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rebecca1233 Group Title

What is the value of f[g(3)] for the functions f(x) = x + 2 and g(x) = 5x - 1? (Type only the value of your final answer, no variables.) Numerical Answers Expected!

  • 2 years ago
  • 2 years ago

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  1. febylailani Group Title
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    f(g(3)) first, find g(3) . after that, put the result tumber on the formula. like this >> f(result g(3)) do u understand?

    • 2 years ago
  2. rebecca1233 Group Title
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    not really.. can u help me work through this

    • 2 years ago
  3. febylailani Group Title
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    ok.. first.. find g(3) with this formula g(x) = 5x - 1

    • 2 years ago
  4. rebecca1233 Group Title
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    soo what do i do now..

    • 2 years ago
  5. febylailani Group Title
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    find the result of g(3) just subtitute the x on this formula >> g(x) = 5x - 1 with 3. what is the result u got?

    • 2 years ago
  6. rebecca1233 Group Title
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    so substitute with x with 3

    • 2 years ago
  7. febylailani Group Title
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    yup.

    • 2 years ago
  8. rebecca1233 Group Title
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    g(3) = 5(3) - 1

    • 2 years ago
  9. febylailani Group Title
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    yup..

    • 2 years ago
  10. rebecca1233 Group Title
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    so 14 is the answer ?

    • 2 years ago
  11. febylailani Group Title
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    it's the answer for g(3). now.. subtitute x with 14 to this formula f(x) = x + 2

    • 2 years ago
  12. rebecca1233 Group Title
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    14+2 = 16

    • 2 years ago
  13. rebecca1233 Group Title
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    so what now

    • 2 years ago
  14. febylailani Group Title
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    it's the final result

    • 2 years ago
  15. rebecca1233 Group Title
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    so 16 is the answer not 14

    • 2 years ago
  16. rebecca1233 Group Title
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    can u please help me with a different question

    • 2 years ago
  17. rebecca1233 Group Title
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    http://openstudy.com/study#/updates/5060f00fe4b0583d5cd2892c

    • 2 years ago
  18. febylailani Group Title
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    f[g(3)] is f(g(3)) = g(3) + 2 1) to solve that first we must find g(3). g(3) = 5(3) - 1 g(3) = 15 - 1 = 14 2) after that, we can find f(g(3)). f(g(3)) = g(3) + 2 f(14) = 14 +2 f(14) = 16 do u understand?

    • 2 years ago
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