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kiamonstaa

  • 3 years ago

Y= -16x^2+190+0 A= B= C= graph when done.

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  1. ilikephysics2
    • 3 years ago
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    I think you have to do the quadratic formula

  2. kiamonstaa
    • 3 years ago
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    umm i forgot what that is.... the b= something right?

  3. uzumakhi
    • 3 years ago
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    in quadratic equation term with x^2 is A term with x is B term with constant is C

  4. ilikephysics2
    • 3 years ago
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    yes -b + or - sqrt(b^2-4ac) all over at 2a

  5. kiamonstaa
    • 3 years ago
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    okay thx

  6. ilikephysics2
    • 3 years ago
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    in this case you can solve for your variables a b c

  7. jazy
    • 3 years ago
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    \[b = -b \pm \frac{ \sqrt{b^2 - 4ac} }{ 2 }\]

  8. ilikephysics2
    • 3 years ago
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    jazy its 2a

  9. ilikephysics2
    • 3 years ago
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    @jazy

  10. jazy
    • 3 years ago
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    I thought I put that. But yes, over 2a. (:

  11. jazy
    • 3 years ago
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    \[b = -b \pm \frac{\sqrt{b^2 - 4ac}} { 2a }\]

  12. kiamonstaa
    • 3 years ago
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    uughh this is sooo harrddd

  13. jazy
    • 3 years ago
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    ax^2 + b^2 + c -16x^2 + 190 +0 what is a, b, and c?

  14. kiamonstaa
    • 3 years ago
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    -16 190 0

  15. kiamonstaa
    • 3 years ago
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    oh. i got -380

  16. uzumakhi
    • 3 years ago
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    how do you get -380

  17. ilikephysics2
    • 3 years ago
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    you have the steps down, i think you know what you are doing

  18. hartnn
    • 3 years ago
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    also 'x' term is missing..

  19. kiamonstaa
    • 3 years ago
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    oh snap i didnt do the bottom hold on

  20. kiamonstaa
    • 3 years ago
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    so... id plug in the answer i got from the eqation as x?

  21. kiamonstaa
    • 3 years ago
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    i got 0.95

  22. sudharsa
    • 3 years ago
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    it right @jazy

  23. jazy
    • 3 years ago
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    I think you had it right up to the -380. You have to divide by 2(-16) or -32. What is -380 /-32?

  24. ilikephysics2
    • 3 years ago
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    you have it

  25. kiamonstaa
    • 3 years ago
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    yea thats when i got 11.87

  26. kiamonstaa
    • 3 years ago
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    then i pluged it in to the equation

  27. jazy
    • 3 years ago
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    right(: what was the 0.95 for though?

  28. kiamonstaa
    • 3 years ago
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    y= -16(11.87^2)............. the 11.87 is substituted for the x

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