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stupidinmath
 2 years ago
Best ResponseYou've already chosen the best response.0(x3)(x3) x^23x3x+9 x^26x+9=36 x^26x27 right? then next?

Yahoo!
 2 years ago
Best ResponseYou've already chosen the best response.0Sum = 6 Product = 27 So the No are 9 and 3

Yahoo!
 2 years ago
Best ResponseYou've already chosen the best response.0so x^26x27 = x^2 + 3x  9x  27 =0 Nw Factorize

heedcom
 2 years ago
Best ResponseYou've already chosen the best response.0by further factorising it comes to (x+3)(x9)=0

phi
 2 years ago
Best ResponseYou've already chosen the best response.2to find the factors of x^26x27 first notice that the 27 is negative. that means you are looking for 2 numbers with different signs (either + and  or  and +) List the factors of 27 1,27 3,9 do any of the pairs give 6 , when the numbers have different signs? 1 and 27 could be 1 + 27 or +127 but neithert give 6 but +39 = 6 so we want +3 and 9 (x+3)(x9) multiply out to check: x^2 6x27. it works

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0you might try this \[(x3)^2=36\] \[(x3)^236=0\] then since \(a^2b^2=(a+b)(ab)\) you get \[(x3+6)(x36)\] and then add the numbers

phi
 2 years ago
Best ResponseYou've already chosen the best response.2and not to confuse you, you could have started with (x3)^2=36 take the square root of both sides x3= ±6 and x= +6+3= 9 and x= 6+3= 3 this means the factors are (x9)(x+3)

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0if you are looking for the zeros, then there is no reason to factor, you find them in two steps, as @phi wrote above
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