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kiamonstaa Group Title

Y= -16x^2+190+0 A= B= C= graph when done.

  • one year ago
  • one year ago

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  1. ilikephysics2 Group Title
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    I think you have to do the quadratic formula

    • one year ago
  2. kiamonstaa Group Title
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    umm i forgot what that is.... the b= something right?

    • one year ago
  3. uzumakhi Group Title
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    in quadratic equation term with x^2 is A term with x is B term with constant is C

    • one year ago
  4. ilikephysics2 Group Title
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    yes -b + or - sqrt(b^2-4ac) all over at 2a

    • one year ago
  5. kiamonstaa Group Title
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    okay thx

    • one year ago
  6. ilikephysics2 Group Title
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    in this case you can solve for your variables a b c

    • one year ago
  7. jazy Group Title
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    \[b = -b \pm \frac{ \sqrt{b^2 - 4ac} }{ 2 }\]

    • one year ago
  8. ilikephysics2 Group Title
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    jazy its 2a

    • one year ago
  9. ilikephysics2 Group Title
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    @jazy

    • one year ago
  10. jazy Group Title
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    I thought I put that. But yes, over 2a. (:

    • one year ago
  11. jazy Group Title
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    \[b = -b \pm \frac{\sqrt{b^2 - 4ac}} { 2a }\]

    • one year ago
  12. kiamonstaa Group Title
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    uughh this is sooo harrddd

    • one year ago
  13. jazy Group Title
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    ax^2 + b^2 + c -16x^2 + 190 +0 what is a, b, and c?

    • one year ago
  14. kiamonstaa Group Title
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    -16 190 0

    • one year ago
  15. kiamonstaa Group Title
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    oh. i got -380

    • one year ago
  16. uzumakhi Group Title
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    how do you get -380

    • one year ago
  17. ilikephysics2 Group Title
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    you have the steps down, i think you know what you are doing

    • one year ago
  18. hartnn Group Title
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    also 'x' term is missing..

    • one year ago
  19. kiamonstaa Group Title
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    oh snap i didnt do the bottom hold on

    • one year ago
  20. kiamonstaa Group Title
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    so... id plug in the answer i got from the eqation as x?

    • one year ago
  21. kiamonstaa Group Title
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    i got 0.95

    • one year ago
  22. sudharsa Group Title
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    it right @jazy

    • one year ago
  23. jazy Group Title
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    I think you had it right up to the -380. You have to divide by 2(-16) or -32. What is -380 /-32?

    • one year ago
  24. ilikephysics2 Group Title
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    you have it

    • one year ago
  25. kiamonstaa Group Title
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    yea thats when i got 11.87

    • one year ago
  26. kiamonstaa Group Title
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    then i pluged it in to the equation

    • one year ago
  27. jazy Group Title
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    right(: what was the 0.95 for though?

    • one year ago
  28. kiamonstaa Group Title
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    y= -16(11.87^2)............. the 11.87 is substituted for the x

    • one year ago
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