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The number of State Parks in California is 36 more than one third the number of State Parks in Florida. There are 85 State Parks in California. Which of the following equations would you use to find the number of State Parks in Florida? Note: f represents the number of state parks in Florida. Quantity f plus 36 all over 3 equals 85 3(f - 36) = 85 1 over 3f + 36 = 85 Quantity f minus 36 all over 3 equals 85

Mathematics
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Its a simple question but the wording is confusing me. Maybe u can help me out
"36 more than" <<<--- + 36 1/3 of Florida <<<--- (1/3)F 85 = (1/3)F + 36 Solve for F: 3 ( 85-36) = F
wait, huh?

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Other answers:

I'd choose option (c)
Ya it was someone else's question and its bothering me
The wording is very wierd
It's like the first line I wrote... but no kidding, the wording is awful, probably on purpose...
but option c is \( \large \frac{1} {3f} +36=85 \)
oh, ugh!
Maybe I am wrong though. I just guessed that. It isnt my question so i wldnt know
Are you sure that's how it was given, or maybe it was posted erroneously like 1/3f meaning (1/3)f? I've been fighting fraction problems all day... people type without thinking of the possible interpretations, and since it makes all the difference in the world, you have to get clarification
So, did you happen to see that function earlier that was like h(x,y) = y + c for x<=3 and 5-x for x > 3 ?
Any idea how to read "h(x,y)" ? Is that a function that depends on both x and y, producing a function output h(x,y) ?
hahah yaaaaa I cldnt figure it out lol
or is it a function that might depend on x or y, depending on the x value?
ummm its a 3 dimensional function
meaning that z depends on x and y
The thought I kept having was "What the heck is this" (except shorter, and less printable.
You think? I mean, it could be, but the question was "is there a value c that makes the function continuous?"
hmmmm I came across alot of these kind of questions while i was in calc 2 but It wasnt this wording exactly
Like we never had to make it continous. I am not sure. I am gonna look at the question again
idk I have never solved that kind of question b4 but I should look into it
often for earlier classes, continuous functions are 2D questions where the point is to evaluate a function for different categories of x values.
ohhh I have my calc book with me let me see
I assumed it wasn't calc 2... just an early discussion of functions... guess I should have asked what the class was.
(but now we're curious, aren't we... ;) )
lol I forget everything i ever learned. idk after exams i forget everything
Does that work as a math major?
I am majoring in math but for my undergrad
My problem is forgetting DURING exams
lol
like if a function depends on 2 variables then it must be 3d in my opinion but idk
I get what you're saying... that could be right... I didn't get the sense we were talking calc-level stuff, so I assumed (maybe wrongly) that it was a weird way of writing a function that was continuous but not "normal" like a simple line.
If that was true, I was not familiar (nor in agreement!!) with the notation of h(x,y)
I mean as a 2D function....
but then again the question states in R2 so that means it is 2d
Cld be it is a parametric equation that is what it appears to be maybe lol
y = 2 is a line, x = 2 is a different line, but I don't like h(x,y) = some hybrid of those 2
lol
Did you find it? Sorry, I say "2d" out of laziness.. R2
Guess it didn't save me time typing, but maybe a little thinking :)
Determine if there is a value for c which makes the function continuous on R2.
Whoops its def not parametric
ok I can ask the question on MSE and let me see what i get as an answer
what is MSE ?
Math Stack exchange
Similar to this place, but more math?
Its more advanced math. I cant answer a single question on there lol
oh, sounds scary.... good luck :)
lol Not so crazy. I just ask all my questions there
Determine if there is a value for c which makes the function continuous on R2. h(x,y) = {c + y, if x less/equal 3 { 5-x, x>3 Something is wrong with the question though. Like with the brackets
I am crazzzyyyy I just spent my whole evening here on OS helping when I should have been studying.
Yes, you are crazy... but it is fun to help, even if it isn't the best use of limited time... (beats Angry Birds though)
hahahah definitely lol
I have become much less productive, traditionally measured, since I found this site. But I have become considerably happier, and hopefully helping people will have something of a multiplier effect in the bigger picture. That isn't much of a story to tell a prof the next day when you bomb an assignment "cuz I was helping!! HELPING, I say!!"
lol hahah I dont help that often
U get sick of this site at some point. I am nearly on here a year. Of late I have been coming on but like you get bored of helping. Sattellite has been her for forever and never gets sick of it so maybe you wont.
I think pacing yourself may be key... just because it's online and fun for a minute doesn't mean doing the same algebra 1 problem repeatedly for a year is also fun. I can already tell I'm getting more selective with questions I'm picking... I may not make it a year without re-thinking my priorities :)
hahaha. Well I used to use this site to ask my questions back in the day but now its too advanced so I go elsewhere. I used to have fun with the users back then. Now its a bunch of 13 yr olds back then the users were alot older i think. We all used to have groups
Sounds more fun than now... I don't mind helping a 13-year old home school or alt. school student who honestly cares, but it seems like about 50% are just throwing up their hw (or worse, exam questions) and expecting someone to hand them an answer
Force for good is NOT equal "spoon feeding 13-year old laziness"
lol I agree. I sometimes just give ppl answers and then afterwards I am like y did i just do that. Today I gave away like 7 answers to this one guy. He kept on asking i and i kept answering
So, just prior to signing off, thought it was time for a change of profile pic... kept getting grief about V8 juice, and the v8 doesn't mean that anyway (doesn't really mean anything). We'll see how this new pic works out... gives me an easy answer if I don't know how to solve a question... I'll just say "Ask again" or "It depends" in a dreamy bluish liquidy voice
hahahahah lol
Is this suppossed to be an eye or a die?
dice*
or maybe non of the above lol
Magic 8 ball?
(sigh) now I have to go find a better picture, again. ;)
Finding an icon pic for OS is a meta-time-waster
So leave it like this.
heh... just kidding anyway. I will leave it for now... last search was about 17.437 seconds of effort.
I rarely change mine I am way toooo lazy
Gotta run... catch you in the future... if you get some answer on that h(x,y) thing, let me know.
but yours is cool and mine looks like an eyeball :)
see ya...
cya gonna start working toooo

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