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swissgirl

  • 2 years ago

The number of State Parks in California is 36 more than one third the number of State Parks in Florida. There are 85 State Parks in California. Which of the following equations would you use to find the number of State Parks in Florida? Note: f represents the number of state parks in Florida. Quantity f plus 36 all over 3 equals 85 3(f - 36) = 85 1 over 3f + 36 = 85 Quantity f minus 36 all over 3 equals 85

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  1. swissgirl
    • 2 years ago
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    Its a simple question but the wording is confusing me. Maybe u can help me out

  2. JakeV8
    • 2 years ago
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    "36 more than" <<<--- + 36 1/3 of Florida <<<--- (1/3)F 85 = (1/3)F + 36 Solve for F: 3 ( 85-36) = F

  3. JakeV8
    • 2 years ago
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    wait, huh?

  4. JakeV8
    • 2 years ago
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    I'd choose option (c)

  5. swissgirl
    • 2 years ago
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    Ya it was someone else's question and its bothering me

  6. swissgirl
    • 2 years ago
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    The wording is very wierd

  7. JakeV8
    • 2 years ago
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    It's like the first line I wrote... but no kidding, the wording is awful, probably on purpose...

  8. swissgirl
    • 2 years ago
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    but option c is \( \large \frac{1} {3f} +36=85 \)

  9. JakeV8
    • 2 years ago
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    oh, ugh!

  10. swissgirl
    • 2 years ago
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    Maybe I am wrong though. I just guessed that. It isnt my question so i wldnt know

  11. JakeV8
    • 2 years ago
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    Are you sure that's how it was given, or maybe it was posted erroneously like 1/3f meaning (1/3)f? I've been fighting fraction problems all day... people type without thinking of the possible interpretations, and since it makes all the difference in the world, you have to get clarification

  12. JakeV8
    • 2 years ago
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    So, did you happen to see that function earlier that was like h(x,y) = y + c for x<=3 and 5-x for x > 3 ?

  13. JakeV8
    • 2 years ago
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    Any idea how to read "h(x,y)" ? Is that a function that depends on both x and y, producing a function output h(x,y) ?

  14. swissgirl
    • 2 years ago
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    hahah yaaaaa I cldnt figure it out lol

  15. JakeV8
    • 2 years ago
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    or is it a function that might depend on x or y, depending on the x value?

  16. swissgirl
    • 2 years ago
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    ummm its a 3 dimensional function

  17. swissgirl
    • 2 years ago
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    meaning that z depends on x and y

  18. JakeV8
    • 2 years ago
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    The thought I kept having was "What the heck is this" (except shorter, and less printable.

  19. JakeV8
    • 2 years ago
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    You think? I mean, it could be, but the question was "is there a value c that makes the function continuous?"

  20. swissgirl
    • 2 years ago
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    hmmmm I came across alot of these kind of questions while i was in calc 2 but It wasnt this wording exactly

  21. swissgirl
    • 2 years ago
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    Like we never had to make it continous. I am not sure. I am gonna look at the question again

  22. swissgirl
    • 2 years ago
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    idk I have never solved that kind of question b4 but I should look into it

  23. JakeV8
    • 2 years ago
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    often for earlier classes, continuous functions are 2D questions where the point is to evaluate a function for different categories of x values.

  24. swissgirl
    • 2 years ago
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    ohhh I have my calc book with me let me see

  25. JakeV8
    • 2 years ago
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    I assumed it wasn't calc 2... just an early discussion of functions... guess I should have asked what the class was.

  26. JakeV8
    • 2 years ago
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    (but now we're curious, aren't we... ;) )

  27. swissgirl
    • 2 years ago
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    lol I forget everything i ever learned. idk after exams i forget everything

  28. JakeV8
    • 2 years ago
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    Does that work as a math major?

  29. swissgirl
    • 2 years ago
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    I am majoring in math but for my undergrad

  30. JakeV8
    • 2 years ago
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    My problem is forgetting DURING exams

  31. swissgirl
    • 2 years ago
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    lol

  32. swissgirl
    • 2 years ago
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    like if a function depends on 2 variables then it must be 3d in my opinion but idk

  33. JakeV8
    • 2 years ago
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    I get what you're saying... that could be right... I didn't get the sense we were talking calc-level stuff, so I assumed (maybe wrongly) that it was a weird way of writing a function that was continuous but not "normal" like a simple line.

  34. JakeV8
    • 2 years ago
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    If that was true, I was not familiar (nor in agreement!!) with the notation of h(x,y)

  35. JakeV8
    • 2 years ago
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    I mean as a 2D function....

  36. swissgirl
    • 2 years ago
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    but then again the question states in R2 so that means it is 2d

  37. swissgirl
    • 2 years ago
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    Cld be it is a parametric equation that is what it appears to be maybe lol

  38. JakeV8
    • 2 years ago
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    y = 2 is a line, x = 2 is a different line, but I don't like h(x,y) = some hybrid of those 2

  39. swissgirl
    • 2 years ago
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    lol

  40. JakeV8
    • 2 years ago
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    Did you find it? Sorry, I say "2d" out of laziness.. R2

  41. JakeV8
    • 2 years ago
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    Guess it didn't save me time typing, but maybe a little thinking :)

  42. swissgirl
    • 2 years ago
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    Determine if there is a value for c which makes the function continuous on R2.

  43. swissgirl
    • 2 years ago
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    Whoops its def not parametric

  44. swissgirl
    • 2 years ago
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    ok I can ask the question on MSE and let me see what i get as an answer

  45. JakeV8
    • 2 years ago
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    what is MSE ?

  46. swissgirl
    • 2 years ago
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    Math Stack exchange

  47. JakeV8
    • 2 years ago
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    Similar to this place, but more math?

  48. swissgirl
    • 2 years ago
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    Its more advanced math. I cant answer a single question on there lol

  49. JakeV8
    • 2 years ago
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    oh, sounds scary.... good luck :)

  50. swissgirl
    • 2 years ago
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    lol Not so crazy. I just ask all my questions there

  51. swissgirl
    • 2 years ago
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    Determine if there is a value for c which makes the function continuous on R2. h(x,y) = {c + y, if x less/equal 3 { 5-x, x>3 Something is wrong with the question though. Like with the brackets

  52. swissgirl
    • 2 years ago
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    I am crazzzyyyy I just spent my whole evening here on OS helping when I should have been studying.

  53. JakeV8
    • 2 years ago
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    Yes, you are crazy... but it is fun to help, even if it isn't the best use of limited time... (beats Angry Birds though)

  54. swissgirl
    • 2 years ago
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    hahahah definitely lol

  55. JakeV8
    • 2 years ago
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    I have become much less productive, traditionally measured, since I found this site. But I have become considerably happier, and hopefully helping people will have something of a multiplier effect in the bigger picture. That isn't much of a story to tell a prof the next day when you bomb an assignment "cuz I was helping!! HELPING, I say!!"

  56. swissgirl
    • 2 years ago
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    lol hahah I dont help that often

  57. swissgirl
    • 2 years ago
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    U get sick of this site at some point. I am nearly on here a year. Of late I have been coming on but like you get bored of helping. Sattellite has been her for forever and never gets sick of it so maybe you wont.

  58. JakeV8
    • 2 years ago
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    I think pacing yourself may be key... just because it's online and fun for a minute doesn't mean doing the same algebra 1 problem repeatedly for a year is also fun. I can already tell I'm getting more selective with questions I'm picking... I may not make it a year without re-thinking my priorities :)

  59. swissgirl
    • 2 years ago
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    hahaha. Well I used to use this site to ask my questions back in the day but now its too advanced so I go elsewhere. I used to have fun with the users back then. Now its a bunch of 13 yr olds back then the users were alot older i think. We all used to have groups

  60. JakeV8
    • 2 years ago
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    Sounds more fun than now... I don't mind helping a 13-year old home school or alt. school student who honestly cares, but it seems like about 50% are just throwing up their hw (or worse, exam questions) and expecting someone to hand them an answer

  61. JakeV8
    • 2 years ago
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    Force for good is NOT equal "spoon feeding 13-year old laziness"

  62. swissgirl
    • 2 years ago
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    lol I agree. I sometimes just give ppl answers and then afterwards I am like y did i just do that. Today I gave away like 7 answers to this one guy. He kept on asking i and i kept answering

  63. JakeV8
    • 2 years ago
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    So, just prior to signing off, thought it was time for a change of profile pic... kept getting grief about V8 juice, and the v8 doesn't mean that anyway (doesn't really mean anything). We'll see how this new pic works out... gives me an easy answer if I don't know how to solve a question... I'll just say "Ask again" or "It depends" in a dreamy bluish liquidy voice

  64. swissgirl
    • 2 years ago
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    hahahahah lol

  65. swissgirl
    • 2 years ago
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    Is this suppossed to be an eye or a die?

  66. swissgirl
    • 2 years ago
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    dice*

  67. swissgirl
    • 2 years ago
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    or maybe non of the above lol

  68. JakeV8
    • 2 years ago
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    Magic 8 ball?

  69. JakeV8
    • 2 years ago
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    (sigh) now I have to go find a better picture, again. ;)

  70. JakeV8
    • 2 years ago
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    Finding an icon pic for OS is a meta-time-waster

  71. swissgirl
    • 2 years ago
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    So leave it like this.

  72. JakeV8
    • 2 years ago
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    heh... just kidding anyway. I will leave it for now... last search was about 17.437 seconds of effort.

  73. swissgirl
    • 2 years ago
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    I rarely change mine I am way toooo lazy

  74. JakeV8
    • 2 years ago
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    Gotta run... catch you in the future... if you get some answer on that h(x,y) thing, let me know.

  75. JakeV8
    • 2 years ago
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    but yours is cool and mine looks like an eyeball :)

  76. JakeV8
    • 2 years ago
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    see ya...

  77. swissgirl
    • 2 years ago
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    cya gonna start working toooo

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