swissgirl
  • swissgirl
The number of State Parks in California is 36 more than one third the number of State Parks in Florida. There are 85 State Parks in California. Which of the following equations would you use to find the number of State Parks in Florida? Note: f represents the number of state parks in Florida. Quantity f plus 36 all over 3 equals 85 3(f - 36) = 85 1 over 3f + 36 = 85 Quantity f minus 36 all over 3 equals 85
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
swissgirl
  • swissgirl
Its a simple question but the wording is confusing me. Maybe u can help me out
anonymous
  • anonymous
"36 more than" <<<--- + 36 1/3 of Florida <<<--- (1/3)F 85 = (1/3)F + 36 Solve for F: 3 ( 85-36) = F
anonymous
  • anonymous
wait, huh?

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anonymous
  • anonymous
I'd choose option (c)
swissgirl
  • swissgirl
Ya it was someone else's question and its bothering me
swissgirl
  • swissgirl
The wording is very wierd
anonymous
  • anonymous
It's like the first line I wrote... but no kidding, the wording is awful, probably on purpose...
swissgirl
  • swissgirl
but option c is \( \large \frac{1} {3f} +36=85 \)
anonymous
  • anonymous
oh, ugh!
swissgirl
  • swissgirl
Maybe I am wrong though. I just guessed that. It isnt my question so i wldnt know
anonymous
  • anonymous
Are you sure that's how it was given, or maybe it was posted erroneously like 1/3f meaning (1/3)f? I've been fighting fraction problems all day... people type without thinking of the possible interpretations, and since it makes all the difference in the world, you have to get clarification
anonymous
  • anonymous
So, did you happen to see that function earlier that was like h(x,y) = y + c for x<=3 and 5-x for x > 3 ?
anonymous
  • anonymous
Any idea how to read "h(x,y)" ? Is that a function that depends on both x and y, producing a function output h(x,y) ?
swissgirl
  • swissgirl
hahah yaaaaa I cldnt figure it out lol
anonymous
  • anonymous
or is it a function that might depend on x or y, depending on the x value?
swissgirl
  • swissgirl
ummm its a 3 dimensional function
swissgirl
  • swissgirl
meaning that z depends on x and y
anonymous
  • anonymous
The thought I kept having was "What the heck is this" (except shorter, and less printable.
anonymous
  • anonymous
You think? I mean, it could be, but the question was "is there a value c that makes the function continuous?"
swissgirl
  • swissgirl
hmmmm I came across alot of these kind of questions while i was in calc 2 but It wasnt this wording exactly
swissgirl
  • swissgirl
Like we never had to make it continous. I am not sure. I am gonna look at the question again
swissgirl
  • swissgirl
idk I have never solved that kind of question b4 but I should look into it
anonymous
  • anonymous
often for earlier classes, continuous functions are 2D questions where the point is to evaluate a function for different categories of x values.
swissgirl
  • swissgirl
ohhh I have my calc book with me let me see
anonymous
  • anonymous
I assumed it wasn't calc 2... just an early discussion of functions... guess I should have asked what the class was.
anonymous
  • anonymous
(but now we're curious, aren't we... ;) )
swissgirl
  • swissgirl
lol I forget everything i ever learned. idk after exams i forget everything
anonymous
  • anonymous
Does that work as a math major?
swissgirl
  • swissgirl
I am majoring in math but for my undergrad
anonymous
  • anonymous
My problem is forgetting DURING exams
swissgirl
  • swissgirl
lol
swissgirl
  • swissgirl
like if a function depends on 2 variables then it must be 3d in my opinion but idk
anonymous
  • anonymous
I get what you're saying... that could be right... I didn't get the sense we were talking calc-level stuff, so I assumed (maybe wrongly) that it was a weird way of writing a function that was continuous but not "normal" like a simple line.
anonymous
  • anonymous
If that was true, I was not familiar (nor in agreement!!) with the notation of h(x,y)
anonymous
  • anonymous
I mean as a 2D function....
swissgirl
  • swissgirl
but then again the question states in R2 so that means it is 2d
swissgirl
  • swissgirl
Cld be it is a parametric equation that is what it appears to be maybe lol
anonymous
  • anonymous
y = 2 is a line, x = 2 is a different line, but I don't like h(x,y) = some hybrid of those 2
swissgirl
  • swissgirl
lol
anonymous
  • anonymous
Did you find it? Sorry, I say "2d" out of laziness.. R2
anonymous
  • anonymous
Guess it didn't save me time typing, but maybe a little thinking :)
swissgirl
  • swissgirl
Determine if there is a value for c which makes the function continuous on R2.
swissgirl
  • swissgirl
Whoops its def not parametric
swissgirl
  • swissgirl
ok I can ask the question on MSE and let me see what i get as an answer
anonymous
  • anonymous
what is MSE ?
swissgirl
  • swissgirl
Math Stack exchange
anonymous
  • anonymous
Similar to this place, but more math?
swissgirl
  • swissgirl
Its more advanced math. I cant answer a single question on there lol
anonymous
  • anonymous
oh, sounds scary.... good luck :)
swissgirl
  • swissgirl
lol Not so crazy. I just ask all my questions there
swissgirl
  • swissgirl
Determine if there is a value for c which makes the function continuous on R2. h(x,y) = {c + y, if x less/equal 3 { 5-x, x>3 Something is wrong with the question though. Like with the brackets
swissgirl
  • swissgirl
I am crazzzyyyy I just spent my whole evening here on OS helping when I should have been studying.
anonymous
  • anonymous
Yes, you are crazy... but it is fun to help, even if it isn't the best use of limited time... (beats Angry Birds though)
swissgirl
  • swissgirl
hahahah definitely lol
anonymous
  • anonymous
I have become much less productive, traditionally measured, since I found this site. But I have become considerably happier, and hopefully helping people will have something of a multiplier effect in the bigger picture. That isn't much of a story to tell a prof the next day when you bomb an assignment "cuz I was helping!! HELPING, I say!!"
swissgirl
  • swissgirl
lol hahah I dont help that often
swissgirl
  • swissgirl
U get sick of this site at some point. I am nearly on here a year. Of late I have been coming on but like you get bored of helping. Sattellite has been her for forever and never gets sick of it so maybe you wont.
anonymous
  • anonymous
I think pacing yourself may be key... just because it's online and fun for a minute doesn't mean doing the same algebra 1 problem repeatedly for a year is also fun. I can already tell I'm getting more selective with questions I'm picking... I may not make it a year without re-thinking my priorities :)
swissgirl
  • swissgirl
hahaha. Well I used to use this site to ask my questions back in the day but now its too advanced so I go elsewhere. I used to have fun with the users back then. Now its a bunch of 13 yr olds back then the users were alot older i think. We all used to have groups
anonymous
  • anonymous
Sounds more fun than now... I don't mind helping a 13-year old home school or alt. school student who honestly cares, but it seems like about 50% are just throwing up their hw (or worse, exam questions) and expecting someone to hand them an answer
anonymous
  • anonymous
Force for good is NOT equal "spoon feeding 13-year old laziness"
swissgirl
  • swissgirl
lol I agree. I sometimes just give ppl answers and then afterwards I am like y did i just do that. Today I gave away like 7 answers to this one guy. He kept on asking i and i kept answering
anonymous
  • anonymous
So, just prior to signing off, thought it was time for a change of profile pic... kept getting grief about V8 juice, and the v8 doesn't mean that anyway (doesn't really mean anything). We'll see how this new pic works out... gives me an easy answer if I don't know how to solve a question... I'll just say "Ask again" or "It depends" in a dreamy bluish liquidy voice
swissgirl
  • swissgirl
hahahahah lol
swissgirl
  • swissgirl
Is this suppossed to be an eye or a die?
swissgirl
  • swissgirl
dice*
swissgirl
  • swissgirl
or maybe non of the above lol
anonymous
  • anonymous
Magic 8 ball?
anonymous
  • anonymous
(sigh) now I have to go find a better picture, again. ;)
anonymous
  • anonymous
Finding an icon pic for OS is a meta-time-waster
swissgirl
  • swissgirl
So leave it like this.
anonymous
  • anonymous
heh... just kidding anyway. I will leave it for now... last search was about 17.437 seconds of effort.
swissgirl
  • swissgirl
I rarely change mine I am way toooo lazy
anonymous
  • anonymous
Gotta run... catch you in the future... if you get some answer on that h(x,y) thing, let me know.
anonymous
  • anonymous
but yours is cool and mine looks like an eyeball :)
anonymous
  • anonymous
see ya...
swissgirl
  • swissgirl
cya gonna start working toooo

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