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kiamonstaa
 3 years ago
Y= 16x^2+190+0
A=
B=
C=
graph when done.
kiamonstaa
 3 years ago
Y= 16x^2+190+0 A= B= C= graph when done.

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ilikephysics2
 3 years ago
Best ResponseYou've already chosen the best response.2I think you have to do the quadratic formula

kiamonstaa
 3 years ago
Best ResponseYou've already chosen the best response.0umm i forgot what that is.... the b= something right?

uzumakhi
 3 years ago
Best ResponseYou've already chosen the best response.0in quadratic equation term with x^2 is A term with x is B term with constant is C

ilikephysics2
 3 years ago
Best ResponseYou've already chosen the best response.2yes b + or  sqrt(b^24ac) all over at 2a

ilikephysics2
 3 years ago
Best ResponseYou've already chosen the best response.2in this case you can solve for your variables a b c

jazy
 3 years ago
Best ResponseYou've already chosen the best response.0\[b = b \pm \frac{ \sqrt{b^2  4ac} }{ 2 }\]

jazy
 3 years ago
Best ResponseYou've already chosen the best response.0I thought I put that. But yes, over 2a. (:

jazy
 3 years ago
Best ResponseYou've already chosen the best response.0\[b = b \pm \frac{\sqrt{b^2  4ac}} { 2a }\]

kiamonstaa
 3 years ago
Best ResponseYou've already chosen the best response.0uughh this is sooo harrddd

jazy
 3 years ago
Best ResponseYou've already chosen the best response.0ax^2 + b^2 + c 16x^2 + 190 +0 what is a, b, and c?

ilikephysics2
 3 years ago
Best ResponseYou've already chosen the best response.2you have the steps down, i think you know what you are doing

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.0also 'x' term is missing..

kiamonstaa
 3 years ago
Best ResponseYou've already chosen the best response.0oh snap i didnt do the bottom hold on

kiamonstaa
 3 years ago
Best ResponseYou've already chosen the best response.0so... id plug in the answer i got from the eqation as x?

jazy
 3 years ago
Best ResponseYou've already chosen the best response.0I think you had it right up to the 380. You have to divide by 2(16) or 32. What is 380 /32?

kiamonstaa
 3 years ago
Best ResponseYou've already chosen the best response.0yea thats when i got 11.87

kiamonstaa
 3 years ago
Best ResponseYou've already chosen the best response.0then i pluged it in to the equation

jazy
 3 years ago
Best ResponseYou've already chosen the best response.0right(: what was the 0.95 for though?

kiamonstaa
 3 years ago
Best ResponseYou've already chosen the best response.0y= 16(11.87^2)............. the 11.87 is substituted for the x
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