First problem 100 thinking robots are given a challenge : they will communicate only by means of a single light bulb which can be either in the state 1 (light on) or in state 0 (light off). Each second a randomly chosen \[\bf ONE \quad single \] robot can see the bulb (others don't- in that second) and keep it in the previous state or change it to opposite state. Bulb is On at first. Each second one chosen randomly out of 100. The challenge is to know -WHEN every one of them has been at the bulb at least once (or more) times. This info has to reach all of 100 eventually. SEE THE SOLUTION BELOW

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

First problem 100 thinking robots are given a challenge : they will communicate only by means of a single light bulb which can be either in the state 1 (light on) or in state 0 (light off). Each second a randomly chosen \[\bf ONE \quad single \] robot can see the bulb (others don't- in that second) and keep it in the previous state or change it to opposite state. Bulb is On at first. Each second one chosen randomly out of 100. The challenge is to know -WHEN every one of them has been at the bulb at least once (or more) times. This info has to reach all of 100 eventually. SEE THE SOLUTION BELOW

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

Sounds like a statistics problem. To me there will always be a chance the same robot doesn't see the bulb, but it will be so small it's considered 0. We have to decide how small is too small. I really can't help any further then relaying my thoughts. sry
you could set up a limit as x approaches 0 for the last robot. But i don't know how to do that for this problem
Consider it given that there does occur a visit of each to the bulb. THIS IS NOT THE QUESTION !! The question is to communicate that event AFTER IT HAPPENNED JUST USING THE BULB !

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

oh ok. I did read it wrong. Is this a question you need an answer to, or a question for fun to the community? I would have to think about this for a while. still not much help
For intellectual profit of the community (not fun, god forbid that !)
Hi there @experimentX
so you know the answer. Now I'm more interested in this puzzle
Yo @Mikael what's up!! ... serves as bookmark.
There is a follow up problem - which HAS practical serious applications and is very deep
what if the first robot turns the bulb off and every robot you sees the bulb and it is their first time will turn it on. If it is their second time will turn it off. If the bulb is left off for a long time then we can assume every bot has seen it. I don't know how to determine the length of time
Glad to see you \[ Yoda-Not , \bf @ganeshie8 \]
:) so the state has to be communicated to all the 100 robots, but the bulb has only two states hmm
The offered method has weakness - a robot doesn't know whether it was a multiple visit by some group that made the light off (if that is his observation) or the complete set of visits.
lol .. .thanks!!
Ok let's make it simpler:
How each robot can be sure with probability of \[p= 1 -10^{-6}\] that all others HAVE visited the bulb - devise a method for that.
@Algebraic! you are missed here , one needs some critical approach...
Each robot has also a seconds-counting watch
Well let's say @ChmE is "warm" in his attempt...
I'm still thinking I see the problem you mentioned
Just devise an approach with lower possibility of that
So ..
can a robot leave a bolt. so the first time they visit they leave a bolt and there is a robot that collects all the bolts when he has 100 including his own they are done
and my first method will be complete in 100^101/100! years. lol
Great beginning of BRAIN -STORMING , NOW that you have "I wish" method - try making "the bolt" only with the ligh on/Off and the conditions given
I mean - the bulb , in some sense is a third-rate "bolt"
the first turns it off. and he counts how many times he see it on. The other robots turn it on one of their 2 cycles.
OK - push forward on the path of SIMPLIFYING !!!
"the first turns it off"....
and ignore (for a sec) the actual numbers of seconds
I will continue to think about it. Gotta catch a bus
So gentlemen and ladies - who's up to the challenge ?!
I'm going to stay quiet for a while since I've seen the problem before (in slightly different terms).
\[\bf \text{here is Second Problem - will be posted after this one is done and cleared.}\] \[\bf \color{red}{\text {Now the robots have to somehow}\,\,\\ {\Huge\color{green}{Choose \quad a \quad president}}\\{\text{EXACTLY IN THE SAME SITUATION }} }\]
No tricks - real new democratic choice of president.
the 1st robot turns it off and he only ever turns it off. Every other robot turns the light only once. If they have already turned it on they leave it off or if it is on they leave it on. The 1st robot counts how many times he turns it off til 99
if the robots see the light on but havent touched it then they leave it on til they are given the chance to turn it on
All right - so here is The second problem. \[ \bf \text{Choosing a specific number by majority of votes.} \\ \text{ Each robot has has own number known to all.}\\ \text{ Using all of the above they have to choose one pf them.}\\ \text{He will be called the president.} \]
Check my soln to problem 1. I think I've got it
@ChmE This seems the solution "the 1st robot turns it off and he only ever turns it off. Every other robot turns the light only once. If they have already turned it on they leave it off or if it is on they leave it on. The 1st robot counts how many times he turns it off til 99"
OMG!!! I swear I didn't cheat. Been thinking about this question on and off all day yesterday
But you were a bit unclear - you have to STATE that he turns it off during 99 opportunities he is given
ok
By the way - he does know - but how do the others know that he DOES know ?
what do you mean by that
the robot knows but how to the other robots know he knows?
First robot counted 99 light-on and reached the conclusion that all have been at the bulb. NOW - how will he communicate that fact to all the others ?
haha. This isn't fun anymore. I gotta think about this
This is NOT fun, but i will spare you this time : Only probabilistically they will know. How? by seeing the light in their SEVERAL personal visits off they conclude that the probability that the FIRST - the turning-off guy was right before them is too low.
ok. thx. Is this a question that was proposed to you in one of your classes?
Thanks - now let us call here the other people who has been here - so they appreciate our work. @bahrom7893 @sauravshakya @kingGeorge, @ganeshie8 @hartnn @experimentex
Welcome to our humble abode Mrs @sauravshakya @hartnn and all !
Much appreciated !
ACTUALLY THIS SIMILAR PROBLEM WAS ALREADY SOLVED BY ME TOO.
http://mathriddles.williams.edu/?p=146
THAT IS THE SIMILAR QUESTION....... only number are different..AND ITS LOGICAL NO SERIES
AS far as I remember.
ya, i have also seen such problems...
Dear visitor @sauravshakya - I bet you ten sayings of praise (of your choosing) that the following you have NOT solved before http://openstudy.com/study#/updates/50631053e4b0583d5cd34249
Because I have met this situation in real life engineering problem.
Thanks Highlander ....!
Hello. :)
Best of luck. and keep them cool and well nutritioned !
Haha. Yeahh. Thanks. Nice problem though.
I was just thinking @Mikael . How is my solution/our solution correct because it relies on the robots communicating prior to seeing the lightbulb? Which by the given conditions cannot happen.
It is assumed the do communicate and agree beforehand.

Not the answer you are looking for?

Search for more explanations.

Ask your own question