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ilikephysics2Best ResponseYou've already chosen the best response.2
I think you have to do the quadratic formula
 one year ago

kiamonstaaBest ResponseYou've already chosen the best response.0
umm i forgot what that is.... the b= something right?
 one year ago

uzumakhiBest ResponseYou've already chosen the best response.0
in quadratic equation term with x^2 is A term with x is B term with constant is C
 one year ago

ilikephysics2Best ResponseYou've already chosen the best response.2
yes b + or  sqrt(b^24ac) all over at 2a
 one year ago

ilikephysics2Best ResponseYou've already chosen the best response.2
in this case you can solve for your variables a b c
 one year ago

jazyBest ResponseYou've already chosen the best response.0
\[b = b \pm \frac{ \sqrt{b^2  4ac} }{ 2 }\]
 one year ago

jazyBest ResponseYou've already chosen the best response.0
I thought I put that. But yes, over 2a. (:
 one year ago

jazyBest ResponseYou've already chosen the best response.0
\[b = b \pm \frac{\sqrt{b^2  4ac}} { 2a }\]
 one year ago

kiamonstaaBest ResponseYou've already chosen the best response.0
uughh this is sooo harrddd
 one year ago

jazyBest ResponseYou've already chosen the best response.0
ax^2 + b^2 + c 16x^2 + 190 +0 what is a, b, and c?
 one year ago

ilikephysics2Best ResponseYou've already chosen the best response.2
you have the steps down, i think you know what you are doing
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
also 'x' term is missing..
 one year ago

kiamonstaaBest ResponseYou've already chosen the best response.0
oh snap i didnt do the bottom hold on
 one year ago

kiamonstaaBest ResponseYou've already chosen the best response.0
so... id plug in the answer i got from the eqation as x?
 one year ago

jazyBest ResponseYou've already chosen the best response.0
I think you had it right up to the 380. You have to divide by 2(16) or 32. What is 380 /32?
 one year ago

kiamonstaaBest ResponseYou've already chosen the best response.0
yea thats when i got 11.87
 one year ago

kiamonstaaBest ResponseYou've already chosen the best response.0
then i pluged it in to the equation
 one year ago

jazyBest ResponseYou've already chosen the best response.0
right(: what was the 0.95 for though?
 one year ago

kiamonstaaBest ResponseYou've already chosen the best response.0
y= 16(11.87^2)............. the 11.87 is substituted for the x
 one year ago
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