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swissgirl

The number of State Parks in California is 36 more than one third the number of State Parks in Florida. There are 85 State Parks in California. Which of the following equations would you use to find the number of State Parks in Florida? Note: f represents the number of state parks in Florida. Quantity f plus 36 all over 3 equals 85 3(f - 36) = 85 1 over 3f + 36 = 85 Quantity f minus 36 all over 3 equals 85

  • one year ago
  • one year ago

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  1. swissgirl
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    Its a simple question but the wording is confusing me. Maybe u can help me out

    • one year ago
  2. JakeV8
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    "36 more than" <<<--- + 36 1/3 of Florida <<<--- (1/3)F 85 = (1/3)F + 36 Solve for F: 3 ( 85-36) = F

    • one year ago
  3. JakeV8
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    wait, huh?

    • one year ago
  4. JakeV8
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    I'd choose option (c)

    • one year ago
  5. swissgirl
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    Ya it was someone else's question and its bothering me

    • one year ago
  6. swissgirl
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    The wording is very wierd

    • one year ago
  7. JakeV8
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    It's like the first line I wrote... but no kidding, the wording is awful, probably on purpose...

    • one year ago
  8. swissgirl
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    but option c is \( \large \frac{1} {3f} +36=85 \)

    • one year ago
  9. JakeV8
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    oh, ugh!

    • one year ago
  10. swissgirl
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    Maybe I am wrong though. I just guessed that. It isnt my question so i wldnt know

    • one year ago
  11. JakeV8
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    Are you sure that's how it was given, or maybe it was posted erroneously like 1/3f meaning (1/3)f? I've been fighting fraction problems all day... people type without thinking of the possible interpretations, and since it makes all the difference in the world, you have to get clarification

    • one year ago
  12. JakeV8
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    So, did you happen to see that function earlier that was like h(x,y) = y + c for x<=3 and 5-x for x > 3 ?

    • one year ago
  13. JakeV8
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    Any idea how to read "h(x,y)" ? Is that a function that depends on both x and y, producing a function output h(x,y) ?

    • one year ago
  14. swissgirl
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    hahah yaaaaa I cldnt figure it out lol

    • one year ago
  15. JakeV8
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    or is it a function that might depend on x or y, depending on the x value?

    • one year ago
  16. swissgirl
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    ummm its a 3 dimensional function

    • one year ago
  17. swissgirl
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    meaning that z depends on x and y

    • one year ago
  18. JakeV8
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    The thought I kept having was "What the heck is this" (except shorter, and less printable.

    • one year ago
  19. JakeV8
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    You think? I mean, it could be, but the question was "is there a value c that makes the function continuous?"

    • one year ago
  20. swissgirl
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    hmmmm I came across alot of these kind of questions while i was in calc 2 but It wasnt this wording exactly

    • one year ago
  21. swissgirl
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    Like we never had to make it continous. I am not sure. I am gonna look at the question again

    • one year ago
  22. swissgirl
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    idk I have never solved that kind of question b4 but I should look into it

    • one year ago
  23. JakeV8
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    often for earlier classes, continuous functions are 2D questions where the point is to evaluate a function for different categories of x values.

    • one year ago
  24. swissgirl
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    ohhh I have my calc book with me let me see

    • one year ago
  25. JakeV8
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    I assumed it wasn't calc 2... just an early discussion of functions... guess I should have asked what the class was.

    • one year ago
  26. JakeV8
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    (but now we're curious, aren't we... ;) )

    • one year ago
  27. swissgirl
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    lol I forget everything i ever learned. idk after exams i forget everything

    • one year ago
  28. JakeV8
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    Does that work as a math major?

    • one year ago
  29. swissgirl
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    I am majoring in math but for my undergrad

    • one year ago
  30. JakeV8
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    My problem is forgetting DURING exams

    • one year ago
  31. swissgirl
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    lol

    • one year ago
  32. swissgirl
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    like if a function depends on 2 variables then it must be 3d in my opinion but idk

    • one year ago
  33. JakeV8
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    I get what you're saying... that could be right... I didn't get the sense we were talking calc-level stuff, so I assumed (maybe wrongly) that it was a weird way of writing a function that was continuous but not "normal" like a simple line.

    • one year ago
  34. JakeV8
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    If that was true, I was not familiar (nor in agreement!!) with the notation of h(x,y)

    • one year ago
  35. JakeV8
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    I mean as a 2D function....

    • one year ago
  36. swissgirl
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    but then again the question states in R2 so that means it is 2d

    • one year ago
  37. swissgirl
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    Cld be it is a parametric equation that is what it appears to be maybe lol

    • one year ago
  38. JakeV8
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    y = 2 is a line, x = 2 is a different line, but I don't like h(x,y) = some hybrid of those 2

    • one year ago
  39. swissgirl
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    lol

    • one year ago
  40. JakeV8
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    Did you find it? Sorry, I say "2d" out of laziness.. R2

    • one year ago
  41. JakeV8
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    Guess it didn't save me time typing, but maybe a little thinking :)

    • one year ago
  42. swissgirl
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    Determine if there is a value for c which makes the function continuous on R2.

    • one year ago
  43. swissgirl
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    Whoops its def not parametric

    • one year ago
  44. swissgirl
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    ok I can ask the question on MSE and let me see what i get as an answer

    • one year ago
  45. JakeV8
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    what is MSE ?

    • one year ago
  46. swissgirl
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    Math Stack exchange

    • one year ago
  47. JakeV8
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    Similar to this place, but more math?

    • one year ago
  48. swissgirl
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    Its more advanced math. I cant answer a single question on there lol

    • one year ago
  49. JakeV8
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    oh, sounds scary.... good luck :)

    • one year ago
  50. swissgirl
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    lol Not so crazy. I just ask all my questions there

    • one year ago
  51. swissgirl
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    Determine if there is a value for c which makes the function continuous on R2. h(x,y) = {c + y, if x less/equal 3 { 5-x, x>3 Something is wrong with the question though. Like with the brackets

    • one year ago
  52. swissgirl
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    I am crazzzyyyy I just spent my whole evening here on OS helping when I should have been studying.

    • one year ago
  53. JakeV8
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    Yes, you are crazy... but it is fun to help, even if it isn't the best use of limited time... (beats Angry Birds though)

    • one year ago
  54. swissgirl
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    hahahah definitely lol

    • one year ago
  55. JakeV8
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    I have become much less productive, traditionally measured, since I found this site. But I have become considerably happier, and hopefully helping people will have something of a multiplier effect in the bigger picture. That isn't much of a story to tell a prof the next day when you bomb an assignment "cuz I was helping!! HELPING, I say!!"

    • one year ago
  56. swissgirl
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    lol hahah I dont help that often

    • one year ago
  57. swissgirl
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    U get sick of this site at some point. I am nearly on here a year. Of late I have been coming on but like you get bored of helping. Sattellite has been her for forever and never gets sick of it so maybe you wont.

    • one year ago
  58. JakeV8
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    I think pacing yourself may be key... just because it's online and fun for a minute doesn't mean doing the same algebra 1 problem repeatedly for a year is also fun. I can already tell I'm getting more selective with questions I'm picking... I may not make it a year without re-thinking my priorities :)

    • one year ago
  59. swissgirl
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    hahaha. Well I used to use this site to ask my questions back in the day but now its too advanced so I go elsewhere. I used to have fun with the users back then. Now its a bunch of 13 yr olds back then the users were alot older i think. We all used to have groups

    • one year ago
  60. JakeV8
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    Sounds more fun than now... I don't mind helping a 13-year old home school or alt. school student who honestly cares, but it seems like about 50% are just throwing up their hw (or worse, exam questions) and expecting someone to hand them an answer

    • one year ago
  61. JakeV8
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    Force for good is NOT equal "spoon feeding 13-year old laziness"

    • one year ago
  62. swissgirl
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    lol I agree. I sometimes just give ppl answers and then afterwards I am like y did i just do that. Today I gave away like 7 answers to this one guy. He kept on asking i and i kept answering

    • one year ago
  63. JakeV8
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    So, just prior to signing off, thought it was time for a change of profile pic... kept getting grief about V8 juice, and the v8 doesn't mean that anyway (doesn't really mean anything). We'll see how this new pic works out... gives me an easy answer if I don't know how to solve a question... I'll just say "Ask again" or "It depends" in a dreamy bluish liquidy voice

    • one year ago
  64. swissgirl
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    hahahahah lol

    • one year ago
  65. swissgirl
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    Is this suppossed to be an eye or a die?

    • one year ago
  66. swissgirl
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    dice*

    • one year ago
  67. swissgirl
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    or maybe non of the above lol

    • one year ago
  68. JakeV8
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    Magic 8 ball?

    • one year ago
  69. JakeV8
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    (sigh) now I have to go find a better picture, again. ;)

    • one year ago
  70. JakeV8
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    Finding an icon pic for OS is a meta-time-waster

    • one year ago
  71. swissgirl
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    So leave it like this.

    • one year ago
  72. JakeV8
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    heh... just kidding anyway. I will leave it for now... last search was about 17.437 seconds of effort.

    • one year ago
  73. swissgirl
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    I rarely change mine I am way toooo lazy

    • one year ago
  74. JakeV8
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    Gotta run... catch you in the future... if you get some answer on that h(x,y) thing, let me know.

    • one year ago
  75. JakeV8
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    but yours is cool and mine looks like an eyeball :)

    • one year ago
  76. JakeV8
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    see ya...

    • one year ago
  77. swissgirl
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    cya gonna start working toooo

    • one year ago
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