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anonymous
 3 years ago
Limits help (kind of forgot...) Click here to see function
anonymous
 3 years ago
Limits help (kind of forgot...) Click here to see function

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[ \huge \lim_{x \rightarrow 2} \frac{(x3)(x+2)}{(x2)}.\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0How can I simplify the denominator so that it doesnt give me a 0..?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0numerator is not zero, so go fish

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0? Wouldn't it be a a denominator of 0, which is a "nono"?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if you get a zero in the denominator, but not a zero in the numerator, then there is no limit only when you get \(\frac{0}{0}\) can you continue if you get a zero in the denominator

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0No, We haven't learned about that yet

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0l'hopital works for \(\frac{0}{0}\) in any case you didn't get there yet i am sure

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So, @satellite73 would the limit be DNE ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Because my teacher always says to only substitute directly when the denominator is not equal to zero...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0not applicable here if you have a rational funciton, and you want to take the limit as x goes to some number, the first step is to plug in the number if you get a number back, that is your answer if you get \(\frac{a}{0}\) where \(a\neq 0\) there is no limit if you get \(\frac{0}{0}\) there is more work to be done factor and cancel but in this case you get \(\frac{4}{0}\) so forget it

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0That makes a lot of sense @satellite73! Thanks so much!!
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