Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

there are 6 stores in town that had a total of 20 visitors on a particular day. However only 10 people went shopping that day; some people visited more than one store. If 6 people visited exactly two stores each and everyone visited at least one store, what is largest no of stores anyone could have visited. a)6 b)8 c)5 d)9 e)2

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

ans to tis is 5 cud any one tell me how
  • phi
there were 10 people who made 20 visits 6 of the 10 people visited exactly 2 stores. That means they made 2*6=12 visits that leaves 4 people who made 8 visits ( 10-6 people and 20-12 visits) everyone visited at least 1 store. that uses up 4 visits we have 4 visits unaccounted for. If the same person made these visits (along with the 1 we just counted), that would be 5 visits maximum.
thanks

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Not the answer you are looking for?

Search for more explanations.

Ask your own question