## anonymous 3 years ago The number of State Parks in California is 36 more than one third the number of State Parks in Florida. There are 85 State Parks in California. Which of the following equations would you use to find the number of State Parks in Florida? Note: f represents the number of state parks in Florida. Quantity f plus 36 all over 3 equals 85 3(f - 36) = 85 1 over 3f + 36 = 85 Quantity f minus 36 all over 3 equals 85

1. anonymous

Its a simple question but the wording is confusing me. Maybe u can help me out

2. anonymous

"36 more than" <<<--- + 36 1/3 of Florida <<<--- (1/3)F 85 = (1/3)F + 36 Solve for F: 3 ( 85-36) = F

3. anonymous

wait, huh?

4. anonymous

I'd choose option (c)

5. anonymous

Ya it was someone else's question and its bothering me

6. anonymous

The wording is very wierd

7. anonymous

It's like the first line I wrote... but no kidding, the wording is awful, probably on purpose...

8. anonymous

but option c is $$\large \frac{1} {3f} +36=85$$

9. anonymous

oh, ugh!

10. anonymous

Maybe I am wrong though. I just guessed that. It isnt my question so i wldnt know

11. anonymous

Are you sure that's how it was given, or maybe it was posted erroneously like 1/3f meaning (1/3)f? I've been fighting fraction problems all day... people type without thinking of the possible interpretations, and since it makes all the difference in the world, you have to get clarification

12. anonymous

So, did you happen to see that function earlier that was like h(x,y) = y + c for x<=3 and 5-x for x > 3 ?

13. anonymous

Any idea how to read "h(x,y)" ? Is that a function that depends on both x and y, producing a function output h(x,y) ?

14. anonymous

hahah yaaaaa I cldnt figure it out lol

15. anonymous

or is it a function that might depend on x or y, depending on the x value?

16. anonymous

ummm its a 3 dimensional function

17. anonymous

meaning that z depends on x and y

18. anonymous

The thought I kept having was "What the heck is this" (except shorter, and less printable.

19. anonymous

You think? I mean, it could be, but the question was "is there a value c that makes the function continuous?"

20. anonymous

hmmmm I came across alot of these kind of questions while i was in calc 2 but It wasnt this wording exactly

21. anonymous

Like we never had to make it continous. I am not sure. I am gonna look at the question again

22. anonymous

idk I have never solved that kind of question b4 but I should look into it

23. anonymous

often for earlier classes, continuous functions are 2D questions where the point is to evaluate a function for different categories of x values.

24. anonymous

ohhh I have my calc book with me let me see

25. anonymous

I assumed it wasn't calc 2... just an early discussion of functions... guess I should have asked what the class was.

26. anonymous

(but now we're curious, aren't we... ;) )

27. anonymous

lol I forget everything i ever learned. idk after exams i forget everything

28. anonymous

Does that work as a math major?

29. anonymous

I am majoring in math but for my undergrad

30. anonymous

My problem is forgetting DURING exams

31. anonymous

lol

32. anonymous

like if a function depends on 2 variables then it must be 3d in my opinion but idk

33. anonymous

I get what you're saying... that could be right... I didn't get the sense we were talking calc-level stuff, so I assumed (maybe wrongly) that it was a weird way of writing a function that was continuous but not "normal" like a simple line.

34. anonymous

If that was true, I was not familiar (nor in agreement!!) with the notation of h(x,y)

35. anonymous

I mean as a 2D function....

36. anonymous

but then again the question states in R2 so that means it is 2d

37. anonymous

Cld be it is a parametric equation that is what it appears to be maybe lol

38. anonymous

y = 2 is a line, x = 2 is a different line, but I don't like h(x,y) = some hybrid of those 2

39. anonymous

lol

40. anonymous

Did you find it? Sorry, I say "2d" out of laziness.. R2

41. anonymous

Guess it didn't save me time typing, but maybe a little thinking :)

42. anonymous

Determine if there is a value for c which makes the function continuous on R2.

43. anonymous

Whoops its def not parametric

44. anonymous

ok I can ask the question on MSE and let me see what i get as an answer

45. anonymous

what is MSE ?

46. anonymous

Math Stack exchange

47. anonymous

Similar to this place, but more math?

48. anonymous

Its more advanced math. I cant answer a single question on there lol

49. anonymous

oh, sounds scary.... good luck :)

50. anonymous

lol Not so crazy. I just ask all my questions there

51. anonymous

Determine if there is a value for c which makes the function continuous on R2. h(x,y) = {c + y, if x less/equal 3 { 5-x, x>3 Something is wrong with the question though. Like with the brackets

52. anonymous

I am crazzzyyyy I just spent my whole evening here on OS helping when I should have been studying.

53. anonymous

Yes, you are crazy... but it is fun to help, even if it isn't the best use of limited time... (beats Angry Birds though)

54. anonymous

hahahah definitely lol

55. anonymous

I have become much less productive, traditionally measured, since I found this site. But I have become considerably happier, and hopefully helping people will have something of a multiplier effect in the bigger picture. That isn't much of a story to tell a prof the next day when you bomb an assignment "cuz I was helping!! HELPING, I say!!"

56. anonymous

lol hahah I dont help that often

57. anonymous

U get sick of this site at some point. I am nearly on here a year. Of late I have been coming on but like you get bored of helping. Sattellite has been her for forever and never gets sick of it so maybe you wont.

58. anonymous

I think pacing yourself may be key... just because it's online and fun for a minute doesn't mean doing the same algebra 1 problem repeatedly for a year is also fun. I can already tell I'm getting more selective with questions I'm picking... I may not make it a year without re-thinking my priorities :)

59. anonymous

hahaha. Well I used to use this site to ask my questions back in the day but now its too advanced so I go elsewhere. I used to have fun with the users back then. Now its a bunch of 13 yr olds back then the users were alot older i think. We all used to have groups

60. anonymous

Sounds more fun than now... I don't mind helping a 13-year old home school or alt. school student who honestly cares, but it seems like about 50% are just throwing up their hw (or worse, exam questions) and expecting someone to hand them an answer

61. anonymous

Force for good is NOT equal "spoon feeding 13-year old laziness"

62. anonymous

lol I agree. I sometimes just give ppl answers and then afterwards I am like y did i just do that. Today I gave away like 7 answers to this one guy. He kept on asking i and i kept answering

63. anonymous

So, just prior to signing off, thought it was time for a change of profile pic... kept getting grief about V8 juice, and the v8 doesn't mean that anyway (doesn't really mean anything). We'll see how this new pic works out... gives me an easy answer if I don't know how to solve a question... I'll just say "Ask again" or "It depends" in a dreamy bluish liquidy voice

64. anonymous

hahahahah lol

65. anonymous

Is this suppossed to be an eye or a die?

66. anonymous

dice*

67. anonymous

or maybe non of the above lol

68. anonymous

Magic 8 ball?

69. anonymous

(sigh) now I have to go find a better picture, again. ;)

70. anonymous

Finding an icon pic for OS is a meta-time-waster

71. anonymous

So leave it like this.

72. anonymous

heh... just kidding anyway. I will leave it for now... last search was about 17.437 seconds of effort.

73. anonymous

I rarely change mine I am way toooo lazy

74. anonymous

Gotta run... catch you in the future... if you get some answer on that h(x,y) thing, let me know.

75. anonymous

but yours is cool and mine looks like an eyeball :)

76. anonymous

see ya...

77. anonymous

cya gonna start working toooo