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stupidinmathBest ResponseYou've already chosen the best response.0
(x3)(x3) x^23x3x+9 x^26x+9=36 x^26x27 right? then next?
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.0
Sum = 6 Product = 27 So the No are 9 and 3
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.0
so x^26x27 = x^2 + 3x  9x  27 =0 Nw Factorize
 one year ago

heedcomBest ResponseYou've already chosen the best response.0
by further factorising it comes to (x+3)(x9)=0
 one year ago

phiBest ResponseYou've already chosen the best response.2
to find the factors of x^26x27 first notice that the 27 is negative. that means you are looking for 2 numbers with different signs (either + and  or  and +) List the factors of 27 1,27 3,9 do any of the pairs give 6 , when the numbers have different signs? 1 and 27 could be 1 + 27 or +127 but neithert give 6 but +39 = 6 so we want +3 and 9 (x+3)(x9) multiply out to check: x^2 6x27. it works
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
you might try this \[(x3)^2=36\] \[(x3)^236=0\] then since \(a^2b^2=(a+b)(ab)\) you get \[(x3+6)(x36)\] and then add the numbers
 one year ago

phiBest ResponseYou've already chosen the best response.2
and not to confuse you, you could have started with (x3)^2=36 take the square root of both sides x3= ±6 and x= +6+3= 9 and x= 6+3= 3 this means the factors are (x9)(x+3)
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
if you are looking for the zeros, then there is no reason to factor, you find them in two steps, as @phi wrote above
 one year ago
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