anonymous
  • anonymous
Limits help (kind of forgot...) Click here to see function
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
\[ \huge \lim_{x \rightarrow 2} \frac{(x-3)(x+2)}{(x-2)}.\]
anonymous
  • anonymous
How can I simplify the denominator so that it doesnt give me a 0..?
anonymous
  • anonymous
numerator is not zero, so go fish

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

hartnn
  • hartnn
directly put x=2
anonymous
  • anonymous
i.e. no limit
anonymous
  • anonymous
? Wouldn't it be a a denominator of 0, which is a "no-no"?
anonymous
  • anonymous
if you get a zero in the denominator, but not a zero in the numerator, then there is no limit only when you get \(\frac{0}{0}\) can you continue if you get a zero in the denominator
anonymous
  • anonymous
no
anonymous
  • anonymous
No, We haven't learned about that yet
anonymous
  • anonymous
l'hopital works for \(\frac{0}{0}\) in any case you didn't get there yet i am sure
anonymous
  • anonymous
So, @satellite73 would the limit be DNE ?
anonymous
  • anonymous
Because my teacher always says to only substitute directly when the denominator is not equal to zero...
anonymous
  • anonymous
not applicable here if you have a rational funciton, and you want to take the limit as x goes to some number, the first step is to plug in the number if you get a number back, that is your answer if you get \(\frac{a}{0}\) where \(a\neq 0\) there is no limit if you get \(\frac{0}{0}\) there is more work to be done factor and cancel but in this case you get \(\frac{-4}{0}\) so forget it
anonymous
  • anonymous
That makes a lot of sense @satellite73! Thanks so much!!

Looking for something else?

Not the answer you are looking for? Search for more explanations.