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Study23 Group Title

Limits help (kind of forgot...) Click here to see function

  • one year ago
  • one year ago

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  1. Study23 Group Title
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    \[ \huge \lim_{x \rightarrow 2} \frac{(x-3)(x+2)}{(x-2)}.\]

    • one year ago
  2. Study23 Group Title
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    How can I simplify the denominator so that it doesnt give me a 0..?

    • one year ago
  3. satellite73 Group Title
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    numerator is not zero, so go fish

    • one year ago
  4. hartnn Group Title
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    directly put x=2

    • one year ago
  5. satellite73 Group Title
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    i.e. no limit

    • one year ago
  6. Study23 Group Title
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    ? Wouldn't it be a a denominator of 0, which is a "no-no"?

    • one year ago
  7. satellite73 Group Title
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    if you get a zero in the denominator, but not a zero in the numerator, then there is no limit only when you get \(\frac{0}{0}\) can you continue if you get a zero in the denominator

    • one year ago
  8. satellite73 Group Title
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    no

    • one year ago
  9. Study23 Group Title
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    No, We haven't learned about that yet

    • one year ago
  10. satellite73 Group Title
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    l'hopital works for \(\frac{0}{0}\) in any case you didn't get there yet i am sure

    • one year ago
  11. Study23 Group Title
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    So, @satellite73 would the limit be DNE ?

    • one year ago
  12. Study23 Group Title
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    Because my teacher always says to only substitute directly when the denominator is not equal to zero...

    • one year ago
  13. satellite73 Group Title
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    not applicable here if you have a rational funciton, and you want to take the limit as x goes to some number, the first step is to plug in the number if you get a number back, that is your answer if you get \(\frac{a}{0}\) where \(a\neq 0\) there is no limit if you get \(\frac{0}{0}\) there is more work to be done factor and cancel but in this case you get \(\frac{-4}{0}\) so forget it

    • one year ago
  14. Study23 Group Title
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    That makes a lot of sense @satellite73! Thanks so much!!

    • one year ago
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