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Study23Best ResponseYou've already chosen the best response.0
\[ \huge \lim_{x \rightarrow 2} \frac{(x3)(x+2)}{(x2)}.\]
 one year ago

Study23Best ResponseYou've already chosen the best response.0
How can I simplify the denominator so that it doesnt give me a 0..?
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
numerator is not zero, so go fish
 one year ago

Study23Best ResponseYou've already chosen the best response.0
? Wouldn't it be a a denominator of 0, which is a "nono"?
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
if you get a zero in the denominator, but not a zero in the numerator, then there is no limit only when you get \(\frac{0}{0}\) can you continue if you get a zero in the denominator
 one year ago

Study23Best ResponseYou've already chosen the best response.0
No, We haven't learned about that yet
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
l'hopital works for \(\frac{0}{0}\) in any case you didn't get there yet i am sure
 one year ago

Study23Best ResponseYou've already chosen the best response.0
So, @satellite73 would the limit be DNE ?
 one year ago

Study23Best ResponseYou've already chosen the best response.0
Because my teacher always says to only substitute directly when the denominator is not equal to zero...
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
not applicable here if you have a rational funciton, and you want to take the limit as x goes to some number, the first step is to plug in the number if you get a number back, that is your answer if you get \(\frac{a}{0}\) where \(a\neq 0\) there is no limit if you get \(\frac{0}{0}\) there is more work to be done factor and cancel but in this case you get \(\frac{4}{0}\) so forget it
 one year ago

Study23Best ResponseYou've already chosen the best response.0
That makes a lot of sense @satellite73! Thanks so much!!
 one year ago
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