A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 2 years ago
Find the type and number of solutions for the equation.
x^2  4x = 4
A)one distinct real solution
B)two distinct real solutions
C) two distinct nonreal complex solutions
 2 years ago
Find the type and number of solutions for the equation. x^2  4x = 4 A)one distinct real solution B)two distinct real solutions C) two distinct nonreal complex solutions

This Question is Closed

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.2Write it in that nice quadratic form first of all! c: \[x^2 4x + 4 = 0\] then lets see.. hmmmm

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.2looks like it is a nice perfect square, doesn't it? c: do ya see it?? :D

georgejafacules
 2 years ago
Best ResponseYou've already chosen the best response.0but what does that mean?

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.2the equation simplifies really nicely to\[(x2)^2 = 0\] so hmm solving for x.. we can square both sides of this equation.

georgejafacules
 2 years ago
Best ResponseYou've already chosen the best response.0so would it be A?

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.2ya that sounds right c: x=2 is the only solution

febylailani
 2 years ago
Best ResponseYou've already chosen the best response.0(x2)(x2)=0 x=2 :)
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.