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sorry also -(-2) is positive 2 as well.

ok so my A coefficient is just 3

Correct

Ok now what do i do in the equation?

I also made the mistake of -3 in the equation it is actually 3

I'll equate it out from the original

\[(2\pm \sqrt{64})/6\]
\[2\pm8/6\]
=2-8=-6/6=-1
or
10/6=5/3

y=

Thanks