anonymous
  • anonymous
Y= -16x^2+190+0 A= B= C= graph when done.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
I think you have to do the quadratic formula
anonymous
  • anonymous
umm i forgot what that is.... the b= something right?
anonymous
  • anonymous
in quadratic equation term with x^2 is A term with x is B term with constant is C

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anonymous
  • anonymous
yes -b + or - sqrt(b^2-4ac) all over at 2a
anonymous
  • anonymous
okay thx
anonymous
  • anonymous
in this case you can solve for your variables a b c
anonymous
  • anonymous
\[b = -b \pm \frac{ \sqrt{b^2 - 4ac} }{ 2 }\]
anonymous
  • anonymous
jazy its 2a
anonymous
  • anonymous
@jazy
anonymous
  • anonymous
I thought I put that. But yes, over 2a. (:
anonymous
  • anonymous
\[b = -b \pm \frac{\sqrt{b^2 - 4ac}} { 2a }\]
anonymous
  • anonymous
uughh this is sooo harrddd
anonymous
  • anonymous
ax^2 + b^2 + c -16x^2 + 190 +0 what is a, b, and c?
anonymous
  • anonymous
-16 190 0
anonymous
  • anonymous
oh. i got -380
anonymous
  • anonymous
how do you get -380
anonymous
  • anonymous
you have the steps down, i think you know what you are doing
hartnn
  • hartnn
also 'x' term is missing..
anonymous
  • anonymous
oh snap i didnt do the bottom hold on
anonymous
  • anonymous
so... id plug in the answer i got from the eqation as x?
anonymous
  • anonymous
i got 0.95
anonymous
  • anonymous
it right @jazy
anonymous
  • anonymous
I think you had it right up to the -380. You have to divide by 2(-16) or -32. What is -380 /-32?
anonymous
  • anonymous
you have it
anonymous
  • anonymous
yea thats when i got 11.87
anonymous
  • anonymous
then i pluged it in to the equation
anonymous
  • anonymous
right(: what was the 0.95 for though?
anonymous
  • anonymous
y= -16(11.87^2)............. the 11.87 is substituted for the x

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