseYou've already chosen the best response.0
ok it just says solve the equation graphically
 2 years ago

Harkirat Group TitleBest ResponseYou've already chosen the best response.1
Put different values of x and get corresponding values of y, plot them and see where the graph intersects the xaxis....... the intersection points are the solutions....
 2 years ago

Harkirat Group TitleBest ResponseYou've already chosen the best response.1
dw:1348520452396:dw
 2 years ago

robtobey Group TitleBest ResponseYou've already chosen the best response.0
Your plot is attached. Notice that the curve does not cross the x axis. There are no real roots.
 2 years ago
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